P4.3 - Coordinate geometry in the (x, y) plane
- Syllabus
- 2019
- Topic
- P4.3
- Level
- A2
Parametric equations give both coordinates in terms of a third variable: x=f(t) and y=g(t). Each permitted value of t produces a point (x,y); changing t traces the curve. A Cartesian equation removes t and links x directly to y.
To convert to Cartesian form, make t or a simple function of t the subject of one equation and substitute into the other. For trigonometric parameters, isolate sint and cost and use sin2t+cos2t=1. Finally translate the stated range of t into restrictions on x or y.
For x=(t+3)/(t+1) and y=2/(t+1) with t>0, notice that x=1+2/(t+1)=1+y. Hence y=x−1. Since t+1>1, 0<y<2 and therefore 1<x<3. The unrestricted line would contain points that the parameter never reaches.
For x=3+2cost and y=−1+4sint, cost=2x−3,sint=4y+1. Therefore 4(x−3)2+16(y+1)2=1. The allowed interval for t decides whether this represents the whole ellipse or only part of it.
| Cartesian form | One useful parametrisation |
|---|---|
| y=F(x) | x=t, y=F(t) |
| a2(x−h)2+b2(y−k)2=1 | x=h+acost, y=k+bsint |
Eliminating the parameter can enlarge the locus, so a Cartesian equation without the inherited range may be incomplete. Different parameter values can produce the same point, and different parametrisations can describe the same curve. For an intersection, substitute both parametric expressions into the other curve, solve for permitted values of t, then recover both coordinates.