3.1 Translational Kinetic Energy

Syllabus
2024
Topic
3.1
Level

Learning objectives

Kinetic energy depends on speed squared

Connect motion to energy

An object has translational kinetic energy because its center of mass is moving. For an object of mass mm moving with velocity v\vec v, use the speed v=vv=|\vec v| in the kinetic-energy equation.

K=12mv2[K]=J=kgm2/s2\begin{gathered}K=\frac{1}{2}mv^2\\ [K]=\text{J}=\text{kg}\,\text{m}^2/\text{s}^2\end{gathered}

Read the squared-speed relationship

At fixed speed, doubling the mass doubles KK. At fixed mass, doubling the speed makes KK four times as large because velocity magnitude is squared. Reversing the direction of motion without changing speed leaves KK unchanged.

Calculate with units

Worked example: A 2.0kg2.0\,\text{kg} cart moves at 3.0m/s3.0\,\text{m/s} relative to the laboratory.

K=12(2.0kg)(3.0m/s)2=9.0JK=\dfrac12(2.0\,\text{kg})(3.0\,\text{m/s})^2=9.0\,\text{J}.

The cart therefore has 9.0J9.0\,\text{J} of translational kinetic energy in the laboratory frame.

State whose measurement it is

Kinetic energy is a scalar, so it has no direction, but its value depends on the observer's reference frame. An observer moving alongside the cart at 3.0m/s3.0\,\text{m/s} measures the cart's speed as zero and therefore measures K=0K=0, while the laboratory observer measures 9.0J9.0\,\text{J}. Both values are correct in their own frames.