CAIE A-Level Further Math AS 1.2 Rational Functions and Graphs QuestionsPractise sketching rational and related graphs from asymptotes, intercepts, modulus changes and exact solution intervals.Syllabus2028–2030CourseFurther Mathematics 9231LevelAS
Exam pointssketch rational curves with labelled axes, asymptotes and interceptsuse transformed graphs, including modulus curves, to solve inequalities exactly
Question 1[Maximum number: 15]The curve C has equation y=f(x), where f(x)=x2+2x2−x−2\mathrm{f}(x)=\frac{x^{2}+2}{x^{2}-x-2}f(x)=x2−x−2x2+2.Question (a)(a)Find the equations of the asymptotes of C.[ 2 ]Show Answerx=−1,x=2x=-1, \quad x=2x=−1,x=2Vertical asymptotes.y=1Horizontal asymptote.2Question (b)(b)Find the coordinates of any stationary points on C, giving your answers correct to 1 decimal place.[ 4 ]Show Answerdy dx=(x2−x−2)(2x)−(x2+2)(2x−1)(x2−x−2)2\frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{\left(x^{2}-x-2\right)(2 x)-\left(x^{2}+2\right)(2 x-1)}{\left(x^{2}-x-2\right)^{2}} dxdy=(x2−x−2)2(x2−x−2)(2x)−(x2+2)(2x−1)M1*Finds dy dx\frac{\mathrm{d} y}{\mathrm{~d} x} dxdy.x2+8x−2=0x^{2}+8 x-2=0x2+8x−2=0Sets equal to 0 and forms equation.(-8.2,0.9), (0.2, -0.9).Condone(−4−32,232),(−4+32,−232).\left(-4-3 \sqrt{2}, \frac{2}{3} \sqrt{2}\right),\left(-4+3 \sqrt{2},-\frac{2}{3} \sqrt{2}\right) .(−4−32,322),(−4+32,−322).4Question (c)(c)Sketch C, stating the coordinates of any intersections with the axes.[ 3 ]Show AnswerAxes and all three asymptotes.Correct shape and position, crossing horizontalasymptote.States (0,-1) coordinates of intersection with axes,may be seen on diagram.3Question (d)(d)Sketch the curve with equation y=1f(x)y=\frac{1}{\mathrm{f}(x)}y=f(x)1.[ 2 ]Show AnswerB1 FTFT from sketch in (c)B1All correct.2Question (e)(e)Find the set of values for which 1f(x)<f(x)\frac{1}{\mathrm{f}(x)}<\mathrm{f}(x)f(x)1<f(x).Additional pageIf you use the following page to complete the answer to any question, the question number must be clearly shown.[ 4 ]Show Answerx2+2x2−x−2=1 or x2+2x2−x−2=−1x+4=0 or 2x2−x=0\begin{aligned} \frac{x^{2}+2}{x^{2}-x-2}=1 \text { or } \frac{x^{2}+2}{x^{2}-x-2}=-1 x+4=0 \quad \text { or } \quad 2 x^{2}-x=0 \end{aligned}x2−x−2x2+2=1 or x2−x−2x2+2=−1x+4=0 or 2x2−x=0Finds critical points, award M1 for each case.x=−4x=-4 \quadx=−4 or x=0,x=12x=0, \quad x=\frac{1}{2}x=0,x=21−4<x<−1,0<x<12,x>2-4<x<-1, \quad 0<x<\frac{1}{2}, x>2−4<x<−1,0<x<21,x>2Must have three distinct regions. Condone ⩽−1\leqslant-1⩽−1and ⩾2\geqslant 2⩾2.4Add to Test
