2.9 Circular Motion
- Syllabus
- 2024
- Topic
- 2.9
- Level
- —
At any point on the circle:
For radius r and tangential speed v, ac=rv2. In uniform circular motion, at=0 even though ac=0. One revolution takes period T and frequency is revolutions per second: T=f1 and T=v2πr.
There is no new force called 'centripetal force.' The inward net component of real forces satisfies ∑Finward=mac. Gravity can supply it alone; normal force and static friction components can supply it on a banked path; a tension component supplies it for a conical pendulum.
Top-of-loop threshold: at the minimum speed that maintains contact, the contact force has just fallen to zero, so gravity alone supplies the inward force: mg=mrv2. Therefore vmin=gr. Below this speed, the required inward force would exceed what gravity provides at that point, so contact cannot be maintained.
Constant speed does not mean zero acceleration in a circle because velocity direction keeps changing. For banked curves, AP Physics 1 expects quantitative analysis only when no friction is required for uniform circular motion; friction-required banked curves are analyzed qualitatively.
For a satellite of mass m in a circular orbit of radius R around a central mass M, gravitational attraction supplies the entire inward force. Orbit radius is measured from the central body's center of mass.
GR2Mm=mRv2 and v=T2πR. Substitution cancels the satellite mass and gives Kepler's third-law form for a circular orbit: T2=GM4π2R3.
| Comparison | Consequence |
|---|---|
| Same M: R increases by factor q | T increases by q3/2 |
| Same R: M increases by factor q | T decreases by q |
| Satellite mass m changes | Circular-orbit period at the same R is unchanged |
Ratio example: around the same central body, if orbit B has RB=4RA, then TATB=(RARB)3/2=43/2=8. The farther circular orbit takes eight times as long. AP Physics 1 does not require Kepler's first or second laws; keep this derivation to circular orbits.