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A-Level CAIE Mathematics AS2.3 TrigonometryQuestion Bank

Question 1

[Maximum number: 3]

It is given that θ\theta is an acute angle in degrees such that sinθ=23\sin \theta=\frac{2}{3}.
Find the exact value of sin(θ+60)\sin \left(\theta+60^{\circ}\right).

Question 1

[Maximum number: 4]

Solve the equation sec2θ+tan2θ=5tanθ+4\sec ^{2} \theta+\tan ^{2} \theta=5 \tan \theta+4 for 0<θ<1800^{\circ}<\theta<180^{\circ}. Show all necessary working.

Question 1

Question 1(i)

(a)

Simplify sin2αsecα\sin 2 \alpha \sec \alpha.

[ 2 ]

Question 1(ii)

(b)

Given that 3cos2β+7cosβ=03 \cos 2 \beta+7 \cos \beta=0, find the exact value of cosβ\cos \beta.

[ 3 ]

Question 1

[Maximum number: 4]

Solve the equation 2sin(θ+30)+5cosθ=2sinθ2 \sin \left(\theta+30^{\circ}\right)+5 \cos \theta=2 \sin \theta for 0<θ<900^{\circ}<\theta<90^{\circ}.

Question 2

[Maximum number: 4]

Showing all necessary working, solve the equation sin(θ30)+cosθ=2sinθ\sin \left(\theta-30^{\circ}\right)+\cos \theta=2 \sin \theta, for 0<θ<1800^{\circ}<\theta<180^{\circ}.

Question 2

[Maximum number: 5]

Solve the equation 5cosθ(1+cos2θ)=45 \cos \theta(1+\cos 2 \theta)=4 for 0θ3600^{\circ} \leqslant \theta \leqslant 360^{\circ}.

Question 2

Question 2(a)

(a)

Express 5sinx3cosx5 \sin x-3 \cos x in the form Rsin(xα)R \sin (x-\alpha), where R>0 and 0<α<12π0<\alpha<\frac{1}{2} \pi. Give the exact value of R and give α\alpha correct to 2 decimal places.

[ 3 ]

Question 2(b)

(b)

Hence state the greatest and least possible values of (5sinx3cosx)2(5 \sin x-3 \cos x)^{2}.

[ 2 ]

Question 2

[Maximum number: 6]

Express the equation tan(θ+45)2tan(θ45)=4\tan \left(\theta+45^{\circ}\right)-2 \tan \left(\theta-45^{\circ}\right)=4 as a quadratic equation in tanθ\tan \theta. Hence solve this equation for 0θ1800^{\circ} \leqslant \theta \leqslant 180^{\circ}.

Question 2

[Maximum number: 6]

By first expanding sin(θ+30)\sin \left(\theta+30^{\circ}\right), solve the equation sin(θ+30)cosecθ=2\sin \left(\theta+30^{\circ}\right) \operatorname{cosec} \theta=2 for 0<θ<3600^{\circ}<\theta<360^{\circ}.

Question 2

[Maximum number: 5]

Solve the equation sec θcos(θ60)=4\theta \cos \left(\theta-60^{\circ}\right)=4 for 180<θ<180-180^{\circ}<\theta<180^{\circ}.

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