Topic 10: Organic Chemistry AS: Halogenoalkanes, Alcohols and Spectra

Syllabus
2017
Topic
Level
AS

Learning objectives

10.1Classify reactions (including those in Unit 1) as addition, elimination, substitution, oxidation, reduction, hydrolysis orBe able to classify reactions (including those in Unit 1) as addition, elimination, substitution, oxidation, reduction, hydrolysis or polymerisation10.2The concept of a reaction mechanismUnderstand the concept of a reaction mechanism10.3Heterolytic bond breaking results in species that are electrophiles or nucleophilesUnderstand that heterolytic bond breaking results in species that are electrophiles or nucleophiles10.4The definition of the term ‘nucleophile’Know the definition of the term ‘nucleophile’10.5The link between bond polarity and the type of reaction mechanism a compound will undergo 10B: Halogenoalkanes Students willUnderstand the link between bond polarity and the type of reaction mechanism a compound will undergo 10B: Halogenoalkanes Students will be assessed on their ability to:10.6The nomenclature of halogenoalkanesUnderstand the nomenclature of halogenoalkanes and be able to draw their structural, displayed and skeletal formulae10.7The distinction between primary, secondary and tertiary halogenoalkanesUnderstand the distinction between primary, secondary and tertiary halogenoalkanes10.8The reactions of halogenoalkanes with: i aqueous alkaliUnderstand the reactions of halogenoalkanes with: i aqueous alkali, including KOH(aq) to produce alcohols (where the hydroxide ion acts as a nucleophile) ii ethanolic potassium hydroxide to produce alkenes by an elimination reaction (where the hydroxide ion acts as a base) iii aqueous silver nitrate in ethanol (where water acts as a nucleophile) iv alcoholic ammonia under pressure to produce amines (where the ammonia acts as a nucleophile) v alcoholic potassium cyanide to produce nitriles (where the cyanide ion acts as a nucleophile) Students should know this is an example of increasing the length of the carbon chain.10.9The mechanisms of the nucleophilic substitution reactions between primary halogenoalkanes and: i aqueous potassium hydroxideUnderstand the mechanisms of the nucleophilic substitution reactions between primary halogenoalkanes and: i aqueous potassium hydroxide ii ammonia SN1 and SN2 substitution mechanisms will be tested in Unit 4.10.10Experimental observations and data can be used to compare the relative rates of hydrolysis of: i primary, secondaryUnderstand that experimental observations and data can be used to compare the relative rates of hydrolysis of: i primary, secondary and tertiary structural isomers of a halogenoalkane ii primary chloro-, bromo- and iodoalkanes using aqueous silver nitrate in ethanol10.11CORE PRACTICAL 5 Investigation of the rates of hydrolysis of some halogenoalkanesCORE PRACTICAL 5 Investigation of the rates of hydrolysis of some halogenoalkanes.10.12The trend in reactivity of primary, secondary and tertiary halogenoalkanesKnow the trend in reactivity of primary, secondary and tertiary halogenoalkanes10.13Understand, in terms of bond enthalpy, the trend in reactivity of chloro-, bromo- and iodoalkanesUnderstand, in terms of bond enthalpy, the trend in reactivity of chloro-, bromo- and iodoalkanes10.14CORE PRACTICAL 6 Chlorination of 2-methylpropan-2-ol with concentrated hydrochloric acidCORE PRACTICAL 6 Chlorination of 2-methylpropan-2-ol with concentrated hydrochloric acid.10.15The nomenclature of alcoholsUnderstand the nomenclature of alcohols and be able to draw their structural, displayed and skeletal formulae10.16The distinction between primary, secondary and tertiary alcoholsUnderstand the distinction between primary, secondary and tertiary alcohols10.17The reactions of alcohols with: i oxygen in air (combustion) ii halogenating agents • PCl5 to produce chloroalkanesUnderstand the reactions of alcohols with: i oxygen in air (combustion) ii halogenating agents • PCl5 to produce chloroalkanes (including its use as a qualitative test for the presence of the –OH group) • 50% concentrated sulfuric acid and potassium bromide to produce bromoalkanes • red phosphorus and iodine to produce iodoalkanes iii concentrated phosphoric acid to form alkenes by elimination Descriptions of the mechanisms of these reactions are not required.10.18Potassium dichromate(VI) in dilute sulfuric acid can oxidise: i primary alcohols to produce aldehydes (which give a positiveUnderstand that potassium dichromate(VI) in dilute sulfuric acid can oxidise: i primary alcohols to produce aldehydes (which give a positive result with Benedict’s or Fehling’s solution) if the product is distilled as it forms ii primary alcohols to produce carboxylic acids (which give a positive result with sodium carbonate or sodium hydrogencarbonate) if the reagents are heated under reflux iii secondary alcohols to produce ketones In equations, the oxidising agent can be represented by [O].10.19Understand, the following techniques in the preparation and purification of a liquid organic compound: i heating underUnderstand, the following techniques in the preparation and purification of a liquid organic compound: i heating under reflux ii extraction with a solvent using a separating funnel iii distillation iv drying with an anhydrous salt v boiling temperature determination10.20CORE PRACTICAL 7 The oxidation of propan-1-ol to produce propanal and propanoic acidCORE PRACTICAL 7 The oxidation of propan-1-ol to produce propanal and propanoic acid.10.21Interpret data from mass spectra to suggest possible structures of simple organic compounds using the m/z of the molecularBe able to interpret data from mass spectra to suggest possible structures of simple organic compounds using the m/z of the molecular ion and fragmentation patterns10.22Infrared spectra, or data from infrared spectra, to deduce functional groups present in organic compounds, and predictBe able to use infrared spectra, or data from infrared spectra, to deduce functional groups present in organic compounds, and predict infrared absorptions, given wavenumber data, due to familiar functional groups including: i C–H stretching absorptions in alkanes, alkenes and aldehydes ii C=C stretching absorption in alkenes iii O–H stretching absorptions in alcohols and carboxylic acids iv C=O stretching absorptions in aldehydes, ketones and carboxylic acids v C–X stretching absorption in halogenoalkanes vi N-H stretching absorption in amines10.23CORE PRACTICAL 8 Analysis of some inorganic and organic unknownsCORE PRACTICAL 8 Analysis of some inorganic and organic unknowns.

