Edexcel IGCSE Math A Higher 2.4 Linear Equations Questions

Practise solving linear equations and using algebraic working to model totals, costs, perimeters and other worded situations.

Exam points

solve one-variable equations with brackets, fractions or unknowns on both sides
form equations from totals, costs or perimeters before calculating the required value

Covered syllabus points

2.4.A Solving linear equations 2.4.B Forming linear equations

[Maximum number: 3]

Solve 5(4-x)=7-3 x
Show clear algebraic working.

[Maximum number: 5]

The diagram shows a regular hexagon, ABCDEF, and an isosceles triangle, GHJ.

Figure for Question 2 — Edexcel IGCSE Math A Higher

Diagram NOT accurately drawn

The perimeter of the hexagon is equal to the perimeter of the triangle.
Find the length of each side of the hexagon.
Show clear algebraic working.
cm

Hexagon perimeter:
6(x-1)=6x-6
Triangle perimeter:
2(x+5)+2x-3=4x+7
Equate perimeters:
6x-6=4x+7 $2x=13,\qquad x=6.5$
Side of the hexagon:
x-1=5.5
Final answer:
$5.5\text{ cm}$

[Maximum number: 3]

Solve $\frac{8-2 x}{3}-\frac{2 x-3}{2}=4$ Show clear algebraic working.

\frac{8-2x}{3}-\frac{2x-3}{2}=4

Multiply by 6:

2(8-2x)-3(2x-3)=24

16-4x-6x+9=24

25-10x=24

x=0.1

Final answer:

x=0.1

M1 for a method to deal with fractions, e.g. finding a common denominator or multiplying by a common multiple in a correct equation.
M1 for expanding brackets and multiplying by the common denominator in a correct equation;
condone one error in expansion.
A1 oe, dependent on M1.

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Covered syllabus points

Question 1

Question 2

Question 3