AP Environmental Science 6.8: Solar Power
Practice AP Environmental Science questions on photovoltaic, active solar, passive solar, sunlight availability, and energy storage.
- Syllabus
- Effective Fall 2025
- Course
- AP Environmental Science
Practice AP Environmental Science questions on photovoltaic, active solar, passive solar, sunlight availability, and energy storage.
Increasing global urbanization causes associated problems such as the formation of urban heat islands.
Urban areas are increasingly using solar energy to generate electricity for residences and businesses.
As a result of improved technology, the efficiency of solar panels has changed over time. In 1992 a solar cell had a maximum efficiency of 15.9%. In 2017 a solar cell prototype capable of 44.5% efficiency was produced. Calculate the percent change in efficiency from the 1992 cell to the 2017 cell. Show your work.
As a result of improved technology, the efficiency of solar panels has changed over time. In 1992 a solar cell had a maximum efficiency of 15.9\%. In 2017 a solar cell prototype capable of 44.5\% efficiency was produced. Calculate the percent change in efficiency from the 1992 cell to the 2017 cell. Show your work.
One point for the correct setup (must include multiplication by 100 ) to calculate the percent change:
- 15.9%44.5%−15.9%×100
- (15.9%44.5%−1)×100
1 point
One point for the correct calculation of the percent change:
Accept one of the following:
- 179.9\%
- 180\%
1 point
The roof of a typical house in the United States receives a total of four hours of sunlight per day that can be converted by solar panels into electricity. A house has 30 solar panels on its roof, and each panel generates a maximum output of 300 watts. Calculate how many kWh can be produced by the system at maximum output in one calendar year. Show your work.
One point for the correct setup to calculate the amount of kWh that can be produced at maximum output:
- 30 panels × panel 300 watts ×1,000 watts 1 kW× day 4 hours ×1 year 365 days
One point for the correct calculation of the amount of kWh that can be produced at 1 point maximum output:
- 13,140 kWh per year
Total for part (c)
6 points