P4.4 - Binomial expansion
- Syllabus
- 2019
- Topic
- P4.4
- Level
- A2
The binomial series expands a rational power around x=0. Put the expression into the standard form (1+u)n first; the coefficients come from the descending products of n, while the size of u controls where a non-terminating series is valid.
(1+u)n=1+nu+2!n(n−1)u2+3!n(n−1)(n−2)u3+⋯
Rewrite (ax+b)n=bn(1+bax)n. For a negative or non-integer rational n, require bax<1, so ∣x∣<∣b/a∣. A non-negative integer power terminates and does not need this convergence restriction.
For (4+5x)1/2, take out 41/2=2 and use u=5x/4: 2(1+21u−81u2+161u3+⋯)=2+45x−6425x2+512125x3+⋯. This series is valid for ∣5x/4∣<1, or ∣x∣<4/5.
For a rational function, decompose first and expand each simple fraction. For example, 1−2x2+4+x3=2(1−2x)−1+43(1+x/4)−1 =411+1661x+64515x2+⋯. The two component ranges are ∣x∣<1/2 and ∣x∣<4, so the combined expansion requires the narrower condition ∣x∣<1/2.
Keep the extracted factor bn outside the series, substitute the whole expression for u into every power, and state the range in terms of x. A finite truncation is an approximation within that range; it is not an identity equal to the original function for every x.