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A-Level CAIE Mathematics AS2.5 IntegrationQuestion Bank

[Maximum number: 3]

Use the trapezium rule with four intervals to find an approximation to

152x8dx\int_{1}^{5}\left|2^{x}-8\right| \mathrm{d} x

A curve is such that dy dx=472x\frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{4}{7-2 x}. The point (3,2) lies on the curve. Find the equation of the curve.

(a)

Find 24x1 dx\int \frac{2}{4 x-1} \mathrm{~d} x.

(b)

Hence find 1724x1 dx\int_{1}^{7} \frac{2}{4 x-1} \mathrm{~d} x, expressing your answer in the form lna\ln a, where a is an integer.

[ 3 ]
[Maximum number: 4]
Question image

The diagram shows a sketch of the curve y=3(9x3)y=\frac{3}{\sqrt{ }\left(9-x^{3}\right)} for values of x from -1.2 to 1.2 .

(a)

Use the trapezium rule, with two intervals, to estimate the value of

1.21.23(9x3)dx\int_{-1.2}^{1.2} \frac{3}{\sqrt{ }\left(9-x^{3}\right)} \mathrm{d} x

giving your answer correct to 2 decimal places.

[ 3 ]
(b)

Explain, with reference to the diagram, why the trapezium rule may be expected to give a good approximation to the true value of the integral in this case.

[ 1 ]
[Maximum number: 3]

Use the trapezium rule with three intervals to estimate the value of

012πln(1+sinx)dx\int_{0}^{\frac{1}{2} \pi} \ln (1+\sin x) \mathrm{d} x

giving your answer correct to 2 decimal places.

[Maximum number: 3]

Use the trapezium rule with three intervals to estimate the value of

014π(1tanx)dx\int_{0}^{\frac{1}{4} \pi} \sqrt{ }(1-\tan x) \mathrm{d} x

giving your answer correct to 3 decimal places.

[Maximum number: 3]

Use the trapezium rule with 3 intervals to estimate the value of

032x4dx.\int_{0}^{3}\left|2^{x}-4\right| \mathrm{d} x .
(a)

Use the trapezium rule with 3 intervals to estimate the value of

16π23πcosecx dx\int_{\frac{1}{6} \pi}^{\frac{2}{3} \pi} \operatorname{cosec} x \mathrm{~d} x

giving your answer correct to 2 decimal places.

[ 3 ]
(b)

Using a sketch of the graph of y=cosecxy=\operatorname{cosec} x, explain whether the trapezium rule gives an overestimate or an underestimate of the true value of the integral in part (i).

[ 2 ]
[Maximum number: 3]

Show that 2624x+1 dx=ln53\int_{2}^{6} \frac{2}{4 x+1} \mathrm{~d} x=\ln \frac{5}{3}.

Use the trapezium rule with three intervals to find an approximation to

033x10dx\int_{0}^{3}\left|3^{x}-10\right| \mathrm{d} x
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