Question 1
1
White clover (Trifolium repens) is native to Eurasia but is now a common plant found worldwide in lawns, next to roads, in pastures and similar habitats. Some T. repens plants are able to produce the toxin hydrogen cyanide (HCN) by cyanogenesis. A study at 128 sites ( 2509 plants) in Toronto (Canada) looked at the proportion of T. repens plants producing HCN. The sites were at regular intervals from the city centre towards rural areas.
9 marks
Question 1(a)
1(a)
2 marks
Question 1(a)(i)
1(a)(i)
State the distance from the city centre at which the highest proportion of plants sampled contained HCN.
Easystructured1 marks
Answer
i 32 (km); Accept answers in the range of 31 to \(33(\mathrm{~km})\)
Question 1(a)(ii)
1(a)(ii)
Outline the relationship shown in the graph. To determine whether similar patterns in cyanogenesis were seen in other cities, studies were also carried out around New York City and Boston (USA) and Montreal (Canada).
Mediumstructured1 marks
Answer
positive correlation / (proportion with) HCN increases as distance increases;
Question 1(b)
1(b)
Deduce whether the pattern of cyanogenesis was the same in all of the areas around all four cities.
Mediumstructured2 marks
Answer
a Toronto NYC and Boston show same pattern/all show positive correlation/relationship/WTTE; b Montreal shows negative correlation/negative relationship/WTTE so is different; 2 max
Question 1
1
The incidence of white syndrome, an infectious disease of coral, was investigated in a six-year study on Australia's Great Barrier Reef. The map shows disease conditions on coral reefs at six study sites.
13 marks
Question 1(e)
1(e)
This study was carried out over six years on the Australian Great Barrier Reef. State one advantage of field investigations compared with mesocosm experiments to study ecological processes.
Easystructured1 marks
Question 1
1
Honeybees (Apis mellifera) are key pollinators in most ecosystems. The worldwide use of neonicotinoid pesticides has caused concern because they may be contributing to the decline of honeybee populations. Scientists measured the concentration of five neonicotinoids (acetamiprid, clothianidin, imidacloprid, thiacloprid and thiamethoxam) in honey samples from 198 different locations across the world. Each pie chart shows the relative frequency of neonicotinoids in honey samples from a continent.
15 marks
Question 1(a)
1(a)
Identify in which continent the fewest types of neonicotinoid were detected in honey samples.
Mediumstructured1 marks
Answer
Oceania
Question 1(b)
1(b)
Using the data, outline the different use of thiamethoxam in North and South America. The neonicotinoids can be used alone or together with other neonicotinoids. The percentage of honey samples with 0,1,2,3,4 or 5 different neonicotinoids in each continent are shown in the stacked bar chart.
Mediumstructured1 marks
Answer
thiamethoxam is the most used in North America (but not in South America) / CONVERSE OR in South America they use different neonicotinoids to thiamethoxam OWTTE Allow numerical comparison.
Question 1(c)
1(c)
Identify the total percentage of honey samples contaminated with neonicotinoid pesticides in the continent with the lowest overall levels of contamination. \% In order to grow, honeybee larvae are fed royal jelly, a high energy food with very high acetylcholine concentrations. In an experiment, larvae were bred artificially on a diet with reduced acetylcholine content in the royal jelly. The graph shows the mean survival rate of these larvae compared to control larvae fed on a normal diet. Key: - Control △ Reduced acetylcholine royal jelly
Easystructured1 marks
Answer
57 (\%) Allow range 56\% to 58\%.
Question 1
1
A community living in the water of an estuary was used to investigate how climate change may affect ecological systems. The food web in this community included phytoplankton (producers), zooplankton (consumers) and saprotrophic bacteria. Small plastic mesocosms were set up with water from the estuary containing only these three groups of organisms. The mesocosms were subjected to four different temperatures and two nutrient levels (control and nutrients added) to replicate local variations of the conditions in the estuary during springtime warming. The graph shows the biomass of the community for each of the eight mesocosms at the end of the experimental period. Biomass was measured in terms of the amount of carbon present. The horizontal line indicates the initial biomass.
15 marks
Question 1(g)
1(g)
The first study used mesocosms and the second study was carried out in natural grassland. Discuss the use of mesocosms as opposed to a study in a natural environment.