Classify organic reactions by the bond change

Class Recognising change
addition two species add across a multiple bond to form one main product
elimination atoms/groups are removed and a multiple bond forms
substitution one atom/group is replaced by another
oxidation oxygen gained or hydrogen lost
reduction hydrogen gained or oxygen lost
hydrolysis a bond is split by reaction with water or aqueous reagent
polymerisation many monomers join into a long-chain molecule

Compare reactant and product connectivity, identify bonds broken and formed, and classify the specified step. Conditions help distinguish competition: aqueous KOH favours substitution/hydrolysis, while ethanolic KOH with heat favours elimination.

A reagent name alone does not determine class. The same OH^- reagent can substitute or eliminate depending on solvent and temperature.

A mechanism is an electron-by-electron reaction pathway

A reaction mechanism is a sequence of elementary steps showing how reactants become products, including bond breaking/forming, intermediates and movement of electron pairs.

Feature Meaning
full curly arrow movement of an electron pair from a bond or lone pair
intermediate formed in one step and consumed in a later step
overall equation sum of steps after intermediates cancel

Every curly arrow starts at an electron pair and ends where a new bond or lone pair forms. Atom count and total charge must be conserved through every step.

A mechanism is not just the balanced overall equation or a list of conditions; it explains the electron movements that connect them.

Heterolytic fission creates electron-poor and electron-rich species

In heterolytic bond breaking, both bonding electrons move to one atom. A full curly arrow runs from the bond to that atom, producing oppositely charged species.

For Cδ+^{\delta+}–Brδ^{\delta-}, both C–Br electrons move to bromine. Br^- is electron-rich and can act as a nucleophile; the electron-deficient carbon species can be attacked by a nucleophile and is electrophilic.

Bond polarity makes one heterolytic direction more plausible: the more electronegative atom takes the pair, stabilising negative charge, while the other centre becomes electron-deficient.

Heterolysis moves a pair and forms ions. Homolysis splits the pair one electron each and forms radicals.

A nucleophile donates an electron pair

A nucleophile is an electron-pair donor that forms a covalent bond to an electron-deficient atom.

Nucleophile Donating pair Typical use
OH^- oxygen lone pair forms alcohol from a halogenoalkane
NH3_3 nitrogen lone pair forms an amine
CN^- carbon lone pair/electron pair forms a nitrile and extends the chain
H2_2O oxygen lone pair hydrolyses a halogenoalkane

Draw the curly arrow from the actual lone pair (or the atom bearing it) to the δ+\delta+ carbon. The nucleophile is attracted by charge but defined by pair donation.

