2.2 Functions - AHL content

Syllabus
First assessment 2021
Topic
2.2
Level
HL

Composition means apply one function inside another

HL only

The composite (f∘g)(x)=f(g(x)) applies g first and then f. Its domain is restricted wherever the inner output is outside the outer function's domain.

Keep the order visible. If f(x)=√x and g(x)=x−1, then (f∘g)(x)=√(x−1), so x≥1; reversing the order gives √x−1 with a different domain and meaning.

For f(x)=2x+1 and g(x)=x², (f∘g)(3)=2·9+1=19, while (g∘f)(3)=7²=49. The functions need not commute.

Composition is not multiplication. Check which function acts first and state the domain rather than assuming both orders are valid.

Inverse workflow: restrict the original domain until the function is one-to-one, write y=f(x)y=f(x), swap xx and yy, and solve for yy. Then (ff1)(x)=x(f\circ f^{-1})(x)=x on the range of ff and (f1f)(x)=x(f^{-1}\circ f)(x)=x on the restricted domain. For f(x)=(x3)2f(x)=(x-3)^2 restricted to x3x\ge3, f1(x)=3+xf^{-1}(x)=3+\sqrt{x}; choosing x3x\le3 would give the other branch 3x3-\sqrt{x}.

Graph transformations act on input or output

HL only

For y=f(x), adding outside the function changes outputs: y=f(x)+b shifts vertically. Changing the input changes where an existing feature occurs: y=f(x−a) shifts right by a.

A factor outside, y=af(x), stretches or reflects vertically; a factor inside, y=f(bx), changes horizontal scale by 1/|b| and may reflect when b<0. Composite transformations must be applied in the stated order.

From y=x², the graph y=2(x−3)²+1 has vertex (3,1), opens upward and is twice as steep vertically. Read the vertex after the horizontal shift, then the vertical changes.

Inside and outside signs behave differently: f(x−3) moves right, while f(x)+3 moves up. Do not reverse a horizontal scale factor.

Further models match decay, cycles, saturation and changing rules

HL only

AHL models extend the SL families: half-life uses exponential decay; a+blnxa+b\ln x models logarithmic change; asin(b(xc))+da\sin(b(x-c))+d models cycles; L/[1+Cekx]L/[1+Ce^{-kx}] models growth limited by carrying capacity LL; piecewise functions use different rules on stated intervals.

For a half-life hh, Q(t)=Q0(1/2)t/hQ(t)=Q_0(1/2)^{t/h}. In a sinusoidal model, radians are assumed unless degrees are marked, the period is 2π/b2\pi/|b|, and cc is a horizontal translation or phase shift. In a logistic model, LL is the horizontal asymptote and carrying capacity.

Example

If a quantity starts at 800 and has half-life 3 years, Q(t)=800(1/2)t/3Q(t)=800(1/2)^{t/3}, so Q(6)=200Q(6)=200. For a piecewise model, solve shared-boundary parameter conditions when continuity is required; the formal definition of continuity is not required.

A model family is chosen from mechanism and shape, not fit alone. Do not use degrees in a radian model, call LL the initial value of a logistic curve, or assume two piecewise rules join continuously without checking their boundary values.

Log scales reveal multiplicative structure

HL only

A logarithmic axis spaces equal ratios equally. Taking logs can turn a multiplicative model into a linear one: y=Ax^k gives log y=log A+k log x, while y=Ab^x gives log y=log A+x log b.

The slope on a log–log plot estimates a power k; the slope on a semi-log plot estimates log b. Choose the transformation that matches the proposed mechanism and keep the same log base when interpreting intercepts.

If doubling x roughly quadruples y, a log–log slope near 2 is more informative than a straight-line fit on ordinary axes. The intercept gives the scale factor only after undoing the logarithm.

A straight line after transformation does not prove the original relationship. Check units, zero/negative values and back-transform predictions before making the contextual claim.

Logarithms compress very large or small positive values into a manageable scale. On a semi-log plot, linearity supports y=Abxy=Ab^x and slope is logb\log b; on a log–log plot, linearity supports y=Axky=Ax^k and slope is kk, with intercept logA\log A. Students interpret these graphs in examinations but are not required to draw or sketch them. Zero and negative values cannot be logged without redefining the model.

Objective notes

4 learning objectives