2.4.1—Hyperbolic functions
- Syllabus
- 9231–2028–2029
- Objective
- 2.4.1
- Level
- A2
Use cosh²x−sinh²x=1, 1−tanh²x=sech²x and coth²x−1=csch²x to replace a difficult power or quotient by a form with a known derivative.
Choose the identity that leaves a differential factor. For even powers, separate one factor when integrating; for equations, isolate a single hyperbolic function before applying an inverse.
∫sinh²x dx can use sinh²x=(cosh2x−1)/2, giving a sum of an elementary term and a linear term in x.
The sign in cosh²−sinh² is opposite to the circular identity, and applying an identity without preserving the differential can make the integral harder.