A nucleophile is not simply a negative ion: neutral NH3_3 and H2_2O are nucleophiles because they donate lone pairs.

Bond polarity selects the attacking reagent and mechanism

Electronegativity differences create partial charges. An electron-rich nucleophile attacks a δ+\delta+ centre, while an electrophile accepts electron density from an electron-rich bond or lone pair.

Polar feature Vulnerable site Likely mechanism
Cδ+^{\delta+}–Xδ^{\delta-} in a halogenoalkane carbon attached to X nucleophilic substitution
Hδ+^{\delta+}–Brδ^{\delta-} plus alkene π\pi bond Hδ+^{\delta+} attacked by π\pi electrons electrophilic addition
polar C=O carbonyl carbon δ+\delta+ nucleophilic attack in later organic chemistry

Mark the relevant dipole, identify the electron-pair donor and acceptor, then start each curly arrow at the donor pair. Bond strength and reaction conditions still affect whether the predicted route is fast or favoured.

Polarity identifies a likely attack site, but does not alone determine rate; bond enthalpy, steric environment, solvent and pathway also matter.

Halogenoalkane names use halo prefixes and locants

Choose the longest carbon chain, number it to give substituents the lowest set of locants, name F/Cl/Br/I as fluoro-, chloro-, bromo- and iodo-, alphabetise different prefixes, and use di-, tri- or tetra- for repeats.

Structural formula IUPAC name
CH3_3CH2_2CH2_2Br 1-bromopropane
CH3_3CHBrCH3_3 2-bromopropane
CH3_3CCl(CH3_3)CH2_2CH3_3 2-chloro-2-methylbutane
(CH3_3)3_3CCN 2,2-dimethylpropanenitrile; the C of C\equivN is C1

A structural formula groups connected atoms; a displayed formula shows every atom and bond; a skeletal formula uses vertices/line ends for carbon and omits attached C–H bonds while showing halogen symbols.

Number the parent chain, not the drawing direction. Reversing a sketch must not create a different name.

Halogenoalkane class depends on the carbon bonded to X

Class Carbon groups attached to the C–X carbon Example
primary, 1° one CH3_3CH2_2Br
secondary, 2° two CH3_3CHBrCH3_3
tertiary, 3° three (CH3_3)3_3CCl

Locate the carbon directly bonded to the halogen, ignore the halogen and any hydrogens, then count how many other carbon atoms are directly attached to that carbon.

Do not classify from the total number of carbons or the halogen type. 1-chloro-2-methylpropane is primary because its C–Cl carbon touches only one carbon.

Solvent and reagent switch halogenoalkane products

Reagent/conditions Role Product/equation pattern
aqueous KOH, warm/reflux OH^- nucleophile RX+OH^-$\rightarrowROH+XROH+X^-$
ethanolic KOH, heat OH^- base eliminates HX to form alkene + H2_2O + X^-
AgNO3_3(aq) in ethanol, warm H2_2O nucleophile; Ag+^+ traps X^- alcohol plus AgX precipitate
excess alcoholic NH3_3, heat under pressure NH3_3 nucleophile primary amine; ammonium halide by-product
alcoholic KCN, reflux CN^- nucleophile RCN+X^-; carbon chain gains one carbon

For an unsymmetrical secondary halogenoalkane, elimination can remove H from either adjacent carbon and may give positional and E/Z alkene products. Aqueous conditions instead favour alcohol formation.

CN^- attaches through carbon to form R–C\equivN. Counting the nitrile carbon explains why the product chain is one carbon longer.

Primary halogenoalkanes undergo nucleophilic substitution

For R–X + OH^-, mark Cδ+^{\delta+}–Xδ^{\delta-}. Draw a curly arrow from the O lone pair to the C–X carbon and another from the C–X bond to X. The one-step substitution gives ROH and X^-.

Step Electron movement/result
attack/substitution NH3_3 lone pair attacks the C–X carbon while C–X electrons move to X, forming RNH3+_3^+ and X^-
deprotonation a second NH3_3 molecule uses its lone pair to remove H+^+; the N–H bond pair returns to N
products RNH2_2 and NH4+_4^+X^-

Use excess ammonia to favour the primary amine and reduce further substitution. Full curly arrows start at lone pairs or bonds and all dipoles, charges and leaving groups must be shown.

