Edexcel A-Level Chemistry AS 6 Energetics Questions
Practise energetics by interpreting enthalpy definitions, diagrams, calorimetry data, Hess cycles and bond enthalpy tables.
- Syllabus
- First assessment 2019
- Course
- Chemistry YCH11
- Level
- AS
Practise energetics by interpreting enthalpy definitions, diagrams, calorimetry data, Hess cycles and bond enthalpy tables.
Fuels
Fuels burn in oxygen to release a lot of energy.
Many hydrocarbons and alcohols are used as fuels. During complete combustion, they produce carbon dioxide and water.
Petrol contains 2,2,4-trimethylpentane, an isomer of octane, that promotes smooth combustion.
2,2,4-trimethylpentane
Alcohols, such as methanol and ethanol, can be used as fuels either on their own or as additives in petrol.
The standard enthalpy change of combustion, ΔcH⊖, of 2,2,4-trimethylpentane is −5461 kJ mol−1.
State the two standard conditions for this enthalpy change.
(temperature) 298 K / 25^ C
and
(pressure) 1 atm / 100 kPa / 101 kPa / 1 x 10^5 Pa / 1.01 x 10^5 Pa
Allow 'a specified / stated temperature'
Ignore just 'room temperature'
Draw a labelled enthalpy level diagram for the complete combustion of 2,2,4-trimethylpentane.
Calculate the heat energy released during the complete combustion of 1dm3 of 2,2,4-trimethylpentane.
[Density of 2,2,4-trimethylpentane =0.692 g cm−3 ]
calculation of energy given out by 1 g
- calculation of energy given out by 1 cm3
- calculation of energy given out by 1dm3
Example of calculation:
Method 1 enthalpy change /g=1145461=47.904( kJ)
enthalpy change /cm3=47.904×0.692=33.149( kJ)
TE on M1
enthalpy change /dm3=33.149×1000=33149/33.149×103( kJ)
TE on M2
Method 2
mass of 2,2,4-trimethylpentane in 1dm3=0.692×1000=692( g)(1)
mol in 1dm3=114692=6.0702( mol)(1)
TE on M1
enthalpy change /dm3=6.0702×5461=33149/33.149×103( kJ)(1)
TE on M2
Allow alternative methods
Correct answer with some working scores (3)
Ignore SF except 1 SF
Ignore minus sign
Ignore units, even if incorrect
In an experiment to determine the enthalpy change of combustion of ethanol, C2H5OH, a student used the apparatus shown.
Results:
Mass of water =100.0 g
Mass of ethanol used =0.305 g
Temperature rise of water =13.2∘C
Calculate the enthalpy change of combustion of ethanol.
Give your answer to an appropriate number of significant figures, and include a sign and units.
[Specific heat capacity of water =4.18 J g−1C−1 ]
Example of calculation:
- calculation of heat evolved
heat evolved =100.0 x 4.18 x 13.2=5517.6( J) / 5.5176 kJ
- calculation of moles of ethanol used
amount of ethanol =0.305/46=0.0066304 / 6.6304 x 10^-3( mol)
- working for heat evolved per mole
heat evolved per mole =5.51766.6304 x 10^-3
(= 832.17)
- value of _c H to 2 / 3 SF
and
_c H=-830 /-832 kJ mol^-1
Allow units kJ / mol or kJ or kJ mol^- mol
units
Ignore letter case in units e.g. k or K, J or j Accept -830000 /-832000 J mol^-1
TE on M3
The student looked in a data book and found the actual value for the standard enthalpy change of combustion of ethanol was more exothermic than the experimental value obtained.
Give two reasons for the difference between the data book value and the experimental value, other than referring to standard conditions.
An answer that makes reference to any two of the following points:
- heat loss (to the surroundings)
- incomplete combustion (of ethanol)
- some ethanol evaporates
- calculation does not take into account the heat capacity of the beaker
Allow insufficient oxygen for combustion Ignore not all of the ethanol was burned
Ignore product(s) / water evaporates
Allow some heat is used to heat up the beaker Ignore thermometer Ignore ethanol was impure Ignore water was not stirred Ignore no lid on beaker
The enthalpy changes for the conversion of four compounds in the gas phase into their constituent atoms are shown.
Calculate the bond enthalpy of the C-C bond, in kJmol−1.