Hardessay2 marks
Answer
advantages of mesocosms/converse problems with studies in natural environments a easier to manipulate/control variables/conditions / less susceptible to outside influences OR easier to replicate OR take up less space; disadvantages of mesocosms/converse opportunities with studies in natural environments b some trophic levels missing/incomplete food chains in mesocosms OR large animals cannot be included / ethical concerns about enclosing animals in mesocosms OR some variables lacking in mesocosms / doesn't show what happens in natural ecosystems; Allow only one mark for an advantage and one mark for a disadvantage as this is a discuss question. 2 max
Question 1
1
The biodiversity of insects worldwide is in decline. Destruction of habitats, pollution and climate change have contributed to the decline in global insect populations and to the extinction of insect species. A comprehensive literature review was carried out to determine the annual global rate of decline in insect species. The graph shows the results for three major orders of terrestrial insects and the total decline in insect biomass worldwide.
0 marks
Question 1(a)
1(a)
State the mean annual decline in insect biomass.
Easystructured1 marks
Answer
2.5 \%; \% required
Question 1(b)
1(b)
Compare and contrast the results for Hymenoptera and Lepidoptera.
Mediumstructured2 marks
Answer
a. both show a decline in number; b. the mean decline for Hymenoptera is less than the mean for Lepidoptera OR there is a wider range of decline among the species of Lepidoptera; 2 max
Question 1(c)
1(c)
Calculate the number of Coleoptera species that would be expected to exist after one year from a starting number of 400000 species, assuming the mean rate of decline.
Mediumstructured1 marks
Answer
392000 (species);
Question 1(h)
1(h)
The graph shows the percentage of bumblebees that survived each day while being fed on different P:L diets. For each trial, n=15. ... 100\% protein 50:1 25:1 10:1 5:1 1:1 1:5 1:10 State the relationship between high lipid content and survivability on day 7.
Mediumstructured1 marks
Answer
the higher the lipid content, the fewer bees survived/negative correlation;
Question 1
1
There is growing evidence of a decrease in bee populations. This decrease is a serious problem because of their valuable role as pollinators in the ecosystems where they live. Neonicotinoid pesticides have been implicated in this decrease because they have been found at trace levels in the nectar and pollen of crop plants and in the bee colonies. Scientists placed colonies of a species of bumblebee, Bombus terrestris, in the laboratory to test the effects of different levels of a neonicotinoid on their development. They divided the colonies into three groups: - The control colonies were given a solution of water and sugar that resembled nectar produced by flowers. - A second group of colonies was given the same sugar solution containing a neonicotinoid dissolved in it at low concentrations, similar to those found in nature. - A third group of colonies was given the same sugar solution containing a neonicotinoid dissolved in it at high concentrations, similar to those found in nature. After two weeks, all colonies were placed in the field to allow the bumblebees to feed naturally.
12 marks
Question 1(a)
1(a)
5 marks
Question 1(a)(iii)
1(a)(iii)
Compare and contrast the cumulative increase in mass of the three groups of colonies once they were placed in the field.
Mediumstructured2 marks
Answer
a. all increased in (cumulative) mass gain up to 5-6 weeks OR all decreased (in cumulative mass gain) after 6 weeks; b. both with neonicotinoids have significantly lower (cumulative) mass than the control colonies (at all periods) OR colonies exposed to high concentration always had the lowest (cumulative) mass gain; Accept vice versa
Question 1(a)(iv)
1(a)(iv)
Suggest a reason for the changes in mass in the colonies between weeks 6 and 8.
Mediumstructured1 marks
Answer
a. less production of honey/wax; b. fewer bees/dispersal of bees/queens; c. bad weather/environmental change/predators/disease/pests; 1 max
Question 1(b)
1(b)
The number of queen bumblebees produced in each colony was recorded. New bumblebee colonies are started by a queen. Using the data in the graph, predict how the use of neonicotinoid pesticides will affect bumblebee populations.
