2.4 Linear equations

Syllabus
2017
Topic
2.4
Level
Higher

Solve linear equations systematically

A linear equation states that two expressions have equal value. Solving finds the value of the one unknown that preserves this equality.

Structure Reliable move
fractions present multiply every term by a common denominator
brackets present expand accurately, or divide a common factor when valid
unknown on both sides collect all unknown terms on one side
constants on both sides collect constants on the other side
ax=bax=b divide both sides by aa

Solve (82x)/3(2x3)/2=4(8-2x)/3-(2x-3)/2=4. Multiply every term by 6: 2(82x)3(2x3)=242(8-2x)-3(2x-3)=24. Then 2510x=2425-10x=24, so x=1/10x=1/10.

Substitute the solution into both sides of the original equation, not only the simplified line. Equal results check signs, brackets and denominators.

An operation applied to only one side breaks equality. When clearing a denominator, multiply every term and preserve brackets around a multi-term numerator.

Form and solve a linear equation from data

Forming an equation translates a condition about one unknown into two equal expressions. The equality comes from a total, shared measurement or other stated relationship.

Stage Action
choose define one unknown with its unit
express write every related quantity in terms of it
connect use the stated total or equality to form one equation
solve apply a valid linear-equation method
interpret calculate the requested quantity and check context

A regular hexagon has side (x1)(x-1) cm. An isosceles triangle has equal sides (x+5)(x+5) cm and base (2x3)(2x-3) cm. Equal perimeters give 6(x1)=2(x+5)+(2x3)6(x-1)=2(x+5)+(2x-3). Hence x=6.5x=6.5, so each hexagon side is 5.55.5 cm.

For triangle angles aa, a+10a+10 and a+20a+20, use their total: a+(a+10)+(a+20)=180a+(a+10)+(a+20)=180. Solve for aa, then check all three angles are valid.

The solution for the chosen unknown is not always the requested answer. Return to the context, calculate the named length, count or cost, and include its unit.