AP Calculus AB 6.9 Substitution Review
Review AP Calculus AB 6.9 by choosing a useful substitution, changing the differential correctly, and simplifying the resulting integral.
- Syllabus
- Effective Fall 2025
- Course
- AP Calculus AB
Review AP Calculus AB 6.9 by choosing a useful substitution, changing the differential correctly, and simplifying the resulting integral.
∫01x2+1xdx is equal to
4π
ln2
21(ln2−1)
ln2
B