28.2 Chemical properties of first-row transition elements
- Syllabus
- 9701–2028–2029
- Topic
- 28.2
- Level
- A2
A ligand forms a complex by donating a lone pair into an accessible orbital on Cu²⁺ or Co²⁺. Ligand size, charge and number determine the product formula, charge, coordination number and geometry.
| Ligand around M²⁺ (M = Cu or Co) | Representative complex | Coordination / geometry |
|---|---|---|
| H₂O | [M(H₂O)₆]²⁺ | 6 / octahedral |
| NH₃ | [M(NH₃)₆]²⁺; Cu commonly [Cu(NH₃)₄(H₂O)₂]²⁺ in aqueous excess NH₃ | 6 / octahedral |
| OH⁻ with water | [M(H₂O)₄(OH)₂] | 6 / octahedral precipitate |
| Cl⁻ in concentrated chloride | [MCl₄]²⁻ | 4 / tetrahedral |
For each product, conserve the metal and ligands and add charges algebraically. Neutral H₂O/NH₃ retain the metal's +2 overall charge; two OH⁻ give a neutral complex; four Cl⁻ give an overall 2− charge.
Complex formation is coordinate bonding, not necessarily redox. Changing ligand or colour does not by itself change the metal oxidation state.
A ligand is a species containing a lone pair of electrons that forms a dative covalent bond to a central metal atom or ion. The donor atom is the ligand atom directly bonded to the metal.
| Ligand | Donor atom | Ligand charge |
|---|---|---|
| H₂O | O | 0 |
| NH₃ | N | 0 |
| Cl⁻ | Cl | −1 |
| CN⁻ | usually C in the standard cyanido complex | −1 |
A counter-ion outside the coordination sphere is not a ligand unless it directly donates a lone pair to the metal. In the dative bond, both bonding electrons originate from the ligand, not the metal.
| Term | Donor atoms used by one ligand | Required examples |
|---|---|---|
| monodentate | 1 | H₂O, NH₃, Cl⁻, CN⁻ |
| bidentate | 2 | 1,2-diaminoethane (en), H₂NCH₂CH₂NH₂; ethanedioate, C₂O₄²⁻ |
| polydentate | several | EDTA⁴⁻, commonly hexadentate |
Three bidentate en ligands provide six donor atoms, so [M(en)₃]ⁿ⁺ has coordination number 6 even though only three ligand molecules are present.
Denticity is neither ligand charge nor the number of ligand molecules in a formula. Count how many atoms of one ligand actually bind to the same metal centre.
A complex is a molecule or ion formed by a central metal atom or ion surrounded by one or more ligands. The metal–ligand links are dative covalent bonds.
| Formula feature | Meaning in [CoCl₄]²⁻ |
|---|---|
| central metal | Co |
| ligands inside brackets | four Cl⁻ |
| overall complex charge | 2− |
| ions outside brackets in a salt | counter-ions, not part of the complex |
A complex can be neutral or charged. Coordination number is based on directly bonded donor atoms and is not automatically the number of written ligand molecules when ligands are polydentate.
| Geometry | Coordination number | Characteristic bond angle(s) | Example |
|---|---|---|---|
| linear | 2 | 180° | [Ag(NH₃)₂]⁺ |
| square planar | 4 | 90° adjacent; 180° opposite | [PtCl₄]²⁻ |
| tetrahedral | 4 | 109.5° | [CoCl₄]²⁻ |
| octahedral | 6 | 90° adjacent; 180° opposite | [Co(H₂O)₆]²⁺ |
First count coordinated donor atoms, then use the identity of the stated complex: coordination number 4 can be either tetrahedral or square planar, so donor count alone does not decide between them.
Do not infer shape from the complex charge. Real complexes may be distorted, but use the named ideal geometry and its ideal angles unless the question supplies a distortion.
Coordination number is the number of dative covalent bonds from ligand donor atoms to the central metal atom or ion. Complex charge equals metal oxidation state plus the charges on all coordinated ligands.
| Step | Question to answer |
|---|---|
| 1 | What is the metal symbol and oxidation state? |
| 2 | What ligand and denticity are given? |
| 3 | How many ligand molecules supply the required coordination number? |
| 4 | What is metal charge + total ligand charge? |
| 5 | Put the whole coordination entity in brackets and write that charge outside. |
M²⁺ with coordination number 4 and four neutral NH₃ ligands gives [M(NH₃)₄]²⁺. M³⁺ with coordination number 4 and two bidentate C₂O₄²⁻ ligands gives [M(C₂O₄)₂]⁻ because +3 + 2(−2) = −1.