Mediumstructured3 marks
Answer
a. number of populations may/will decrease; b. both treatments decreased very significantly the number of queens; c. low treatment had (almost) the same effect as the high OR even low levels have as toxic/lethal effects as high levels; d. without new queens, new colonies cannot be founded; e. no/less/little reproduction (as only queens lay eggs); f. new colonies are essential to maintain bumblebee populations; 3 max
Question 1
1
Common shrews (Sorex araneus) are small mammals found in Northern Europe. Their diet includes insects, slugs, spiders, worms and amphibians. They do not hibernate in winter because their bodies are too small to store sufficient fat reserves. To study brain size in shrews, researchers anesthetize them, X-ray their skulls and measure the height of the braincase (BCH) where the brain is located. The graph shows the relationship between BCH and the brain mass of individual adult shrews.
12 marks
Question 1(a)
1(a)
State the relationship between BCH and brain mass of shrews.
Easystructured1 marks
Answer
positive correlation/the greater the BCH the greater the brain mass; No mark for 'positive relationship' or for directly proportional
Question 1(b)
1(b)
Outline how the shrew labelled P differs from the normal relationship between BCH and brain mass.
Mediumstructured1 marks
Answer
a. high BCH but brain mass is low/lower than expected/lower than others with similar BCH; b. (fairly) low brain mass but BCH is high/higher than expected/higher than others with similar brain mass; 1 max
Question 1(g)
1(g)
Shrews were observed in different seasons and the time they spent on a particular activity was recorded and expressed as a percentage of the total observation time. The circles in the kite shapes represent the mean value of time for each activity. State the activity and season that occupied the greatest mean percentage of observation time.
Easystructured1 marks
Answer
resting in spring;
Question 1(h)
1(h)
Suggest a reason for the difference in the time observed eating and drinking.
Mediumstructured2 marks
Answer
a. more food/energy eaten/required in winter/cold; b. food needed to maintain temperature/stay warm/generate heat; c. more loss of body heat in cold conditions; d. more energy used hunting for food; e. food less available in winter/harder to find enough food; 2 max 1. i 4(\%);
Question 1(i)
1(i)
The researchers were interested in the seasonal differences in searching for food. They set up a square arena with sides of 110 cm and four entrances (A, B, C and D). Containers were placed in the arena, some with food and others with no food. The diagram shows a top-down view of the arena. Each shrew was starved of food for two hours before its cage was opened at one of the entrances to the arena. The length of the path taken by the shrew to obtain food was measured. This was standardized by dividing the path length by the straight-line distance from the entrance to the containers with food. Each shrew was used for 10 trials. The graph shows the standardized mean path length taken by all the shrews at different seasons of the year. The letters show where the cages were placed for each trial. Calculate the percentage of containers that contained food.
Easystructured1 marks
Answer
a. in winter shrews have smaller brains/smaller BCH / converse for summer; b. lower/poorer memory/thinking/cognitive skills/learning/intelligence/senses/sense of smell/ability to find food in winter/ converse for summer;
Question 1(j)
1(j)
Outline a reason that the path length was standardized.
Mediumstructured1 marks
Answer
compensates for the different distances between entrances and food/OWTTE; OR to enable (fair/valid) comparison/OWTTE; Do not accept unspecific answers such as 'to be consistent'
Question 1
1
12 marks
Question 1(a)
1(a)
1. There is increasing interest in the bacteria that live in the human gut, known as the gut microbiota. Evidence is accumulating of widespread effects on human health, with some species of bacteria increasing the prevalence of specific diseases and others giving protection. Long-term diet appears to influence the numbers and types of bacteria that are present in an individual's gut. Several different characteristic combinations of bacteria (called enterotypes) have been discovered. The stacked column graph shows relative amounts of different genera of bacteria in the gut of people with four of these enterotypes. The Bacteroides 2 (B2) enterotype is associated with an increased prevalence of inflammatory bowel disease. Using the data in the stacked column graph, describe the features that characterize the B2 enterotype.
Mediumstructured2 marks
Answer
a. nearly half is Bacteroides / more Bacteroides (than other enterotypes); b. few Prevotella/fewer Prevotella than in P and R OR less Faecalibacterium than other enterotypes OR Ruminococcus is the lowest in B2; c. only 40 % other taxa / fewer other taxa (than other enterotypes) / less overall diversity (of taxa); 2 max
Question 1(b)
1(b)
Samples of feces were collected from 40 individuals and were immediately frozen to preserve them. The numbers of bacteria in the feces (cell counts \(/ 10^{11}\) cells \(\mathrm{g}^{-1}\) ) were later measured and the enterotype was determined. The box plot shows this data. Each data point shows the cell count from one fecal sample. Estimate the median number of bacterial cells per gram of feces in the R enterotype.
