Simplify .
Given that , find the exact value of .
EduNinjaSimplify sin2αsecα.
Given that 3cos2β+7cosβ=0, find the exact value of cosβ.
Solve the equation 2sin(θ+30∘)+5cosθ=2sinθ for 0∘<θ<90∘.
Solve the equation sec2θ+tan2θ=5tanθ+4 for 0∘<θ<180∘. Show all necessary working.
By first expanding sin(θ+30∘), solve the equation sin(θ+30∘)cosecθ=2 for 0∘<θ<360∘.
Express the equation tan(θ+45∘)−2tan(θ−45∘)=4 as a quadratic equation in tanθ. Hence solve this equation for 0∘⩽θ⩽180∘.
Solve the equation 5cosθ(1+cos2θ)=4 for 0∘⩽θ⩽360∘.
Express 5sinx−3cosx in the form Rsin(x−α), where R>0 and 0<α<21π. Give the exact value of R and give α correct to 2 decimal places.
Hence state the greatest and least possible values of (5sinx−3cosx)2.
Showing all necessary working, solve the equation sin(θ−30∘)+cosθ=2sinθ, for 0∘<θ<180∘.
It is given that secθ=17 where 0<θ<21π.
Find the exact value of tan(θ+41π).
Show that the equation tan(x+45∘)=6tanx can be written in the form
Hence solve the equation tan(x+45∘)=6tanx, for 0∘<x<180∘.