Oxidation state and overall complex charge are different quantities, and the number of ligand molecules is not the coordination number for bidentate or polydentate ligands.
[M(HX2O)X6]X2++2OHX−[M(HX2O)X4(OH)X2](s)+2HX2O(M=Cu,Co)
[Cu(HX2O)X6]X2++4NHX3[Cu(NHX3)X4(HX2O)X2]X2++4HX2O
[M(HX2O)X6]X2++4ClX−[MClX4]X2−+6HX2O(M=Cu,Co)
| Change | Cu(II) observation | Co(II) observation |
|---|---|---|
| hexaaqua + OH⁻ | blue solution → pale-blue precipitate | pink solution → blue precipitate |
| excess NH₃ | deep-blue ammine solution after the initial precipitate | ammine solution; subsequent air oxidation can alter the colour and oxidation state |
| concentrated Cl⁻ | blue/yellow species can appear green as an equilibrium mixture | pink → blue |
| add water after concentrated Cl⁻ | shifts back toward the hexaaqua complex | shifts back toward pink hexaaqua complex |
Exchange occurs when an entering ligand donates a lone pair and replaces one or more existing ligands. Larger Cl⁻ favours four-coordinate tetrahedral products, whereas small H₂O/NH₃ commonly give six-coordinate octahedral environments.
Keep ligand exchange separate from subsequent redox: Co(II) ammine species can be oxidised by air, but that oxidation is not itself the substitution step.
Ecell∘=Ereduction∘−Eoxidation∘
| Step | Action |
|---|---|
| 1 | write both data-book half-equations as reductions |
| 2 | choose the more positive E° half-equation to remain as reduction |
| 3 | reverse the other half-equation to give oxidation |
| 4 | calculate E°cell without multiplying E° values by stoichiometric coefficients |
| 5 | E°cell > 0 predicts feasibility in the written direction under standard conditions |
For Fe³⁺/Fe²⁺, +0.77 V, and Cu²⁺/Cu⁺, +0.15 V: Fe³⁺ is reduced and Cu⁺ is oxidised, so E°cell = 0.77 − 0.15 = +0.62 V.
A positive E°cell is a thermodynamic standard-condition prediction, not a guarantee of an observable rate. Activation energy, concentration and non-standard conditions can change what is observed.
2MnOX4X−+5CX2OX4X2−+16HX+2MnX2++10COX2+8HX2O
MnOX4X−+5FeX2++8HX+MnX2++5FeX3++4HX2O
2CuX2++4IX−2CuI(s)+IX2
| System | Electron / reacting ratio used in calculations | Key observation or follow-up |
|---|---|---|
| MnO₄⁻ : C₂O₄²⁻ in acid | 2 : 5 | Mn²⁺ product autocatalyses; warm reaction initially |
| MnO₄⁻ : Fe²⁺ in acid | 1 : 5 | first permanent pale pink marks slight MnO₄⁻ excess |
| Cu²⁺ : I⁻ | 1 : 2 overall | white CuI precipitate and I₂; I₂ + 2S₂O₃²⁻ → 2I⁻ + S₄O₆²⁻ |
Convert the known concentration and volume to moles, apply the coefficient ratio from the balanced equation, then convert the target moles to the requested concentration, mass or percentage. Track any aliquot or dilution factor separately.
The medium is part of the reaction: acidified permanganate gives Mn²⁺. For Cu²⁺/I⁻ include CuI precipitation, which consumes an additional iodide beyond the 2I⁻ oxidised to I₂.
| Stage | Check |
|---|---|
| choose | identify oxidant/reductant from oxidation states, E° data and stated conditions |
| balance | conserve atoms and charge in each half-equation; use H₂O/H⁺ in acid or convert appropriately for alkaline medium |
| combine | multiply half-equations to cancel electrons, but never multiply E° values |
| calculate | convert the given quantity to moles, apply the overall coefficient ratio, then answer in requested units |
| verify | recheck mass, charge, units, significant figures and any aliquot/dilution factor |
If X²⁺ + 2e⁻ → X and Y → Y³⁺ + 3e⁻, the least common electron count is 6. The combined ratio is 3X²⁺ : 2Y, giving 3X²⁺ + 2Y → 3X + 2Y³⁺.
Do not import a memorised ratio into an unfamiliar system. The balanced electron transfer determines the stoichiometry before any mass, concentration or titre calculation begins.