IB Maths AA HL 3.13 Scalar product Question Bank
Practise IB Mathematics HL 3.13 by applying scalar product methods to exam-style questions.
- Syllabus
- First assessment 2021
- Course
- Mathematics: analysis and approaches HL
- Level
- HL
Practise IB Mathematics HL 3.13 by applying scalar product methods to exam-style questions.
The following question compares the distance and direction between cities on a flat surface to the distance and direction between cities on a sphere.
Consider a model where the cities of Bogotá, Moscow, and Nairobi lie on a flat surface. In this model, Nairobi is 6000 km due south of Moscow and Bogotá is 12500 km due west of Nairobi, as shown in the following diagram.

Use the scalar product to find the angle between p and n.
Find the shortest distance from Bogotá to Moscow on the sphere.
The bearing from B to M is defined as the angle at vertex B in the spherical triangle containing B, M and P . It is given that b×p=36cos120∘−36sin120∘0.
METHOD 1
EITHER (Scalar product)
attempt to use scalar product to find BÔM =arccos(∣b∣∣m∣b.m)
Note: This may be written as cos( BÔM )=∣b∣∣m∣b.m.
=arccos(62(6cos120∘)(6cos57.3∘))
Note: This (A1) can be awarded for cosθ=626cos120∘×6cos57.3∘.
=106∘(=105.673…∘) OR 1.84 radians (1.84434…)
OR (Cosine Rule)
∣BM∣=(6sin120−0)2+(6cos120−6sin57.3)2+(0−6sin57.3)2=9.56(9.56299…) OR 9560 km
attempt to use the cosine rule to find angle BOM
∣BM∣2=62+62−2×6×6×cosBOMBOM=106∘(=105.673…) OR 1.84 radians (1.84434…)
THEN
attempt to use 360θ×2πr OR s=rθ=360105.671∘×2π×6=11.1(11.0660… thousand km)
Note: Accept an answer of 11100 OR 11066.0… without units (i.e. "km" is implicit).
METHOD 2 (Cross product)
attempt to use cross product to find BÔM =arcsin∣b∣∣m∣∣b×m∣
Note: This may be written as sin BÔM =∣b∣∣m∣∣b×m∣.
Note: Award at most (M1)(A1)(A0)(M1)A0 for an answer of 7.78 thousand km from finding the principal root of the arcsin.
Using the method from part (c), find the bearing from Bogotá to Moscow.
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attempt to calculate b×mb×m=36cos120∘sin57.3∘−36sin120∘sin57.3∘36sin120∘cos57.3∘=−15.1464…−26.2344…16.8449…
attempt to use scalar product to find angle between vectors
Note: Award (A1) for numerator, (A1) for denominator.
Note: Do not penalise absence of degree symbol.
Award full marks for answer in radians =0.507.
Award full marks for 029∘.
Special Case: If a candidate calculates m×b instead of b×m then you can award at most (M1)(A0)(M1)(A1)(A1)A0.