29. An introduction to A Level organic chemistry A2

Syllabus
9701–2028–2029
Section
29
Level
A2

A Level organic chemistry A2 conventions and functional group reference

Syllabus
9701–2028–2029
Topic
—
Level
A2

Recognise the A Level organic functional groups from connectivity

Recognise a functional group from which atoms are directly bonded, not by spotting one atom or relying on a name. In the formulae below, R and R′ are carbon-containing groups, Ar is an arene ring, and X is a halogen.

Family Recognition pattern Decisive connectivity / example
arene Ar contains a benzene ring; e.g. methylbenzene
halogenoarene Ar–X X is directly bonded to a ring carbon; e.g. chlorobenzene
phenol Ar–OH OH is directly bonded to a ring carbon; e.g. phenol
acyl chloride R–C(=O)–Cl Cl is bonded to the carbonyl carbon; e.g. CH₃COCl
secondary / tertiary amine R₂NH / R₃N N is bonded to two / three carbon groups
primary / secondary / tertiary amide RCONH₂ / RCONHR′ / RCONR′R″ N is directly bonded to a carbonyl carbon and has zero, one or two N-substituent carbon groups
amino acid H₂N–CHR–CO₂H amine and carboxyl groups occur in the same molecule; R = H gives glycine
Do not confuse… Discriminating bond
halogenoarene vs halogenoalkane Ar–X vs an sp³ carbon–X bond outside the ring
phenol vs aromatic alcohol Ar–OH vs Ar–CH₂OH
acyl chloride vs chloro-ketone C(=O)–Cl vs Cl elsewhere on the carbon skeleton
amide vs amine amide N is directly bonded to C=O; amine N is not

The official reference table requires recognition and use of these structures. Systematic naming of secondary and tertiary amines is not required here; later chapters teach their characteristic reactions and comparisons.

Keep a benzene ring abbreviated inside a larger displayed structure

When a benzene ring is part of a molecule, Cambridge does not expect its six carbon atoms and attached ring hydrogens to be expanded as a fully displayed formula. Keep the ring as the conventional benzene hexagon and display the substituent connectivity clearly.

Molecule What the representation must show
chlorobenzene a benzene ring with Cl bonded directly to one ring vertex
phenol a benzene ring with OH bonded directly to one ring vertex
methylbenzene a benzene ring with CH₃ bonded to one ring vertex
disubstituted arene two bonds from the correct ring vertices so their relative positions are unambiguous

If the rest of a molecule is requested as a displayed formula, draw those non-ring atoms and bonds explicitly while leaving the benzene ring in its accepted ring representation. The bond from the ring to each substituent is still part of the required connectivity.

The ring symbol already supplies the six-carbon aromatic framework; it is not an extra atom. Do not omit a substituent bond, attach X or OH through an unintended CH₂ group, or redraw every ring C–H bond when the ring is only part of the molecule.

29.1 Formulas, functional groups and nomenclature

Syllabus
9701–2028–2029
Topic
29.1
Level
A2

A functional group's connectivity produces characteristic properties

A functional group is the connected atom arrangement that produces a class's characteristic physical and chemical properties. The rest of the carbon skeleton modifies those properties, but does not replace the functional group's characteristic chemistry.

Page-47 class Structural feature Consequence that distinguishes the class
arene delocalised benzene π system characteristic aromatic rather than alkene-like reaction behaviour
phenol OH directly bonded to an arene ring ring–OH interaction gives behaviour different from an aliphatic alcohol
acyl chloride polar C=O bonded to Cl reactive carbonyl derivative with characteristic substitution chemistry
amine N lone pair not directly beside C=O can accept H⁺ and behave as a base
amide N directly bonded to C=O N lone pair is delocalised toward the carbonyl, so it is much less available than in an amine
amino acid amine and carboxyl groups in one molecule can show both basic and acidic behaviour

Within one homologous class, increasing carbon-chain size can alter boiling point and solubility through intermolecular-force balance. To predict a molecule, identify both the functional group and the size or shape of its carbon framework.

One atom is not a functional-group diagnosis: OH on an arene is phenol, but OH on an sp³ carbon is an alcohol; nitrogen beside C=O is an amide, not an amine.

Translate between general, structural, displayed and skeletal formulae without changing connectivity

Formula style What it communicates Example use for an acyl chloride
general the family pattern across different members RCOCl
structural atom order and grouped connectivity CH₃CH₂COCl
displayed every atom and every covalent bond in the shown non-benzene structure show CH₃–CH₂–C with C=O and C–Cl, including all C–H bonds
skeletal carbon framework as lines; C atoms and C-bound H atoms are omitted a two-segment chain ending at C(=O)Cl

In a skeletal formula, every unlabelled line end or vertex is carbon; add enough implied H atoms to give carbon four bonds. Heteroatoms such as N, O and Cl are written, and hydrogens attached to heteroatoms are shown when present.

