Question 1[Maximum number: 3]Consider the differential equation y dy dx=cos2xy \frac{\mathrm{~d} y}{\mathrm{~d} x}=\cos 2 xy dx dy=cos2x.For which value of the constant of integration does your solution coincide with the function given in part (i)?Mark as masteredShow Answersin2x+A≡(cosx+sinx)2\quad \sin 2 x+A \equiv(\cos x+\sin x)^{2}sin2x+A≡(cosx+sinx)2(cosx+sinx)2=cos2x+2sinxcosx+sin2x(\cos x+\sin x)^{2}=\cos ^{2} x+2 \sin x \cos x+\sin ^{2} x(cosx+sinx)2=cos2x+2sinxcosx+sin2xuse of sin2x≡2sinxcosx\sin 2 x \equiv 2 \sin x \cos xsin2x≡2sinxcosx.A=1Add to Test