Question (a)(a)Find the equations of the asymptotes of C.[ 2 ]Show Answerx=−1,x=2x=-1, \quad x=2x=−1,x=2Vertical asymptotes.y=1Horizontal asymptote.2
Question (b)(b)Find the coordinates of any stationary points on C, giving your answers correct to 1 decimal place.[ 4 ]Show Answerdy dx=(x2−x−2)(2x)−(x2+2)(2x−1)(x2−x−2)2\frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{\left(x^{2}-x-2\right)(2 x)-\left(x^{2}+2\right)(2 x-1)}{\left(x^{2}-x-2\right)^{2}} dxdy=(x2−x−2)2(x2−x−2)(2x)−(x2+2)(2x−1)M1*Finds dy dx\frac{\mathrm{d} y}{\mathrm{~d} x} dxdy.x2+8x−2=0x^{2}+8 x-2=0x2+8x−2=0Sets equal to 0 and forms equation.(-8.2,0.9), (0.2, -0.9).Condone(−4−32,232),(−4+32,−232).\left(-4-3 \sqrt{2}, \frac{2}{3} \sqrt{2}\right),\left(-4+3 \sqrt{2},-\frac{2}{3} \sqrt{2}\right) .(−4−32,322),(−4+32,−322).4
Question (c)(c)Sketch C, stating the coordinates of any intersections with the axes.[ 3 ]Show AnswerAxes and all three asymptotes.Correct shape and position, crossing horizontalasymptote.States (0,-1) coordinates of intersection with axes,may be seen on diagram.3
Question (d)(d)Sketch the curve with equation y=1f(x)y=\frac{1}{\mathrm{f}(x)}y=f(x)1.[ 2 ]Show AnswerB1 FTFT from sketch in (c)B1All correct.2
Question (e)(e)Find the set of values for which 1f(x)<f(x)\frac{1}{\mathrm{f}(x)}<\mathrm{f}(x)f(x)1<f(x).Additional pageIf you use the following page to complete the answer to any question, the question number must be clearly shown.[ 4 ]Show Answerx2+2x2−x−2=1 or x2+2x2−x−2=−1x+4=0 or 2x2−x=0\begin{aligned} \frac{x^{2}+2}{x^{2}-x-2}=1 \text { or } \frac{x^{2}+2}{x^{2}-x-2}=-1 x+4=0 \quad \text { or } \quad 2 x^{2}-x=0 \end{aligned}x2−x−2x2+2=1 or x2−x−2x2+2=−1x+4=0 or 2x2−x=0Finds critical points, award M1 for each case.x=−4x=-4 \quadx=−4 or x=0,x=12x=0, \quad x=\frac{1}{2}x=0,x=21−4<x<−1,0<x<12,x>2-4<x<-1, \quad 0<x<\frac{1}{2}, x>2−4<x<−1,0<x<21,x>2Must have three distinct regions. Condone ⩽−1\leqslant-1⩽−1and ⩾2\geqslant 2⩾2.4
Question 2[Maximum number: 16]The curve C has equation y=f(x), where f(x)=x2x+1\mathrm{f}(x)=\frac{x^{2}}{x+1}f(x)=x+1x2.Question (a)(a)Find the equations of the asymptotes of C.[ 3 ]Show Answerx=-1Vertical asymptote.y=(x+1)(x−1)+1x+1y=\frac{(x+1)(x-1)+1}{x+1}y=x+1(x+1)(x−1)+1Oblique asymptote.y=x-13Question (b)(b)Find the coordinates of any stationary points on C.[ 2 ]Show Answerdy dx=x2+2x(x+1)2=0\frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{x^{2}+2 x}{(x+1)^{2}}=0 dxdy=(x+1)2x2+2x=0Sets dy dx=0\frac{\mathrm{d} y}{\mathrm{~d} x}=0 dxdy=0.(0,0), (-2,-4)2Question (c)(c)Sketch C.