Do not use radical half-arrows. These nucleophilic substitutions move electron pairs; detailed SN1/SN2 comparison belongs to Unit 4.

Silver-halide timing compares hydrolysis rates

In aqueous silver nitrate/ethanol, the halogenoalkane hydrolyses and released X^- forms AgX. Shorter time to the first comparable cloudiness or precipitate means faster hydrolysis.

Controlled series Expected rate/observation Main comparison
primary, secondary, tertiary structural isomers with same X tertiary precipitates first, then secondary, then primary carbon environment
primary RCl, RBr, RI with same R RI first, then RBr, then RCl C–X bond strength

Use equal halogenoalkane amounts, identical AgNO3_3/ethanol volumes and concentrations, the same water-bath temperature, simultaneous mixing and one objective endpoint. Ethanol helps the organic reagent mix with aqueous solution.

Precipitate colour identifies X (AgCl white, AgBr cream, AgI yellow); appearance time compares rate. Do not confuse these two observations.

Core Practical 5 measures halogenoalkane hydrolysis

Stage Action
equilibrate place equal ethanol/aqueous AgNO3_3 mixtures in labelled tubes in a constant-temperature water bath
initiate add equal drops/volumes of each halogenoalkane, stopper or mix consistently and start timing
endpoint record time to first permanent cloudiness/precipitate against the same background
repeat repeat trials and compare mean times or relative rates 1/t1/t

Independent variable is halogenoalkane structure or halogen; dependent variable is precipitation time. Control temperature, reagent concentrations/volumes, total volume, mixing, drop size and endpoint judgement.

Use a water bath rather than a flame because ethanol and many halogenoalkanes are volatile and flammable; minimise quantities, avoid inhalation and dispose of silver/halogenated waste appropriately.

AgX forms after hydrolysis releases halide. Silver nitrate does not directly measure disappearance of the intact C–X molecule.

Hydrolysis reactivity rises primary < secondary < tertiary

For structural isomers of the same halogenoalkane under the specified hydrolysis conditions, reactivity generally increases primary < secondary < tertiary.

The tertiary isomer gives the silver-halide precipitate first, the secondary next and the primary last when concentration, halogen, temperature and mixing are controlled.

This is the empirical AS trend for these hydrolysis conditions. Later SN1/SN2 study explains why mechanism and solvent can alter structural effects; here, use the observed order without claiming every nucleophilic substitution follows it.

Keep halogen identity constant when testing the structural trend. A primary iodoalkane may out-react a tertiary chloroalkane because two variables changed.

C–X bond enthalpy controls the halogen trend

Bond Relative bond enthalpy Hydrolysis reactivity
C–Cl highest/strongest slowest
C–Br intermediate intermediate
C–I lowest/weakest fastest

Hydrolysis requires C–X bond breaking. Less energy is needed to break C–I than C–Br or C–Cl, so otherwise comparable iodoalkanes react fastest: RCl < RBr < RI.

In the silver nitrate test, AgI appears first, AgBr next and AgCl last for matched primary compounds. Precipitate colour separately confirms the halide.

Bond polarity alone would predict C–Cl as highly susceptible, but the larger C–Cl bond enthalpy makes it slower. Rate depends on the barrier, not just partial charge.

Core Practical 6 prepares 2-chloro-2-methylpropane

2-methylpropan-2-ol reacts with concentrated hydrochloric acid to form 2-chloro-2-methylpropane and water: (CH3_3)3_3COH+HCl\rightarrow(CH3_3)3_3CCl+H2_2O.

Stage Action/purpose
react mix the alcohol and concentrated HCl carefully, shake with regular venting and allow layers to separate
separate/wash retain the organic product layer; wash to remove acid, venting CO2_2 if hydrogencarbonate is used
dry add an anhydrous drying agent until the liquid is clear and some solid remains free-flowing
purify decant/filter and distil, collecting the fraction near the product boiling temperature

Identify layers by density or a drop test rather than assuming top/bottom, minimise transfer losses, and assess purity from a narrow boiling range. Concentrated HCl is corrosive and the product is volatile/flammable: use ventilation and no flame.

The separating funnel must be vented away from people. A sealed funnel can build pressure during shaking or bicarbonate washing.

