SL 5.10—Indefinite integration
- Syllabus
- First assessment 2021
- Objective
- —
- Level
- SL
Indefinite integration reconstructs a family of functions.
Reverse the derivative term by term and retain the arbitrary constant; the constant represents the unknown vertical shift.
∫(2x+sin x)dx=x²−cos x+C.
Differentiate the answer and use any initial value to fix C.
Do not omit C when no initial condition has selected one antiderivative.
Formula set: ∫xndx=xn+1/(n+1)+C for n=−1, ∫dx/x=ln∣x∣+C, ∫exdx=ex+C, ∫sinxdx=−cosx+C, and ∫cosxdx=sinx+C. For a linear composite, account for the inner gradient: ∫cos(2x+3)dx=21sin(2x+3)+C. Reverse-chain recognition gives ∫kg′(x)[f(g(x))]dx by substitution or inspection.