Easystructured1 marks
Answer
\(1.9 \times 10^{11}\) / 190000 million / 190 billion (cells per gram); Cells per gram not needed as in stem. Accept \(1.80 \times 10^{11}\) to \(1.95 \times 10^{11}\).
Question 1(c)
1(c)
Distinguish between the cell counts in the R and B2 enterotypes.
Mediumstructured2 marks
Answer
a. lower values for cell counts in B2 (than in R) / converse OR median is higher in R (than in B 2 ) / R median is 1.9 versus B 2 median is 1.1 OR lower number of cell counts in R; b. all counts in R higher than third/75th/upper quartile in B2 OR 25-75 % range (box) in B2 is smaller than in R; c. R maximum 3.1 versus B 2 maximum is 2.1 OR R maximum is higher than B 2 max; d. B2 minimum is lower than R minimum; The ranges are basically the same. 2 max
Question 1(d)
1(d)
Comment on the data for the P enterotype.
Mediumstructured1 marks
Answer
a. only one sample/count/data point; b. only analysed feces from one person (with this enterotype); c. not a big enough sample; 1 max
Question 1(e)
1(e)
2 marks
Question 1(e)(i)
1(e)(i)
Statins are drugs that are commonly prescribed to reduce cholesterol concentrations in the blood. As part of research into the effects of statins, the enterotype and body mass index (BMI) of 782 individuals were determined. The results are shown in the stacked graph. Key: B1 = Bacteroides 1 P = Prevotella R = Ruminococcaceae B2 = Bacteroides 2 Estimate the prevalence of the P enterotype at a BMI of 50.
Easystructured1 marks
Answer
0.35; Accept any values between 0.33 and 0.37. Accept 35\%.
Question 1(e)(ii)
1(e)(ii)
State the relationship between BMI and the prevalence of the B 2 enterotype.
Easystructured1 marks
Answer
B2 is associated/commoner/more prevalent in people with higher BMI OR (prevalence of) B2 increases as BMI increases; Accept positive correlation/OWTTE.
Question 1(f)
1(f)
Evaluate the evidence provided by the data in the graph for the hypothesis that the R enterotype causes low BMI.
Hardstructured2 marks
Answer
a. R is more common/prevalent in people with low BMI ; b. statement about it being far more common; c. but this correlation does not prove that R causes low BMI; d. low BMI could(actually) be the cause of higher prevalence of R; So ' R is far more common in people with low BMI', would gain both a and b. 2 max
Question 1(g)
1(g)
The 782 individuals for whom BMI and enterotype had been determined were divided into four groups, according to whether or not they were taking statins and their BMI category. The prevalence of the four enterotypes in each of these groups is shown as a percentage in the pie charts. The prevalence of inflammatory bowel disease rises with increases in BMI. At any BMI level, individuals with the B2 enterotype have a higher prevalence of inflammatory bowel disease than with other enterotypes. Using the data in the graph, discuss whether statins could reduce the incidence of inflammatory bowel disease.
Hardstructured2 marks
Answer
a. high/highest \% of B2 enterotype in people with BMI greater than (or equal to) 30 with no statins OR taking statins could reduce the percentage of B2 enterotype in people with BMI \(\geq 30\) OR reducing BMI to below 30 could lower \% of people with B2 enterotype without taking statins; b. but statins may not cause a person to change from B2 to another enterotype OR lower B2 in those taking statins if BMI is >30 so might reduce IBD/inflammatory bowel disease OR but when BMI<30, there is almost double the prevalence of B2 in those taking statins so might not have an effect / increase (prevalence of) inflammatory bowel disease; One for correct data and one for discussion
Question 1
1
According to the UN Inter-agency Group for Child Mortality Estimation, in the year 2000 there were 9.82 million deaths of children under the age of 5 . Many of these deaths were caused by infectious diseases. The pie chart shows estimates for the percentages of deaths that were attributable to two of the most frequent pathogens, Streptococcus pneumoniae and Haemophilus influenzae.
