SL 5.10—Indefinite integration

Syllabus
First assessment 2021
Objective
Level
HL

Indefinite integration reconstructs a family of functions

Indefinite integration reconstructs a family of functions.

Reverse the derivative term by term and retain the arbitrary constant; the constant represents the unknown vertical shift.

Example

∫(2x+sin x)dx=x²−cos x+C.

Differentiate the answer and use any initial value to fix C.

Do not omit C when no initial condition has selected one antiderivative.

Formula set: xndx=xn+1/(n+1)+C\int x^n\,dx=x^{n+1}/(n+1)+C for n1n\ne-1, dx/x=lnx+C\int dx/x=\ln|x|+C, exdx=ex+C\int e^x\,dx=e^x+C, sinxdx=cosx+C\int\sin x\,dx=-\cos x+C, and cosxdx=sinx+C\int\cos x\,dx=\sin x+C. For a linear composite, account for the inner gradient: cos(2x+3)dx=12sin(2x+3)+C\int\cos(2x+3)\,dx=\tfrac12\sin(2x+3)+C. Reverse-chain recognition gives kg(x)[f(g(x))]dx\int k g'(x)[f(g(x))]\,dx by substitution or inspection.