A.4 Geometry and trigonometry

Syllabus
2021
Topic
Level
AS

Calculate boundary, surface area and volume of biological shapes

Identify the idealised shape and whether the question asks for a boundary length, surface area or enclosed volume. Convert every dimension to one unit before applying powers, and report linear, squared or cubed units to match the quantity.

Shape Boundary/surface area Volume
Circle Circumference C=2πrC=2\pi r; area A=πr2A=\pi r^2
Rectangular prism SA=2(lw+lh+wh)SA=2(lw+lh+wh) V=lwhV=lwh
Cylindrical prism Total SA=2πr2+2πrhSA=2\pi r^2+2\pi rh; curved area =2πrh=2\pi rh V=πr2hV=\pi r^2h
Sphere SA=4πr2SA=4\pi r^2 V=43πr3V=\frac{4}{3}\pi r^3

A chloroplast image has diameter 96 mm at ×16,000\times16{,}000. Convert 9696 mm to 96,00096{,}000 µm, then actual diameter =96,000/16,000=6.0=96{,}000/16{,}000=6.0 µm and radius =3.0=3.0 µm. Approximating it as a sphere, SA=4π(3.0)2=113SA=4\pi(3.0)^2=113 µm2^2 to a whole number.

Surface-area-to-volume ratio requires separate calculations followed by division. For similar shapes, area scales with length squared and volume with length cubed, so enlarging a cell lowers its SA:V even when its shape is unchanged.

Radius is half the diameter. Do not use curved cylinder area when total surface area is required, mix units before squaring/cubing, or report surface area in volume units.