1.6 Determining Limits Using Algebraic Manipulation

Syllabus
2020
Topic
1.6
Level

Rewriting an Expression to Reveal Its Limit

If direct substitution gives 0/00/0, the result is indeterminate—not the value of the limit. Rewrite the expression into an equivalent form that is valid for inputs near the target, then evaluate the simpler limit.

Structure causing 0/00/0 Useful rewrite
Numerator and denominator share a polynomial factor Factor, then divide out the common factor
A difference involving square roots Multiply by the appropriate conjugate
A trigonometric expression in an unhelpful form Use an identity to create a recognizable equivalent form

\begin{aligned}\lim_{x\to3}\frac{x^2-9}{x-3}&=\lim_{x\to3}\frac{(x-3)(x+3)}{x-3}\&=\lim_{x\to3}(x+3)\qquad(x\ne3)\&=6.\end{aligned}

The original quotient is undefined at x=3x=3, but for every nearby input with x3x\ne3 it equals x+3x+3. Because a limit uses nearby behavior rather than the value at the point, both expressions have the same limit as xx approaches 33.

Cancel only common factors, not separate terms in a sum or difference. After rewriting, check that the new expression is genuinely equal to the original for all sufficiently close inputs except possibly the target itself. The squeeze theorem is a separate method developed in Topic 1.8.