Question 1
A curve with equation y=f(x) is such that . It is given that the curve passes through the point (2,7).
Find f(x).
EduNinjaA curve with equation y=f(x) is such that f′(x)=6x2−x28. It is given that the curve passes through the point (2,7).
Find f(x).
A curve is such that dxdy=(2x+5) and (2,5) is a point on the curve. Find the equation of the curve.
The equation of a curve is such that dxdy=(x−3)34 for x>3. The curve passes through the point (4,5).
Find the equation of the curve.
A curve passes through the point (4,-6) and has an equation for which dxdy=x−21−3. Find the equation of the curve.
Find ∫(x3+x31)dx.
A curve is such that dxdy=(4x+1)8. The point (2,5) lies on the curve. Find the equation of the curve.
A curve is such that its gradient at a point (x, y) is given by dxdy=x−3x−21. It is given that the curve passes through the point (4,1).
Find the equation of the curve.
The function f is such that f′(x)=5−2x2 and ( 3,5 ) is a point on the curve y=f(x). Find f(x).
The equation of a curve is such that dxdy=x43+32x3. It is given that the curve passes through the point (21,4).
Find the equation of the curve.
A curve is such that dxdy=x26 and (2,9) is a point on the curve. Find the equation of the curve.