SL 3.8—Trigonometric equations
- Syllabus
- First assessment 2021
- Objective
- —
- Level
- HL
Solve trigonometric equations on a stated interval.
Find a reference angle, use quadrant symmetry, and list only solutions inside the requested interval.
sin x=1/2 on [0,2π] gives x=π/6 and 5π/6.
The interval determines which repeated solutions are included.
A calculator principal value is not the complete interval solution.
Quadratic reduction example on 0≤x≤2π: 2sin2x−3sinx+1=0 factors as (2sinx−1)(sinx−1)=0. Hence sinx=1/2 or sinx=1, giving x=π/6,π/2,5π/6. Check every candidate in the original equation and report only values in the stated finite interval; no general solution is required.