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A-Level CAIE Mathematics AS2.4 DifferentiationQuestion Bank

[Maximum number: 3]

Solve the equation |5 x-2|=|4 x+9|.

[Maximum number: 3]

Find the gradient of the curve y=ln(5x+1)y=\ln (5 x+1) at the point where x=4.

[Maximum number: 3]

Given that y=lnxx2y=\frac{\ln x}{x^{2}}, find the exact value of dy dx\frac{\mathrm{d} y}{\mathrm{~d} x} when x=e.

A curve is defined for 0<θ<12π0<\theta<\frac{1}{2} \pi by the parametric equations

x=tanθ,y=2cos2θsinθx=\tan \theta, \quad y=2 \cos ^{2} \theta \sin \theta

Show that dy dx=6cos5θ4cos3θ\frac{\mathrm{d} y}{\mathrm{~d} x}=6 \cos ^{5} \theta-4 \cos ^{3} \theta.

[Maximum number: 4]

The equation of a curve is y=sinx1+cosxy=\frac{\sin x}{1+\cos x}, for π<x<π-\pi<x<\pi. Show that the gradient of the curve is positive for all x in the given interval.

[Maximum number: 5]

The curve with equation y=e2x1x2y=\frac{\mathrm{e}^{-2 x}}{1-x^{2}} has a stationary point in the interval -1<x<1. Find dy dx\frac{\mathrm{d} y}{\mathrm{~d} x} and hence find the x-coordinate of this stationary point, giving the answer correct to 3 decimal places.

The curve with equation y=sin2xe2xy=\frac{\sin 2 x}{\mathrm{e}^{2 x}} has one stationary point in the interval 0x12π0 \leqslant x \leqslant \frac{1}{2} \pi. Find the exact x-coordinate of this point.

[Maximum number: 6]

Find the gradient of each of the following curves at the point for which x=0.

(a)

y=3sinx+tan2xy=3 \sin x+\tan 2 x

[ 3 ]
(b)

y=61+e2xy=\frac{6}{1+\mathrm{e}^{2 x}}

[ 3 ]
[Maximum number: 4]

A curve has equation y=3ln(2x+9)2lnxy=3 \ln (2 x+9)-2 \ln x.

(a)

Find the x-coordinate of the stationary point.

[ 4 ]
[Maximum number: 5]

A curve has equation y=7+4ln(2x+5)y=7+4 \ln (2 x+5).
Find the equation of the tangent to the curve at the point ( -2,7 ), giving your answer in the form y=m x+c.

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