SL 3.1—Three-dimensional geometry
- Syllabus
- First assessment 2021
- Objective
- —
- Level
- SL
In three-dimensional coordinates, a point is (x,y,z). A displacement vector records the change in each coordinate, so distance and direction can be calculated component by component.
For points P and Q, PQ=Q−P and |PQ|=√((Δx)²+(Δy)²+(Δz)²). The midpoint averages corresponding coordinates. These formulas are geometric statements, not just calculator rules.
From P(1,−2,3) to Q(4,2,−1), the displacement is (3,4,−4) and the distance is √41. The sign tells direction; squaring removes it only when measuring length.
Do not drop the z-coordinate or confuse a displacement component with the total distance. Keep units and point order clear when interpreting direction.
The midpoint of P(x1,y1,z1) and Q(x2,y2,z2) is ((x1+x2)/2,(y1+y2)/2,(z1+z2)/2). For solids, use the correct base area and perpendicular height: prism V=Ah, pyramid or cone V=Ah/3, sphere V=4πr3/3; total surface area includes every exposed face. In a cuboid, identify a face diagonal first, then use a second right triangle to obtain a space length or an angle between a line and a plane.