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IB Chemistry HL1.5 Ideal gasesQuestion Bank

Question 1

[Maximum number: 5]

Nitrogen monoxide, NO(g), is produced in internal combustion and jet engines.

Question 1(b)

(a)

Calculate the amount, in moles, of NO in 1.0×103 m31.0 \times 10^{-3} \mathrm{~m}^{3} of engine exhaust gas which contains 0.10 % NO by volume at 200C200^{\circ} \mathrm{C} and 1.0×105 Pa1.0 \times 10^{5} \mathrm{~Pa}.

Use sections 1 and 2 of the data booklet.

[ 3 ]

Question 1(c)

(b)

Outline why NO deviates more than nitrogen, N2\mathrm{N}_{2}, from the ideal gas model.

[ 2 ]

Question 1

[Maximum number: 2]

A powder has the following percentage composition by mass:
30.0 % sucrose, C12H22O11\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}
45.0 % citric acid, C6H8O7\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{7}
25.0 \% sodium hydrogencarbonate, NaHCO3\mathrm{NaHCO}_{3}

In the presence of water, the powder effervesces as the citric acid reacts with the sodium hydrogencarbonate:

3NaHCO3( s)+C6H8O7(aq)Na3(C6H5O7)(aq)+3CO2( g)+3H2O(l)3 \mathrm{NaHCO}_{3}(\mathrm{~s})+\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{7}(\mathrm{aq}) \rightarrow \mathrm{Na}_{3}\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}\right)(\mathrm{aq})+3 \mathrm{CO}_{2}(\mathrm{~g})+3 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})

Question 1(a)

Question 1(a)(ii)

(a)
(i)

Determine the volume, in dm3\mathrm{dm}^{3} at SATP, of carbon dioxide released in the reaction in (a)(i). Use sections 1 and 2 of the data booklet.

[ 2 ]

Question 1

[Maximum number: 4]

Alkanes are commonly occurring organic compounds.

Question 1(a)

(a)

The first four straight chain alkanes are gases at room temperature.

Boiling points of straight chain alkanes

Boiling points of straight chain alkanes

[ 4 ]

Question 1(a)(iii)

(i)

Calculate the volume, in dm3\mathrm{dm}^{3}, occupied by 6.45 g of propane gas at 100 kPa and 15C15^{\circ} \mathrm{C}.

[ 2 ]

Question 1(a)(iv)

(ii)

Outline why the volume occupied by propane(g) at very high pressure is higher than the value calculated using PV=nRT.

[ 2 ]

Question 1

[Maximum number: 2]

An organic compound, A, has the following composition by mass when its only combustion products, carbon dioxide and water, are analysed.

Table

Question 1(c)

(a)

A sample of the vapour of A at 200.0C200.0^{\circ} \mathrm{C}, and 1.00×105 Pa1.00 \times 10^{5} \mathrm{~Pa}, has a density of 2.544×103 g m32.544 \times 10^{3} \mathrm{~g} \mathrm{~m}^{-3}. Determine the molar mass and the molecular formula of A.

[ 2 ]

Question 1

[Maximum number: 3]

Analytical and spectroscopic techniques enable chemists to identify and determine structures of compounds.

Question 1(b)

(a)

0.363 g of organic liquid Y was vaporized completely at 95.0C95.0^{\circ} \mathrm{C} and 100.0 kPa . The gas volume was measured to be 81.0 cm381.0 \mathrm{~cm}^{3}. Determine the molar mass of Y.

[ 3 ]

Question 2

Which graph shows the relationship between the volume and pressure of a fixed mass of an ideal gas?

A
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B
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C
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D
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Question 3

Which graph represents the relationship between volume and pressure for a fixed mass of gas at constant temperature?

A
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B
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C
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D
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Question 3

[Maximum number: 1]

What is the pressure, in Pa , inside a 1.0 m31.0 \mathrm{~m}^{3} cylinder containing 10 kg of H2( g)\mathrm{H}_{2}(\mathrm{~g}) at 25C25^{\circ} \mathrm{C} ? R=8.31JK1 mol1;pV=nRTR=8.31 \mathrm{JK}^{-1} \mathrm{~mol}^{-1} ; p V=n R T

A

1×104×8.31×251.0×103\frac{1 \times 10^{4} \times 8.31 \times 25}{1.0 \times 10^{3}}

B

5×102×8.31×2981.0\frac{5 \times 10^{2} \times 8.31 \times 298}{1.0}

C

1×8.31×251.0×103\frac{1 \times 8.31 \times 25}{1.0 \times 10^{3}}

D

5×103×8.31×2981.0\frac{5 \times 10^{3} \times 8.31 \times 298}{1.0}

Question 3

[Maximum number: 1]

What is the molar mass of a gas according to the following experimental data?

Table

Ideal gas constant =8.31 J K1 mol1=8.31 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}
PV=nRT

A

40.0×8.31×29098×0.220\frac{40.0 \times 8.31 \times 290}{98 \times 0.220}

B

98×0.22040.0×8.31×290\frac{98 \times 0.220}{40.0 \times 8.31 \times 290}

C

40.0×8.31×1798×0.220\frac{40.0 \times 8.31 \times 17}{98 \times 0.220}

D

98×22040.0×8.31×17\frac{98 \times 220}{40.0 \times 8.31 \times 17}

Question 4

[Maximum number: 1]

What is the pressure, in Pa , inside a 3.0dm33.0 \mathrm{dm}^{3} cylinder containing 64 g of O2\mathrm{O}_{2} at 25.0C25.0^{\circ} \mathrm{C} ? R=8.31JK1 mol1;PV=nRTR=8.31 \mathrm{JK}^{-1} \mathrm{~mol}^{-1} ; P V=n R T

A

2×8.31×253.0\frac{2 \times 8.31 \times 25}{3.0}

B

2×8.31×2983.0×103\frac{2 \times 8.31 \times 298}{3.0 \times 10^{-3}}

C

2×8.31×2983.0\frac{2 \times 8.31 \times 298}{3.0}

D

4×8.31×2983.0×103\frac{4 \times 8.31 \times 298}{3.0 \times 10^{-3}}

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