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AP Statistics 3.10.C Calculating Two-Proportion Intervals

Practise constructing two-proportion confidence intervals by forming the sample-proportion difference, using an unpooled standard error, and choosing the correct z-value.

Syllabus
Effective Fall 2026
Course
AP Statistics

Exam points

  • Use the difference in sample proportions as the point estimate for p1 minus p2.
  • Add the two unpooled variance terms under the square root for the interval standard error.
  • Match the critical z-value to the requested confidence level, such as 1.960 or 2.576.

3.10.C—Calculate an appropriate confidence interval for the difference between two population proportions question 1

[Maximum number: 1]

Two brands of golf cart batteries, R and S, were tested to investigate whether there is a difference between the proportions of fully charged batteries that could power a golf cart for at least thirty miles. A random sample of 50 brand R batteries was selected and a random sample of 50 brand S batteries was selected. Batteries were randomly assigned to one of 100 different golf carts. Each cart was driven until the battery failed. Of the carts with brand R batteries, 40 traveled over thirty miles, and of the carts with brand S batteries, 35 traveled over thirty miles. Which of the following is a 95 percent confidence interval for the difference in the proportions of fully charged batteries that can power a golf cart for at least thirty miles for the two brands?

Statistics 2021Intl MCQ

A

(0.80.7)±1.645(0.8)(0.2)50+(0.7)(0.3)50(0.8-0.7) \pm 1.645 \sqrt{\frac{(0.8)(0.2)}{50}+\frac{(0.7)(0.3)}{50}}

B

(0.80.7)±1.645(0.75)(0.25)(150+150)(0.8-0.7) \pm 1.645 \sqrt{(0.75)(0.25)\left(\frac{1}{50}+\frac{1}{50}\right)}

C

(0.80.7)±1.645(0.8)(0.2)50(0.7)(0.3)50(0.8-0.7) \pm 1.645 \sqrt{\frac{(0.8)(0.2)}{50}-\frac{(0.7)(0.3)}{50}}

D

(0.80.7)±1.960(0.8)(0.2)50+(0.7)(0.3)50(0.8-0.7) \pm 1.960 \sqrt{\frac{(0.8)(0.2)}{50}+\frac{(0.7)(0.3)}{50}}

E

(0.80.7)±1.960(0.75)(0.25)(150+150)(0.8-0.7) \pm 1.960 \sqrt{(0.75)(0.25)\left(\frac{1}{50}+\frac{1}{50}\right)}

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