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AP Physics C Mechanics 5.4 Rotational Inertia Overview

Describe rotational inertia relative to an axis and apply mass distribution and the parallel-axis theorem to rigid systems.

Syllabus
Effective Fall 2025
Course
AP Physics C: Mechanics

5.4 Rotational Inertia question 1

[Maximum number: 3]

A uniform rod of length L and mass m is attached to a pivot on a vertical pole, as shown in Figure 1. There is negligible friction between the rod and the pivot. A horizontal string connects Point Q on the rod to the pole. The rod makes an angle θ\theta with the pole. A block of mass 3 m hangs from the rod at Point P. The center of mass of the rod is located at Point C.

A nonuniform rod is now attached to the pivot, as shown in Figure 3. There is negligible friction between the nonuniform rod and the pivot. The rod has a length of 1.2 m and a linear mass density λ(x)=A+Bx\lambda(x)=A+B x, where x is the distance from the pivot, A=6.0 kg/mA=6.0 \mathrm{~kg} / \mathrm{m}, and B=10.0 kg/m2B=10.0 \mathrm{~kg} / \mathrm{m}^{2}.

Calculate the rotational inertia of the rod about the pivot.

5.4 Rotational Inertia question 2

[Maximum number: 3]

A uniform disk of radius R and mass mdm_{\mathrm{d}} is attached to a vertical pole by a horizontal axle that passes through the center of the disk. Friction between the axle and the disk is negligible. A lump of clay of mass mcm_{\mathrm{c}} is attached to the edge of the disk at Point A. The size of the lump of clay is small compared with the radius of the disk. A horizontal string is connected from the pole to the edge of the disk at Point A. The string makes an angle θ\theta with the line between Point A and the axle, as shown in Figure 1.

A nonuniform disk is now attached to the axle. The lump of clay is attached to the disk at Point B, as shown in Figure 3. The clay has mass mc=0.60 kgm_{\mathrm{c}}=0.60 \mathrm{~kg} and the disk has a radius R=0.30 mR=0.30 \mathrm{~m}. The mass density of the disk varies radially and can be modeled by ρ(r)=βr\rho(r)=\beta r, where r is the radial distance from the axle and β=4.0 kg/m3\beta=4.0 \mathrm{~kg} / \mathrm{m}^{3}.

Calculate the rotational inertia of the disk about the axle.

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