CAIE A-Level Mathematics A2 4.1.3 Forces Questions

Resolving either direction to get an equation

*M1

Correct number of relevant terms;
allow sign errors;
allow
$\sin / \cos$ mix.

$$10 \cos 25=2 \cos 40+16 \sin \theta$$$$\left[\begin{array}{c} 9.06307787=1.532088886+16 \sin \theta 7.530988984=16 \sin \theta \sin \theta=0.4706868115 \end{array}\right]$$$$\begin{aligned} P=10 \sin 25+16 \cos \theta+2 \sin 40 {\left[\begin{array}{c} P=4.226182617+16 \cos \theta+1.285575219 P=5.511757837+16 \cos \theta \end{array}\right]} \end{aligned}$$
This may be with their $\theta$.

Attempt to solve for $\theta=\sin ^{-1}\left(\frac{10 \cos 25-2 \cos 40}{16}\right)$
From equation(s) with correct number of relevant terms.
Must be a numerical expression for $\theta$.

Attempt to solve for $P=10 \sin 25+16 \cos ($ their $\theta)+2 \sin 40$
From equation(s) with correct number of relevant terms.
Using their $\theta$.
Must be a numerical expression for P.

$\theta=28.1$ AND P=19.6
28.07888819 and 19.6285636.
AWRT 28.1 and AWRT 19.6 from correct work.