Alcohol names give the –OH group priority

Choose the longest chain containing the carbon bonded to –OH. Number from the end giving –OH the lowest locant, replace the alkane -e with -ol, and then add and alphabetise substituent prefixes.

Formula Name
CH3_3CH2_2OH ethanol
CH3_3CH(OH)CH3_3 propan-2-ol
(CH3_3)2_2CHCH2_2OH 2-methylpropan-1-ol
(CH3_3)3_3COH 2-methylpropan-2-ol

Structural formulae show connectivity, displayed formulae show every bond, and skeletal formulae show carbon vertices while the O and H of –OH must be written explicitly.

Numbering gives –OH priority over alkyl substituents. A lower methyl locant does not justify a higher –OH locant.

Alcohol class depends on the carbon bearing –OH

Class Carbon groups attached to the C–OH carbon Example
primary, 1° one propan-1-ol
secondary, 2° two propan-2-ol
tertiary, 3° three 2-methylpropan-2-ol

Locate the carbon directly bonded to oxygen in –OH, then count the other carbons directly bonded to that carbon. Hydrogens and the O atom are not counted as carbon groups.

Classification predicts oxidation: primary alcohols form aldehydes/acids, secondary form ketones, and tertiary alcohols resist oxidation under ordinary acidified dichromate conditions.

Do not classify by where –OH appears on the page or by total chain branching. Inspect only the immediate C–OH carbon.

Alcohols combust, substitute and eliminate under distinct conditions

Reagent/condition Product/evidence
O2_2, ignition complete combustion gives CO2_2+H2_2O
PCl5_5 RCl+POCl3_3+HCl; steamy HCl fumes support an –OH group in dry conditions
KBr + 50% concentrated H2_2SO4_4 HBr forms in situ and converts ROH to RBr+H2_2O
red phosphorus + iodine PI3_3 forms in situ and converts ROH to RI
concentrated H3_3PO4_4, heat elimination/dehydration gives alkene+H2_2O

For ethanol combustion: C2_2H5_5OH+3O2_2$\rightarrow2CO2CO_2+3H+3H_2O.Fordehydration:CHO. For dehydration: CH_3CHCH_2OHOH\rightarrowCHCH_2=CH=CH_2+H+H_2$O.

Know reagents, conditions, products and observations; mechanisms for these alcohol reactions are not required here.

PCl5_5 also reacts with water to release HCl. Use dry apparatus/sample before interpreting steamy fumes as evidence for an alcohol –OH group.

Distillation or reflux controls primary-alcohol oxidation

Alcohol/conditions with acidified K2_2Cr2_2O7_7 Organic product Confirmation
primary; distil product as it forms aldehyde Benedict's/Fehling's gives brick-red Cu2_2O precipitate
primary; excess oxidant, heat under reflux carboxylic acid carbonate/hydrogencarbonate gives CO2_2 effervescence
secondary; heat ketone orange dichromate turns green but aldehyde tests are negative
tertiary no reaction under these conditions dichromate remains orange

CH3_3CH2_2CH2_2OH+[O]\rightarrowCH3_3CH2_2CHO+H2_2O; then CH3_3CH2_2CHO+[O]\rightarrowCH3_3CH2_2COOH. Propan-2-ol+[O]\rightarrowpropanone+H2_2O.

Distillation removes the volatile aldehyde before further oxidation. Reflux returns vapour for sustained contact with excess oxidant, favouring the acid.

The orange-to-green change shows dichromate reduction, but does not alone distinguish aldehyde, acid or ketone. Product conditions and confirmatory tests do.

Five techniques prepare and purify organic liquids

Technique Correct purpose and key feature
reflux heat reaction for long time under vertical condenser; vapour condenses and returns
solvent extraction shake immiscible layers in separating funnel, vent, allow separation, identify and drain layers
distillation separate/collect volatile product; thermometer bulb at still-head sidearm and condenser water enters lower port
drying add anhydrous salt to organic layer until liquid clears and solid stays free-flowing, then remove solid
boiling-temperature determination collect/measure a narrow stable range and compare with expected value as purity evidence

A typical preparation uses reflux or controlled distillation for reaction, separating-funnel washes/extraction, drying of the retained organic layer, then final distillation to collect the boiling fraction.

Never seal a heated/distillation system, add anti-bumping granules before heating, vent a separating funnel away from people, and use non-flame heating for flammable liquids.