A valid translation preserves carbon count, functional-group connectivity, multiple bonds and overall charge. For CH₃CH₂COCl, every style must still show three carbons and Cl directly bonded to the carbonyl carbon.

A general formula describes a class, not one unique molecule. A molecular formula gives atom counts but may hide connectivity and isomerism; neither can replace a structural formula when bond order matters.

Name bounded aliphatic structures with one systematic workflow

Step Naming decision
1 identify the principal functional group and its suffix
2 choose the longest parent chain containing that group, or the single parent ring
3 number from the end that gives the principal group the lowest locant, then the lowest locant set
4 identify substituents, positions and multiplicative prefixes; alphabetise distinct prefixes
5 assemble locants, prefixes, parent, unsaturation and suffix with correct punctuation
Syllabus boundary Required range
ordinary aliphatic molecules up to 6 carbon atoms
cyclic molecules one ring only, containing up to 6 carbon atoms
esters and amides up to 6 + 6 carbon atoms in the two carbon-containing parts
esters and nitriles straight chains only
secondary and tertiary amines recognise structures; their naming is not required by the page-47 table
Structure Key parent decision Systematic name
CH₃CH₂COCl 3-carbon acyl chain propanoyl chloride
CH₃CH(NH₂)CO₂H carboxyl carbon is C1; amino on C2 2-aminopropanoic acid
CH₃CH₂CONHCH₃ propanamide parent; methyl substituent is on N N-methylpropanamide
CH₃COOCH₂CH₃ alcohol-derived ethyl first; acid-derived ethanoate second ethyl ethanoate

The parent is not simply the visually longest line if it omits the principal group. In nitriles the C≡N carbon belongs to the parent count; in esters the two sides have different naming roles and are not joined into one chain.

Name one-ring aromatic molecules from the parent group and lowest locants

Step Aromatic naming move
1 choose benzene or the retained functional parent, such as phenol or benzoic acid
2 assign the parent-group ring carbon as C1 when the parent fixes it
3 number around the ring in the direction giving the lowest complete set of locants
4 add substituent locants and di-, tri-, etc.; alphabetise different substituent prefixes where needed
Structure description Numbering Name
benzoic acid with NO₂ two ring bonds from C1 CO₂H-bearing carbon is C1; NO₂ at C3 3-nitrobenzoic acid
phenol with Br on both adjacent carbons and the opposite carbon OH-bearing carbon is C1; Br at C2, C4 and C6 2,4,6-tribromophenol

Keep the single benzene ring in its conventional ring form and show each substituent bond at the correct vertex. The spatial drawing and locants must encode the same relative positions.

Do not renumber phenol or benzoic acid from an arbitrary substituent, and do not optimise only the first locant while ignoring the full ordered locant set. This objective is limited to one benzene ring with simple substituents.

29.2 Characteristic organic reactions

Syllabus
9701–2028–2029
Topic
29.2
Level
A2

Distinguish electrophilic substitution from addition–elimination by its step sequence

Mechanism term Attacking species and site Characteristic sequence Net result
electrophilic substitution an electrophile attacks an electron-rich arene π system electrophile bonds to the ring; H⁺ or another group is lost; the delocalised π system is restored one ring atom/group is replaced by the electrophile
nucleophilic addition–elimination a nucleophile attacks the δ⁺ carbonyl carbon of an acyl derivative nucleophile adds and C=O π electrons move to O; C=O reforms as a leaving group departs one group on the acyl carbon is replaced by the nucleophile

Read the name as a mechanism history. ‘Electrophilic’ or ‘nucleophilic’ identifies the electron-pair acceptor or donor that attacks; ‘substitution’ describes the overall replacement; ‘addition–elimination’ records two successive stages even though its overall product also looks substituted.

CX6HX6+BrX2→AlBrX3CX6HX5Br+HBr\ce{C6H6 + Br2 ->[AlBr3] C6H5Br + HBr}

In bromination, the catalyst helps generate a sufficiently strong electrophile. The benzene ring forms a bond to it and then loses H⁺, restoring aromatic delocalisation; this is substitution rather than permanent addition to the ring.

CHX3COCl+HX2O→CHX3COOH+HCl\ce{CH3COCl + H2O -> CH3COOH + HCl}

In acyl-chloride hydrolysis, water attacks the carbonyl carbon to form an addition intermediate. The carbonyl reforms as Cl⁻ leaves; proton transfer gives the overall carboxylic acid and HCl products.

Do not classify from the overall equation alone. Electrophilic addition leaves new groups added across a π bond, whereas electrophilic substitution restores the arene π system; addition–elimination contains a real addition intermediate before the leaving group departs.

