METHOD 1
valid approach
eg x=−2ab
correct working A1
eg −2(3)(−6),x=66
correct answers
eg x=1,y=0;(1,0)
METHOD 2
valid approach
eg f(x)=0, factorisation, completing the square
correct working
eg x2−2x+1=0,(3x−3)(x−1),f(x)=3(x−1)2
correct answers
eg x=1,y=0;(1,0)
METHOD 3
valid approach using derivative
eg f′(x)=0,6x−6
correct equation A1
eg 6x−6=0
correct answers
eg x=1,y=0;(1,0)