1.6 Determining Limits Using Algebraic Manipulation
- Syllabus
- 2020
- Topic
- 1.6
- Level
- —
If direct substitution gives 0/0, the result is indeterminate—not the value of the limit. Rewrite the expression into an equivalent form that is valid for inputs near the target, then evaluate the simpler limit.
| Structure causing 0/0 | Useful rewrite |
|---|---|
| Numerator and denominator share a polynomial factor | Factor, then divide out the common factor |
| A difference involving square roots | Multiply by the appropriate conjugate |
| A trigonometric expression in an unhelpful form | Use an identity to create a recognizable equivalent form |
\begin{aligned}\lim_{x\to3}\frac{x^2-9}{x-3}&=\lim_{x\to3}\frac{(x-3)(x+3)}{x-3}\&=\lim_{x\to3}(x+3)\qquad(x\ne3)\&=6.\end{aligned}
The original quotient is undefined at x=3, but for every nearby input with x=3 it equals x+3. Because a limit uses nearby behavior rather than the value at the point, both expressions have the same limit as x approaches 3.
Cancel only common factors, not separate terms in a sum or difference. After rewriting, check that the new expression is genuinely equal to the original for all sufficiently close inputs except possibly the target itself. The squeeze theorem is a separate method developed in Topic 1.8.