7.3 Representing and Analyzing SHM

Syllabus
2024
Topic
7.3
Level

Learning objectives

Read displacement, velocity, and acceleration in SHM

Represent displacement sinusoidally

x=Acos(2πft)orx=Asin(2πft)x=A\cos(2\pi ft)\quad\text{or}\quad x=A\sin(2\pi ft)

AA is maximum displacement from equilibrium and ff sets the cycle rate. Sine and cosine describe the same SHM with different choices of where the clock starts.

Match the three key positions

Position Velocity Acceleration
x=+Ax=+A v=0v=0 Maximum magnitude toward negative/equilibrium direction
x=0x=0 Maximum speed a=0a=0
x=Ax=-A v=0v=0 Maximum magnitude toward positive/equilibrium direction
1

Trace one cosine-start cycle

Time for cosine start Displacement Motion state
00 +A+A Released from rest; acceleration toward equilibrium
T/4T/4 00 Moving fastest in the negative direction; acceleration zero
T/2T/2 A-A Instantaneously at rest; acceleration toward equilibrium
3T/43T/4 00 Moving fastest in the positive direction; acceleration zero
TT +A+A One complete cycle

Read zeros and extrema

On an xx–time graph, velocity is zero at displacement peaks and greatest in magnitude where the curve crosses equilibrium. Acceleration always has the opposite sign to xx, so its extrema align with displacement extrema but point oppositely.

Change amplitude without changing period

Increasing amplitude makes the displacement graph taller, but it does not change the period of an ideal SHM system. Do not infer a longer cycle merely because the object travels farther.