[ 3 ]Show AnswerAxes and asymptotes.Left branch correct.Right branch correct.3Question (d)(d)Find the coordinates of any stationary points on the curve with equation y=1f(x)y=\frac{1}{\mathrm{f}(x)}y=f(x)1.[ 2 ]Show Answer( −2,−14-2,-\frac{1}{4}−2,−41 )B1 for each correct coordinate. SC B1for ( −2,−14-2,-\frac{1}{4}−2,−41 ) and ( 0,0 ).2Question (e)(e)Sketch the curve with equation y=1f(x)y=\frac{1}{\mathrm{f}(x)}y=f(x)1 and find, in exact form, the set of values for which 1f(x)>f(x)\frac{1}{\mathrm{f}(x)}>\mathrm{f}(x)f(x)1>f(x).[ 6 ]Show AnswerLeft branch correct.Right branch correct.x2x+1=1 or x2x+1=−1x2−x−1=0\begin{aligned} \frac{x^{2}}{x+1}=1 \text { or } \frac{x^{2}}{x+1}=-1 x^{2}-x-1=0 \end{aligned}x+1x2=1 or x+1x2=−1x2−x−1=0Finds critical points, award M1 foreach case.x=12−125x=\frac{1}{2}-\frac{1}{2} \sqrt{5}x=21−215 or x=12+125x=\frac{1}{2}+\frac{1}{2} \sqrt{5}x=21+215x<−1,12−125<x<12+125,x≠0x<-1, \quad \frac{1}{2}-\frac{1}{2} \sqrt{5}<x<\frac{1}{2}+\frac{1}{2} \sqrt{5}, \quad x \neq 0x<−1,21−215<x<21+215,x=0Condone missing x≠0x \neq 0x=0.6Add to Test
Question (a)(a)Find the equations of the asymptotes of C.[ 3 ]Show Answerx=-1Vertical asymptote.y=(x+1)(x−1)+1x+1y=\frac{(x+1)(x-1)+1}{x+1}y=x+1(x+1)(x−1)+1Oblique asymptote.y=x-13
Question (b)(b)Find the coordinates of any stationary points on C.[ 2 ]Show Answerdy dx=x2+2x(x+1)2=0\frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{x^{2}+2 x}{(x+1)^{2}}=0 dxdy=(x+1)2x2+2x=0Sets dy dx=0\frac{\mathrm{d} y}{\mathrm{~d} x}=0 dxdy=0.(0,0), (-2,-4)2
Question (c)(c)Sketch C.[ 3 ]Show AnswerAxes and asymptotes.Left branch correct.Right branch correct.3
Question (d)(d)Find the coordinates of any stationary points on the curve with equation y=1f(x)y=\frac{1}{\mathrm{f}(x)}y=f(x)1.[ 2 ]Show Answer( −2,−14-2,-\frac{1}{4}−2,−41 )B1 for each correct coordinate. SC B1for ( −2,−14-2,-\frac{1}{4}−2,−41 ) and ( 0,0 ).2
Question (e)(e)Sketch the curve with equation y=1f(x)y=\frac{1}{\mathrm{f}(x)}y=f(x)1 and find, in exact form, the set of values for which 1f(x)>f(x)\frac{1}{\mathrm{f}(x)}>\mathrm{f}(x)f(x)1>f(x).[ 6 ]Show AnswerLeft branch correct.Right branch correct.x2x+1=1 or x2x+1=−1x2−x−1=0\begin{aligned} \frac{x^{2}}{x+1}=1 \text { or } \frac{x^{2}}{x+1}=-1 x^{2}-x-1=0 \end{aligned}x+1x2=1 or x+1x2=−1x2−x−1=0Finds critical points, award M1 foreach case.x=12−125x=\frac{1}{2}-\frac{1}{2} \sqrt{5}x=21−215 or x=12+125x=\frac{1}{2}+\frac{1}{2} \sqrt{5}x=21+215x<−1,12−125<x<12+125,x≠0x<-1, \quad \frac{1}{2}-\frac{1}{2} \sqrt{5}<x<\frac{1}{2}+\frac{1}{2} \sqrt{5}, \quad x \neq 0x<−1,21−215<x<21+215,x=0Condone missing x≠0x \neq 0x=0.6