Question 1[Maximum number: 2]Let f(x)=cos2xf(x)=\cos 2 xf(x)=cos2x and g(x)=2x2−1g(x)=2 x^{2}-1g(x)=2x2−1.Find (g∘f)(π2)(g \circ f)\left(\frac{\pi}{2}\right)(g∘f)(2π).Mark as masteredShow Answer(g∘f)(π2)=g(−1)(=2(−1)2−1)\quad(g \circ f)\left(\frac{\pi}{2}\right)=g(-1)\left(=2(-1)^{2}-1\right)(g∘f)(2π)=g(−1)(=2(−1)2−1)=1Add to Test