AP Physics C: Mechanics 7.2 Frequency and Period of Shm Questions

Determine period and frequency from oscillator parameters, scaling relationships, timed motion, and linearized measurements for several SHM systems.

Syllabus
Effective Fall 2024
Course
AP Physics C: Mechanics

Exam points

  • use T = 2pi sqrt(m/k) and f = 1/T to analyze a mass-spring oscillator
  • find an effective spring constant and predict how parallel springs change period or frequency
  • use T = 2pi sqrt(L/g) to compare small-angle pendulum periods and frequencies
  • relate the period of a torsional or rotational oscillator to its inertia and restoring constant
  • convert a fraction of an oscillation path into the corresponding fraction of a period

Question 1

[Maximum number: 2]

Block A and Block B of masses m and 3 m, respectively, are arranged in a setup consisting of an ideal spring with spring constant k and a horizontal surface. Friction between the surface and the blocks is negligible except in a region of length D, where the coefficient of kinetic friction between Block A and the surface is μ\mu. Block B is attached to a string of length \ell and negligible mass, as shown in Figure 1. Block A is held against the spring, compressing the spring a distance xcx_{\mathrm{c}}.

At time t=0, Block A is located at position x=x0x=x_{0} and is released from rest. After the block is released, the following occurs.

- At time t=t1t=t_{1}, Block A is at x=x1x=x_{1} after traveling a distance xcx_{\mathrm{c}}. Block A moves with speed v, and the spring is at its equilibrium position.

- At time t=t2t=t_{2}, the left side of Block A is at x=x2x=x_{2} after passing through a distance D across the region with nonnegligible friction.

- At time t=t3t=t_{3}, Block A is at x=x3x=x_{3} and Block A collides with and sticks to Block B.

Indicate how the new frequency of oscillation f2f_{2 \ell} of the system on the new string of length 22 \ell will compare to the frequency of oscillation ff_{\ell} from the original procedure. f2>ff_{2 \ell}>f_{\ell}f2<ff_{2 \ell}<f_{\ell}f2=ff_{2 \ell}=f_{\ell}

Briefly justify your answer.

Figure 1

Figure 1

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