1.3 Decimals
- Syllabus
- 2017
- Topic
- 1.3
- Level
- Higher
Decimal notation uses a decimal point to separate whole-number places from fractional places. In 23.47, the 23 is the whole part and .47 is forty-seven hundredths.
| Position from the point | Value of one unit |
|---|---|
| first place right | one tenth, 0.1 |
| second place right | one hundredth, 0.01 |
| third place right | one thousandth, 0.001 |
Decimals locate values between integers on a number line. Between 2.2 and 2.3, ten equal intervals represent hundredths, so 2.28 is eight hundredths after 2.2.
Trailing zeros do not change value: 5.2=5.20. A zero between non-zero digits can hold a place, so 5.02 is not equal to 5.2.
The decimal point fixes every place. Do not read 3.05 as thirty-five hundredths; it is three and five hundredths.
Each move one place left multiplies a digit's value by 10; each move one place right divides its value by 10. This rule continues across the decimal point.
| Digit in 4.7634 | Place | Value |
|---|---|---|
| 7 | tenths | 0.7 |
| 6 | hundredths | 0.06 |
| 3 | thousandths | 0.003 |
| 4 | ten-thousandths | 0.0004 |
Expanded form makes the values visible: 4.7634=4+0.7+0.06+0.003+0.0004.
Zero holds an empty place. In 0.407, the zero in the hundredths place keeps the 7 in the thousandths place.
Name the value, not just the digit: the 3 in 4.7634 has value 0.003, not 3 and not 0.03.
To compare decimals, align their decimal points and compare digits from left to right. The first place where the digits differ determines the order.
| Original | Equal-length form |
|---|---|
| 0.078 | 0.078 |
| 0.7 | 0.700 |
| 0.87 | 0.870 |
| 0.08 | 0.080 |
| 0.707 | 0.707 |
Comparing thousandths columns after alignment gives 0.078<0.080<0.700<0.707<0.870, so the original numbers are ordered 0.078,0.08,0.7,0.707,0.87.
For negative decimals, values farther left on the number line are smaller: −0.8<−0.35. Compare their positive sizes, then reverse the order because both are negative.
More decimal digits do not automatically mean a larger value. 0.707 has three decimal places but is smaller than 0.87.
A terminating decimal has finitely many decimal digits. It can be converted directly to a fraction using a power of 10, or to a percentage by multiplying by 100%.
| Target | Method | Example |
|---|---|---|
| fraction | write the digits over 10, 100, 1000, … according to decimal places, then simplify | 0.72=10072=2518 |
| percentage | multiply the decimal by 100 and attach % | 0.08=8% |
For 0.017, there are three decimal places, so 0.017=100017. The numerator and denominator have no common factor greater than 1.
A decimal below 1 becomes a proper fraction. A decimal such as 0.6 becomes 60%, which is also below 100%.
This conversion method covers terminating decimals here. Do not place a recurring decimal over a guessed power of 10; recurring decimals require the later algebraic method.
A terminating decimal is a fraction because every decimal place is a fractional power-of-ten place. Finite decimal digits therefore form a finite sum of tenths, hundredths, thousandths and so on.
For example, 0.407=104+1000+10007=1000407. This is an exact equality, not an approximation.
| Decimal places | Power-of-ten denominator | Example |
|---|---|---|
| 1 | 10 | 0.6=106=53 |
| 2 | 100 | 0.65=10065=2013 |
| 3 | 1000 | 0.125=1000125=81 |
Simplifying changes the name of the fraction, not the value. Thus 0.65, 10065 and 2013 are the same number.
A displayed rounded decimal may only approximate a value. The claim is exact when the decimal truly terminates at the final shown digit, not when further digits have merely been hidden by rounding.
A recurring decimal repeats the same digit or block forever. Algebra converts it to a fraction by shifting identical recurring tails into alignment and subtracting them away.
| Step | Example x=0.3222… |
|---|---|
| identify one non-recurring digit and one recurring digit | x=0.3222… |
| multiply to place matching recurring tails after the decimal point | 10x=3.2222…, 100x=32.2222… |
| subtract the aligned equations | 100x−10x=32.2222…−3.2222… |
| solve and simplify | 90x=29, so x=9029 |
If the repeating block begins immediately, use x and a power-of-ten multiple. For x=0.4545…, 100x−x=45, so 99x=45 and x=115.
The multiplier must shift by the length of the repeating block, while a second multiplier may be needed to pass any non-recurring digits. The two decimals subtracted must have identical infinite tails.
Do not truncate the recurring decimal before subtracting: 0.3222 is a terminating approximation, whereas 0.3222… is the exact recurring value.