You must show your working.
calculation of bond energies of O-H and C-H
- calculation of bond energy of C-O
- calculation of bond energy of C-C
Example of calculation:
Method 1 bond energy O−H=928/2=(+)464( kJ mol−1)
and
bond energy C-H =1740/4=(+)435( kJ mol−1)
bond energy C−O=2105−(3×435)−464=(+)336( kJ mol−1)
TE on M1
bond energy C−C=3322−(5×435)−464−336=(+)347( kJ mol−1)
Method 2
3322−2105=1217=C−C+2×C−H(1)
bond energy 2×C−H=1740/2=(+)870( kJ mol−1)(1)C−C=1217−870=(+)347( kJ mol−1)(1)
M3 TE on M1 and M2 in both methods
Correct answer with some working scores
The standard enthalpy change of neutralisation for the reaction between sodium hydroxide solution and hydrochloric acid is −56 kJ mol−1.
Which row in the table is correct for this neutralisation?
Reaction type
Temperature
exothermic
increases
exothermic
decreases
endothermic
increases
endothermic
decreases
A
This question is about sodium hydroxide.
State what is meant by standard enthalpy change of neutralisation, Δneut H⊖.
An answer that makes reference to the following points:
- heat energy released under standard conditions (1)
- (when) 1 mol of water is produced (by the reaction of (1) acid with alkali)
Allow enthalpy change under standard conditions
Allow for standard conditions 1 atm/1(.01)×105 Pa
and a stated temperature / 298 K/25∘C
Ignore standard states
Do not award required
A student carried out an investigation to determine the enthalpy change of neutralisation of aqueous sodium hydroxide by hydrochloric acid.
Method
- separate 25.0 cm3 samples of 0.80 moldm−3 sodium hydroxide and 0.80 moldm−3 hydrochloric acid were left to reach room temperature
- after two minutes, the solutions were mixed in a copper calorimeter and the temperature was noted at 30 s intervals.
Use the graph shown to determine the maximum temperature change, ΔT, in this experiment. You must show your working on the graph.
An answer that makes reference to the following points:
- two lines of best fit drawn
(1)
- value ±0.2
(1)
)
Cooling may be shown as straight line or smooth
curve
Calculate the enthalpy change of neutralisation using your answers to (a) and (b)(i). Give a sign and units with your answer.
Assume: no energy is used to heat the container.
the specific heat capacity of the solution =4.2 J∘C−1 g−1. the densities of the solutions of NaOH and HCl are 1.0 g cm−3.
An answer that makes reference to the following points:
- energy transferred to solutions (1)
- moles of water formed (1)
- enthalpy change of neutralisation with negative (1) sign and units
Example of calculation:
0.05×4.2×4.4=0.924( kJ)50×4.2×4.4=924( J)(25÷1000)×0.8=0.02( mol)0.924÷0.02=−46.2 kJ mol−1/−46,200 J mol−1
T E on b(i) and throughout b(ii)
Ignore SF except 1 SF
Comment: Range based on range on graph - 44.10 kJ mol−1
to −48.30 kJ mol−1.
Explain how, if at all, the enthalpy change of neutralisation obtained in (b)(ii) would differ if the heat capacity of the calorimeter was included in the calculation.
An explanation that makes reference to the following points:
- (because the calculation has not taken into account the) energy required to heat the calorimeter/ the (total) heat capacity would be greater
- the value(of the enthalpy change of neutralisation) would be
(1) more exothermic/more negative
Ignore references to the relative heat capacity of copper/water(solution)
Allow higher/ increase/ greater
(2)
Fuels
Fuels burn in oxygen to release a lot of energy.
Many hydrocarbons and alcohols are used as fuels. During complete combustion, they produce carbon dioxide and water.
Petrol contains 2,2,4-trimethylpentane, an isomer of octane, that promotes smooth combustion.
2,2,4-trimethylpentane
Alcohols, such as methanol and ethanol, can be used as fuels either on their own or as additives in petrol.
The standard enthalpy change of combustion, ΔcH⊖, of 2,2,4-trimethylpentane is −5461 kJ mol−1.
State the two standard conditions for this enthalpy change.
(temperature) 298 K / 25^ C
and
(pressure) 1 atm / 100 kPa / 101 kPa / 1 x 10^5 Pa / 1.01 x 10^5 Pa
Allow 'a specified / stated temperature'
Ignore just 'room temperature'
Fuels
Fuels burn in oxygen to release a lot of energy.
Many hydrocarbons and alcohols are used as fuels. During complete combustion, they produce carbon dioxide and water.
Petrol contains 2,2,4-trimethylpentane, an isomer of octane, that promotes smooth combustion.
2,2,4-trimethylpentane
Alcohols, such as methanol and ethanol, can be used as fuels either on their own or as additives in petrol.
The standard enthalpy change of combustion, ΔcH⊖, of 2,2,4-trimethylpentane is −5461 kJ mol−1.