16 marks
Question 1(a)
1(a)
Calculate the number of deaths in children under the age of 5 that were attributed to S. pneumoniae in the year 2000.
Easystructured1 marks
Answer
736 500; No calculation required. Note accept 0.7365 million (4 significant figures needed) or other mathematics notations.
Question 1(f)
1(f)
Acute respiratory infection (ARI) is a frequent reason for antibiotic use among children in low-income and middle-income countries (LMICs). S. pneumoniae is the predominant, but not the only, cause of ARI in children. In a large-scale study, data were collected in 18 LMICs from 65815 children under the age of 5 . The data were analysed to estimate the fraction of ARI cases among the children that could be attributed to S. pneumoniae as shown in the graphs. The upper estimate in the graphs is for all cases, whether or not they were treated with antibiotics. The lower estimate is for the subset of cases that required antibiotic treatment. The range of estimates is shown by violin plots, with a point for the median estimate and lines for 95 % confidence intervals. Using the data in the violin plots, deduce the age range at which children are most likely to develop ARI due to S. pneumoniae.
Mediumstructured2 marks
Answer
a. 2-5 years; b. higher number/value/percentage/attributable fraction for 2-5 years (than 0-5 years); 1 2
Question 1(h)
1(h)
Estimates were made of the extent of antibiotic use in low-income and middle-income countries. Graphs were constructed to show global estimates for the numbers of cases in LMICs per year of ARI treated with antibiotic in children under the age of 5 . The estimates for LMICs were divided according to income: low income, lower-middle income and upper-middle income. The graph shows estimates for three levels of vaccination for S. pneumoniae with PCV: - no vaccination - 2018 coverage: the vaccine coverage that there was in 2018 - universal coverage: predictions assuming that in the future all children in all LMICs receive the vaccination. When there is no vaccination, the estimated number of cases for lower-middle income countries is larger than in either low income or upper-middle income countries. Suggest one reason for this.
Hardstructured1 marks
Answer
a. higher population in lower-middle income countries/subgroup (compared to the other 2 subgroups); b. low income population may not have/have less access to medicine/antibiotics/vaccination (compared to lower-middle income population)/ low-income populations may not report data OR upper-middle population may have better living conditions/more adequate medical diagnoses (compared to lower-middle income population); Lower-middle income subgroup is not the same as LMIC (includes all 3 subgroups). LMIC should not be used as equivalent. Mpb: accept vice versa. 1 max
Question 1
1
Type II diabetes, a widespread and challenging health problem, is due to insulin resistance, which results in raised blood glucose. Alpha-glucosidase enzymes catalyse the hydrolysis of carbohydrates. Inhibition of the enzymes slows the absorption of glucose in the intestine and thus slows the rise in blood glucose. A study examined the inhibitory effect of five species of seaweed (Palmaria palmata, Saccharina latissima, Fucus vesiculosus, Ascophyllum nodosum and Alaria esculenta) on alpha-glucosidase. Dried seaweed extracts made with water or ethanol were added to maltose. The solutions were incubated, then analysed for glucose content. The graph shows percent inhibition of alpha-glucosidase with different seaweed extracts compared with uninhibited enzyme activity (control).
structured13 marks
Question 1(e)
1(e)
Calculate the greatest increase in mean body mass over 11 weeks.
Easystructured1 marks
Answer
7.8g; Unit required.
Question 1(f)
1(f)
Distinguish between the results for S. Iatissima and P. palmata. Glycated hemoglobin (HbA1c) is formed when glucose in blood plasma binds spontaneously to hemoglobin. A high percentage of HbA1c indicates that glucose levels in the blood have been raised for much of the time. At the beginning of the investigation, after 8 hours without food, blood was taken from all the mice and tested for HbA 1 c levels. The levels were similar for all mice. The graph shows the levels of HbA1c after 10 weeks of treatment with the seaweed extracts.
Mediumstructured2 marks
Answer
a. S.latissima treatment gained less mass; b. P.palmata treatment gains mass consistently, S.latissima treatment only gains mass after week 5; Or converse.