IB Chemistry HL 3.1.9 (HL)—pOH scale Question Bank
3.1.9 (HL)—pOH scale
• pOH = −log₁₀[OH⁻]
• [OH⁻] = 10⁻ᵖᴼᴴ
• pH + pOH = 14 (at 25°C)
• Interconvert [H+], [OH-], pH, and pOH
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EduNinjaEduNinja• pOH = −log₁₀[OH⁻]
• [OH⁻] = 10⁻ᵖᴼᴴ
• pH + pOH = 14 (at 25°C)
• Interconvert [H+], [OH-], pH, and pOH