37.3 Carbon-13 NMR spectroscopy

Syllabus
9701–2028–2029
Topic
37.3
Level
A2

Use carbon-13 peak count and shifts together to constrain a structure

To interpret a simple 13C NMR spectrum: 1) count sample peaks to find the number of chemically distinct carbon environments; 2) assign each chemical-shift region to plausible carbon environments; 3) combine those constraints with the molecular formula and other data; 4) draw candidate structures; 5) reject any candidate whose environment count or required shifts disagree.

Approximate delta / ppm Carbon environment indicated
0-50 saturated alkyl carbon
30-70 saturated carbon near C=O, halogen or O (use the narrower supplied data ranges)
100-125 nitrile carbon
110-160 alkene or arene carbon
160-185 carboxylic acid or ester carbonyl carbon
190-220 aldehyde or ketone carbonyl carbon

Propanone gives two sample signals: one in the ketone C=O region for the carbonyl carbon and one in the saturated-carbon region for the two equivalent CH3 carbons. Two peaks therefore represent three carbon atoms in two environments.

Treat TMS at 0 ppm as the reference and ignore a labelled solvent peak such as CDCl3 near 77 ppm. Routine 13C peak heights are not directly proportional to the number of carbons in an environment.

Peak count alone rarely proves one structure, and a shift region alone does not determine connectivity. A proposed structure must satisfy both the number of distinct environments and every chemically plausible peak position.

Predict one carbon-13 peak for each chemically distinct carbon environment

Label every carbon, compare the atoms/groups reached in each direction, and merge only carbons related by genuine molecular symmetry or chemical equivalence. The number of remaining classes is the predicted number of 13C signals.

Molecule Carbon atoms Distinct environments / predicted peaks Reason
propane 3 2 the two terminal CH3 carbons are equivalent
propanone 3 2 the two CH3 carbons are equivalent; C=O is distinct
propan-2-ol 3 2 the two CH3 carbons are equivalent; central C-O carbon is distinct
butan-2-one 4 4 carbonyl C, adjacent CH3, CH2 and terminal CH3 all have different surroundings
benzene 6 1 all six ring carbons are symmetry-equivalent

To explain a reduced peak count, state which carbons are equivalent and identify the symmetry that exchanges them without changing the molecule. Merely saying 'it is symmetrical' is incomplete if the equivalent positions are not identified.

Do not count carbon atoms, hydrogens or peak height. Butan-2-one is not a three-environment molecule: its two terminal CH3 groups are not equivalent, and its CH2 and carbonyl carbon add two further environments, giving four.