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AP Statistics 3.1.A Justifying Unbiased Estimators

Practise deciding whether an estimator is unbiased by comparing its expected value with the parameter, weighting strata correctly, and separating bias from variance.

Syllabus
Effective Fall 2026
Course
AP Statistics

Exam points

  • Justify unbiasedness by showing that the estimator's expected value equals the population parameter.
  • Weight stratum sample means by population proportions when strata have different sizes.
  • Separate bias from variance: increasing sample size can reduce variance without changing bias.

3.1.A—Justify why an estimator is or is not unbiased question 1

An environmental research agency conducted a study of a certain state's roadsides to estimate the mean number

of discarded cans and bottles per mile of public road. The state's public roads were grouped into three types:

Major highways: major paved roads designed for high traffic volume

Minor highways: smaller paved roads designed for low traffic volume

Unpaved roads: gravel and dirt roads

There are about 100,000 miles of public roads in the state. The environmental research agency defined a

sampling unit to be a one-mile segment of public road. Using a database supplied by the state's department of

transportation, the agency randomly selected 30 one-mile road segments for each of the three types of roads.

Researchers from the agency searched the roadsides along each of the selected one-mile road segments and

recorded the number of discarded cans and bottles. Results are shown in the table below.

Table for Question 3.1.A—Justify why an estimator is or is not unbiased question 1 — AP Statistics

Two methods for estimating the mean number of discarded cans and bottles per mile along all public roads

in the state are given below.

Method 1

0.24xˉmajor +0.58xˉminor +0.18xˉunpaved =(0.24)(11.2)+(0.58)(32.6)+(0.18)(21.7)=25.5\begin{aligned} & 0.24 \bar{x}_{\text {major }}+0.58 \bar{x}_{\text {minor }}+0.18 \bar{x}_{\text {unpaved }}= \\ & (0.24)(11.2)+(0.58)(32.6)+(0.18)(21.7)=25.5 \end{aligned}

Method 2

xˉmajor +xˉminor +xˉunpaved 3=11.2+32.6+21.73=21.83\frac{\bar{x}_{\text {major }}+\bar{x}_{\text {minor }}+\bar{x}_{\text {unpaved }}}{3}=\frac{11.2+32.6+21.7}{3}=21.83

Which of these methods gives a better estimate of this mean? Explain.

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