In this question you must show all stages of your working. Solutions relying on calculator technology are not acceptable.
Figure 1
Figure 1 shows the curve with equation
y=ln(tanh2x)1⩽x⩽2
Show that the length, s, of the curve is given by
s=∫12cothxdx
dxdy=tanh(x/2)1⋅21sech2(x/2)
=2sinh(x/2)cosh(x/2)1=cosechx
1+(dxdy)2=1+cosech2x
=coth2x=cothx(1≤x≤2)
s=∫12cothxdx
M1: obtains an appropriate expression for dy/dx. M1: applies the arc length formula. ddM1: uses identities to obtain 1+(dy/dx)^2 in terms of x. A1*: reaches the printed integral with no errors.