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IGCSE Chemistry3.3 The mole and the Avogadro constantQuestion Bank

Question 1

[Maximum number: 2]

Iron ore contains iron(III) oxide, Fe2O3\mathrm{Fe}_{2} \mathrm{O}_{3}. A blast furnace is used to extract iron from Fe2O3\mathrm{Fe}_{2} \mathrm{O}_{3}.
Equations for some of the reactions in the blast furnace are shown.

equation 1C+O2CO21 \mathrm{C}+\mathrm{O}_{2} \rightarrow \mathrm{CO}_{2}

equation 2CaCO3CaO+CO22 \mathrm{CaCO}_{3} \rightarrow \mathrm{CaO}+\mathrm{CO}_{2}

equation 3CaO+SiO2CaSiO33 \quad \mathrm{CaO}+\mathrm{SiO}_{2} \rightarrow \mathrm{CaSiO}_{3}

Question 1(b)

(a)

Iron(III) oxide, Fe2O3\mathrm{Fe}_{2} \mathrm{O}_{3}, in iron ore is converted to iron when it reacts with carbon monoxide, CO , in the blast furnace.

[ 2 ]

Question 1(b)(i)

(i)

Calculate the percentage by mass of iron in iron(III) oxide, Fe2O3\mathrm{Fe}_{2} \mathrm{O}_{3}.

percentage=...............................%[2]percentage = ...............................\% [2]
[ 2 ]

Question 1

[Maximum number: 2]

This question is about elements X, Y and Z.

Question 1(b)

Question 1(b)(iii)

(a)
(i)

What is the name of the amount of any substance that contains 6.02×10236.02 \times 10^{23} particles?

[ 1 ]

Question 1(b)(iv)

(ii)

The constant 6.02×10236.02 \times 10^{23} has a name.

What is the name of this constant?

[ 1 ]

Question 2

[Maximum number: 3]

Period 3 contains the elements sodium to argon. This question asks about the chemistry of each of the Period 3 elements or their compounds.

Question 2(a)

(a)

Sodium nitrate is a white crystalline solid. When heated it melts and the following reaction occurs.

2NaNO3(I)2NaNO2(I)+O2( g)2 \mathrm{NaNO}_{3}(\mathrm{I}) \rightarrow 2 \mathrm{NaNO}_{2}(\mathrm{I})+\mathrm{O}_{2}(\mathrm{~g})

A 3.40 g sample of sodium nitrate is heated.
Calculate the
- number of moles of NaNO3\mathrm{NaNO}_{3} used, mol
- number of moles of O2\mathrm{O}_{2} formed, mol
- volume of O2\mathrm{O}_{2} formed, in dm3\mathrm{dm}^{3} (measured at r.t.p.). dm3\mathrm{dm}^{3}

[ 3 ]

Question 7

[Maximum number: 1]

Which gas sample contains the smallest number of molecules?

A

4 g of helium

B

16 g of oxygen

C

28 g of carbon monoxide

D

28 g of nitrogen

Question 7

[Maximum number: 1]

The concentration of a hydrochloric acid solution is 0.5 mol/dm30.5 \mathrm{~mol} / \mathrm{dm}^{3}.
How many moles of hydrochloric acid are present in 25 cm325 \mathrm{~cm}^{3} of this solution?

A

0.0125

B

0.0200

C

12.5

D

20.0

Question 7

[Maximum number: 1]

Which gas sample contains the most molecules?

A

24dm324 \mathrm{dm}^{3} of carbon dioxide, CO2\mathrm{CO}_{2}

B

4 g of hydrogen, H2\mathrm{H}_{2}

C

36dm336 \mathrm{dm}^{3} of hydrogen chloride, HCl

D

14 g of nitrogen, N2\mathrm{N}_{2}

Question 7

[Maximum number: 1]

Which gas sample has the greatest mass?

A

5.0 moles of Cl2\mathrm{Cl}_{2}

B

10.0 moles of O2\mathrm{O}_{2}

C

15.0 moles of N2\mathrm{N}_{2}

D

20.0 moles of H2\mathrm{H}_{2}

Question 7

[Maximum number: 1]

The equation for the reaction of iron(III) oxide with carbon monoxide is shown.

Fe2O3+3CO2Fe+3CO2\mathrm{Fe}_{2} \mathrm{O}_{3}+3 \mathrm{CO} \rightarrow 2 \mathrm{Fe}+3 \mathrm{CO}_{2}

What is the percentage yield of iron when 16.8 g of carbon monoxide reacts completely with iron(III) oxide to form 8.96 g of iron?

A

26.7%

B

40.0\%

C

53.3\%

D

80.0\%

Question 7

[Maximum number: 1]

Which sample contains the largest number of molecules?

A

16 g of methane, CH4( g)\mathrm{CH}_{4}(\mathrm{~g})

B

16 g of oxygen, O2( g)\mathrm{O}_{2}(\mathrm{~g})

C

16 g of phosphorus, P4( s)\mathrm{P}_{4}(\mathrm{~s})

D

16dm316 \mathrm{dm}^{3} of methane at r.t.p., CH4( g)\mathrm{CH}_{4}(\mathrm{~g})

Question 8

[Maximum number: 1]

A tablet contains 0.080 g of ascorbic acid ( Mr=176M_{\mathrm{r}}=176 ).
What is the concentration of ascorbic acid when one tablet is dissolved in 200 cm3200 \mathrm{~cm}^{3} of water?

A

9.1×105 mol/dm39.1 \times 10^{-5} \mathrm{~mol} / \mathrm{dm}^{3}

B

4.5×104 mol/dm34.5 \times 10^{-4} \mathrm{~mol} / \mathrm{dm}^{3}

C

9.1×102 mol/dm39.1 \times 10^{-2} \mathrm{~mol} / \mathrm{dm}^{3}

D

2.3×103 mol/dm32.3 \times 10^{-3} \mathrm{~mol} / \mathrm{dm}^{3}

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