5.6 Newton’s Second Law in Rotational Form

Syllabus
2024
Topic
5.6
Level

Learning objectives

Predict angular acceleration from net torque

Identify when angular velocity changes

A rigid system's angular velocity changes when the net torque about the chosen axis is nonzero. The resulting angular acceleration has the same signed rotational sense as the net torque.

Connect net torque and rotational inertia

αsys=iτiIsys=τnetIsys\alpha_{\mathrm{sys}}=\frac{\sum_i\tau_i}{I_{\mathrm{sys}}}=\frac{\tau_{\mathrm{net}}}{I_{\mathrm{sys}}}

Quantity Meaning SI unit
τnet\tau_{\mathrm{net}} Signed sum of torques about the axis Nm\text{N}\,\text{m}
IsysI_{\mathrm{sys}} Rotational inertia about that axis kgm2\text{kg}\,\text{m}^2
αsys\alpha_{\mathrm{sys}} Rate of change of angular velocity rads2\text{rad}\,\text{s}^{-2}

Predict proportional changes

Change Angular acceleration response Why
Double τnet\tau_{\mathrm{net}} at fixed II Doubles ατnet\alpha\propto\tau_{\mathrm{net}}
Double II at fixed τnet\tau_{\mathrm{net}} Halves α1/I\alpha\propto1/I
Make τnet=0\tau_{\mathrm{net}}=0 Becomes zero Angular velocity stays constant

Calculate angular acceleration

Rigid system: take counterclockwise as positive. If τnet=+6.0Nm\tau_{\mathrm{net}}=+6.0\,\text{N}\,\text{m} and Isys=2.0kgm2I_{\mathrm{sys}}=2.0\,\text{kg}\,\text{m}^2,

α=+6.02.0=+3.0rads2\alpha=\dfrac{+6.0}{2.0}=+3.0\,\text{rad}\,\text{s}^{-2}.

The positive result means the angular velocity changes in the counterclockwise sense under this convention.

Separate rotational and linear dynamics

Rotational analysis alone does not fully describe every rigid system. Use τ=Iα\sum\tau=I\alpha for rotation about the chosen axis and, when the center of mass also translates, perform a separate linear analysis with F=macm\sum\vec F=m\vec a_{\mathrm{cm}}. One equation does not replace the other.