AHL 5.15 (HL)—Further derivatives and integrals

Syllabus
First assessment 2021
Objective
Level
HL

Further derivative pairs unlock advanced integrals

HL only

Further derivative pairs unlock advanced integrals.

Key derivatives are (tanx)=sec2x(\tan x)'=\sec^2x, (secx)=secxtanx(\sec x)'=\sec x\tan x, (cosecx)=cosecxcotx(\cosec x)'=-\cosec x\cot x, (cotx)=cosec2x(\cot x)'=-\cosec^2x, (ax)=axlna(a^x)'=a^x\ln a, (logax)=1/(xlna)(\log_a x)'=1/(x\ln a), (arcsinx)=1/1x2(\arcsin x)'=1/\sqrt{1-x^2}, (arccosx)=1/1x2(\arccos x)'=-1/\sqrt{1-x^2} and (arctanx)=1/(1+x2)(\arctan x)'=1/(1+x^2).

Example

Because 1/[(x+1)(x+2)]=1/(x+1)1/(x+2)1/[(x+1)(x+2)]=1/(x+1)-1/(x+2), partial fractions give dx/[(x+1)(x+2)]=lnx+1lnx+2+C\int dx/[(x+1)(x+2)]=\ln|x+1|-\ln|x+2|+C. For dx/[1+(2x+1)2]\int dx/[1+(2x+1)^2], the linear inner derivative gives 12arctan(2x+1)+C\tfrac12\arctan(2x+1)+C.

Match an integrand to a derivative pair, include the reciprocal inner-gradient factor for a linear composite, and use partial fractions before integrating a rational expression when required.

Inverse-trig derivative domains and logarithmic absolute values matter; a memorised form without its domain or inner-gradient factor is incomplete.