Draw a labelled enthalpy level diagram for the complete combustion of 2,2,4-trimethylpentane.
This question is about sodium hydroxide.
State what is meant by standard enthalpy change of neutralisation, Δneut H⊖.
An answer that makes reference to the following points:
- heat energy released under standard conditions (1)
- (when) 1 mol of water is produced (by the reaction of (1) acid with alkali)
Allow enthalpy change under standard conditions
Allow for standard conditions 1 atm/1(.01)×105 Pa
and a stated temperature / 298 K/25∘C
Ignore standard states
Do not award required
Ammonium nitrate, NH4NO3, is used in the manufacture of fertilisers and explosives. It is produced on a large scale using only methane, water and air.
The process has four stages.
In Stage 4, a solution of NH4NO3 is produced by reacting NH3 (from Stage 2) with HNO3 (from Stage 3).
Data
Complete the enthalpy cycle.
Enthalpy cycle
An answer that makes reference to the following points:
- left hand side of enthalpy cycle
- right hand side of enthalpy cycle
Example of completed enthalpy cycle:
Do not award omission/incorrect state symbols
Do not award multiples
Do not award numbers in opposite order
Do not award -25.6
Do not award +365.6 / 365.6
Calculate the enthalpy change, ΔrH, in kJmol−1, for the reaction of NH3( g) with HNO3(aq).
An answer that makes reference to the following point:
- calculation of ΔrH
Example of calculation:
ΔrH=−(−32.6)−(−220.2)+(−365.6)+25.6=−87.2/−87( kJ mol−1)
Allow omission of units
Allow kJ
TE on cycle in (g)(i)
Fuels
Fuels burn in oxygen to release a lot of energy.
Many hydrocarbons and alcohols are used as fuels. During complete combustion, they produce carbon dioxide and water.
Petrol contains 2,2,4-trimethylpentane, an isomer of octane, that promotes smooth combustion.
2,2,4-trimethylpentane
Alcohols, such as methanol and ethanol, can be used as fuels either on their own or as additives in petrol.
In an experiment to determine the enthalpy change of combustion of ethanol, C2H5OH, a student used the apparatus shown.
Results:
Mass of water =100.0 g
Mass of ethanol used =0.305 g
Temperature rise of water =13.2∘C
The student looked in a data book and found the actual value for the standard enthalpy change of combustion of ethanol was more exothermic than the experimental value obtained.
Give two reasons for the difference between the data book value and the experimental value, other than referring to standard conditions.
An answer that makes reference to any two of the following points:
- heat loss (to the surroundings)
- incomplete combustion (of ethanol)
- some ethanol evaporates
- calculation does not take into account the heat capacity of the beaker
Allow insufficient oxygen for combustion Ignore not all of the ethanol was burned
Ignore product(s) / water evaporates
Allow some heat is used to heat up the beaker Ignore thermometer Ignore ethanol was impure Ignore water was not stirred Ignore no lid on beaker
Consider the bond enthalpy values given in the table.
The equation for the reaction between nitrogen and hydrogen is shown.
N₂(g) + 3H₂(g) → 2NH₃(g)
What is the enthalpy change, in kJ mol⁻¹, for this reaction?
+1080
+852
−93
−529
C
Fuels
Fuels burn in oxygen to release a lot of energy.
Many hydrocarbons and alcohols are used as fuels. During complete combustion, they produce carbon dioxide and water.
Petrol contains 2,2,4-trimethylpentane, an isomer of octane, that promotes smooth combustion.
2,2,4-trimethylpentane
Alcohols, such as methanol and ethanol, can be used as fuels either on their own or as additives in petrol.
The enthalpy changes for the conversion of four compounds in the gas phase into their constituent atoms are shown.
Calculate the bond enthalpy of the C-C bond, in kJmol−1.
You must show your working.
calculation of bond energies of O-H and C-H
- calculation of bond energy of C-O
- calculation of bond energy of C-C
Example of calculation:
Method 1 bond energy O−H=928/2=(+)464( kJ mol−1)
and
bond energy C-H =1740/4=(+)435( kJ mol−1)
bond energy C−O=2105−(3×435)−464=(+)336( kJ mol−1)
TE on M1
bond energy C−C=3322−(5×435)−464−336=(+)347( kJ mol−1)
Method 2
3322−2105=1217=C−C+2×C−H(1)
bond energy 2×C−H=1740/2=(+)870( kJ mol−1)(1)C−C=1217−870=(+)347( kJ mol−1)(1)
M3 TE on M1 and M2 in both methods
Correct answer with some working scores