29.3 Shapes of aromatic organic molecules; σ and π bonds

Syllabus
9701–2028–2029
Topic
29.3
Level
A2

sp² ring carbons create a planar σ framework and one delocalised π system

Each carbon in benzene is sp² hybridised. Its three sp² orbitals form three σ bonds in a trigonal-planar arrangement with bond angles of about 120°, so the six carbon atoms and their attached hydrogen atoms form a planar hexagonal σ framework.

Bonding part Orbitals and overlap Position of electron density Role in benzene
σ framework end-on overlap of sp² orbitals for C–C and sp² with H 1s for C–H along internuclear axes, in the molecular plane fixes the six-membered planar skeleton; 6 C–C σ and 6 C–H σ bonds
delocalised π system sideways overlap of one unhybridised p orbital on every carbon continuous regions above and below the ring plane spreads six π electrons over all six carbon atoms

sp² hybridisation first provides coplanar σ-bond directions and leaves one p orbital perpendicular to the plane on each carbon. Because all six p orbitals are parallel and adjacent, they overlap around the whole ring; this continuous overlap produces the delocalised π system.

Delocalisation makes all six C–C bonds equivalent, with bond length and character intermediate between localised C–C single and C=C double bonds. Benzene is therefore not three independent alkene units.

The same test applies to other aromatic ring systems: the atoms participating in the conjugated ring must provide aligned adjacent p orbitals for continuous delocalisation. An attached substituent or non-ring atom is not automatically in the same plane unless its own bonding requires it.

Planarity enables parallel p-orbital overlap; it is misleading to say that delocalisation alone creates the sp² geometry. The circle in a benzene symbol represents the delocalised π system, not an extra atom, bond or electron shell.

29.4 Optical isomerism

Syllabus
9701–2028–2029
Topic
29.4
Level
A2

Enantiomers usually share properties but differ in biological fit and optical rotation

Enantiomers are non-superimposable mirror images. In an achiral environment they have the same melting point, boiling point and many chemical properties, but they rotate plane-polarised light in opposite directions.

A chiral receptor or enzyme is itself asymmetric, so the two enantiomers can bind differently and produce different biological effects.

Two enantiomers may pass through an ordinary solvent identically yet one fit a biological active site better, like opposite hands fitting a glove.

R and S labels do not by themselves tell you clockwise optical rotation, and ‘same formula’ does not mean the molecules are superimposable.

Optically active samples rotate plane-polarised light; racemates cancel

An optically active sample rotates plane-polarised light. A racemic mixture contains equal amounts of both enantiomers, whose opposite rotations cancel, so the mixture shows no net rotation.

Optical activity describes the sample, not simply the presence of a chiral carbon. A sample enriched in one enantiomer can be active; a perfectly 1:1 mixture is racemic.

A pure (+) enantiomer and pure (−) enantiomer rotate light by equal magnitudes in opposite directions. Mixing equal amounts gives zero observed rotation.

No net rotation does not prove that no chiral molecules are present; it may indicate cancellation in a racemate.

Enantiomers rotate plane-polarised light in opposite directions

The two enantiomers of one substance rotate plane-polarised light by equal angles in opposite directions under the same conditions. One is dextrorotatory (+), the other laevorotatory (−).

The sign of rotation is measured experimentally; it is not predicted from the R/S descriptor or from the direction in which the structure is drawn on a page.

If one enantiomer rotates light +12°, its mirror image rotates it −12° at the same concentration, path length and temperature.

R/S nomenclature and +/− optical rotation are independent labels. Never replace one with the other.

Chiral drug synthesis must control which enantiomer reaches the patient

Drug targets such as receptors and enzymes are chiral. Two drug enantiomers can therefore fit them differently, so one may give the intended effect while the other is less active, inactive or produces a different effect; the outcome must be measured rather than assumed.

Preparation route What happens Why it matters
achiral synthesis then resolution a racemic 1:1 mixture is formed and separated into pure enantiomers supplies the required enantiomer, but separation adds steps and the other enantiomer must be handled or recycled
synthesis with a chiral catalyst the catalyst creates an asymmetric reaction environment that favours formation of one mirror-image pathway produces predominantly the chosen enantiomer and reduces later separation demand
biological chiral catalyst an enzyme active site binds reactants in one orientation can provide high stereoselectivity toward one enantiomer

A pharmaceutical route must identify which enantiomer has the desired biological activity, control or separate the product composition, and verify enantiomeric purity. A racemate cannot be assumed equivalent to the same dose of one pure enantiomer.

A molecule can contain more than one chiral centre, increasing the possible spatial arrangements. This syllabus does not require meso compounds or nomenclature such as diastereoisomers, so do not use those as required explanations here.