2.8 The Product Rule

Syllabus
2020
Topic
2.8
Level

Differentiate a Product of Two Functions

For a product y=u(x)v(x)y=u(x)v(x), the derivative has two contributions: first let uu change while vv stays as it is, then let vv change while uu stays as it is.

\frac{d}{dx}[u(x)v(x)]=u'(x)v(x)+u(x)v'(x)

  1. Label the factors uu and vv.
  2. Find uu' and vv' separately.
  3. Form uv+uvu'v+uv', keeping one original factor in each term.
  4. Simplify or factor only after both terms are present.

For y=x2exy=x^2e^x, take u=x2u=x^2 and v=exv=e^x, so u=2xu'=2x and v=exv'=e^x. Then y=(2x)ex+x2(ex)=ex(x2+2x).y'=(2x)e^x+x^2(e^x)=e^x(x^2+2x). Both terms are needed because both factors vary with xx.

In general, (uv)uv(uv)'\ne u'v'. If one factor is a true constant, its derivative contribution is zero and the product rule reduces to the constant-multiple rule.