A separating funnel separates immiscible liquid layers; a filter separates solid from liquid. Drying agent must be removed before final distillation.

Core Practical 7 makes propanal or propanoic acid

Target Apparatus/conditions Reason
propanal warm propan-1-ol with acidified dichromate and distil product as it forms volatile aldehyde is removed before further oxidation
propanoic acid heat propan-1-ol with excess acidified dichromate under reflux, then distil/purify repeated contact allows complete oxidation

Use anti-bumping granules and controlled addition/heating. For propanal, a sealed-left/open-receiver distillation setup has a correctly placed thermometer and downward condenser with water in at the bottom; collect the appropriate boiling fraction.

Dichromate changes orange to green. Confirm propanal with Benedict's/Fehling's brick-red precipitate and propanoic acid by CO2_2 effervescence with carbonate/hydrogencarbonate; boiling range supports purity.

Acidified dichromate(VI) is toxic/oxidising and sulfuric acid corrosive; use small scale, eye protection and suitable waste. Organic vapours are flammable, so avoid naked flames.

Reflux and distillation are not interchangeable: reflux retains volatile material; distillation deliberately removes and collects it.

Mass spectra combine molecular mass and diagnostic fragments

For a singly charged ion, m/zm/z equals its relative ionic mass. The molecular-ion peak M+^{+\boldsymbol{\cdot}} gives the molecular relative mass; fragment peaks arise when it breaks, and the base peak is the most intense ion.

Step Inference
locate plausible molecular ion constrain molecular formula/Mr_r
calculate mass differences suggest neutral losses or bond cleavages
assign fragment formulae with charge test carbon count, functional group and connectivity
compare all major peaks reject structures that cannot produce the pattern

For C3_3H8_8O with M+^+ at 60, a strong m/z=31m/z=31 ion such as CH2_2OH+^+ supports propan-1-ol, while a strong m/z=45m/z=45 fragment supports cleavage patterns of propan-2-ol. The same molecular ion alone cannot distinguish isomers.

The highest-m/zm/z visible peak is not automatically M+^+ if it is an isotope peak or impurity. Use formula plausibility and the whole pattern.

IR absorptions identify bonds, then functional groups

Bond/group Typical diagnostic region / cm1^{-1} Shape/context
alkane C–H 2850–3000 several stretches
alkene =C–H just above 3000, about 3010–3100 with possible C=C
aldehyde C–H about 2700–2900 often weak pair with C=O
C=C about 1620–1680 may be weak
alcohol O–H about 3230–3550 broad
carboxylic-acid O–H about 2500–3300 very broad, with C=O
C=O about 1680–1750 strong
C–X fingerprint region, roughly 500–800 use supplied X data
N–H about 3300–3500 one or more sharper bands

Use the supplied wavenumber table, identify strong/broad diagnostic absorptions, combine features into functional groups, and use meaningful absences to eliminate candidates. Predict a spectrum by listing every characteristic bond in the structure.

Broad alcohol O–H without C=O supports an alcohol; very broad acid O–H plus strong C=O supports a carboxylic acid; strong C=O without O–H could be an aldehyde or ketone and needs C–H/mass evidence.

One absorption rarely proves a whole structure, and fingerprint-region peaks overlap. Combine IR with molecular formula, mass fragments and chemical tests.

Core Practical 8 identifies unknowns by converging tests

Stage Evidence route
initial record state, colour, solubility and pH on small separate portions
inorganic cation flame test where appropriate; warm with NaOH for NH4+_4^+
inorganic anion acid/CO2_2 test for carbonate, acidified Ba2+^{2+} for sulfate, acidified AgNO3_3 for halides
organic functional group bromine water for C=C; dry PCl5_5 for –OH; acidified dichromate and product tests for alcohol class; carbonate for carboxylic acid
instrumental combine IR functional groups with molecular-ion and fragment m/zm/z evidence

Plan a branching sequence so one test does not contaminate the next, use fresh portions and blanks, record reagent/condition/observation, and require at least two compatible pieces of evidence before naming an unknown.

Risk-assess corrosive acids/alkalis, oxidising dichromate, volatile organics and silver waste; work microscale with ventilation and segregated disposal.

A negative result is informative only if the reagent and conditions were valid. Do not identify a complete molecule from one colour change or one IR band.