Question 8
8
Fig. 8.1 shows part of the emission spectrum of visible radiation emitted by hydrogen gas in a star in a distant galaxy. The galaxy is moving away from the Earth at a speed of \(6.2 \times 10^{6} \mathrm{~ms}^{-1}\) .
Question 8(a)
8(a)
Question 8(a)(i)
8(a)(i)
(a)(i)Explain how the positions of the lines in the emission spectrum seen by an observer on the Earth differ from the positions shown in Fig.8.1.
Answer
movement of star causes change in (observed) frequency or movement of star causes redshift B1 observed frequency is lower (than emitted frequency) B1
Question 8(a)(ii)
8(a)(ii)
(ii)On Fig.8.1,draw the three lines in possible positions in the spectrum seen by the observer. (b)The lines in Fig. 8.1 correspond to electron transitions down to the energy level -3.40 eV . One of the lines represents emitted radiation of wavelength 488 nm .
Answer
all three lines shown to left of corresponding printed lines B1 distance between drawn line and corresponding printed line approximately the same for all three lines B1
Question 8(b)
8(b)
Question 8(b)(iii)
8(b)(iii)
Determine the wavelength, in nm , of this radiation as detected by the observer on the Earth. wavelength = nm
Answer
\[ \begin{aligned} \Delta \lambda =\lambda \times(v / c) =\left(488 \times 6.2 \times 10^{6}\right) /\left(3.00 \times 10^{8}\right) =10 \mathrm{~nm}) \end{aligned} \] C1 \[ \begin{aligned} \text { observed wavelength } =488+\Delta \lambda=488+10 =498 \mathrm{~nm} \end{aligned} \] A1
Question 8(c)
8(c)
A value for the Hubble constant is \(2.3 \times 10^{-18} \mathrm{~s}^{-1}\). Determine the distance of the galaxy from the Earth. distance = m
Answer
\(v \quad=H_{0} d\) C1 \[ \begin{aligned} d =\left(6.2 \times 10^{6}\right) /\left(2.3 \times 10^{-18}\right) =2.7 \times 10^{24} \mathrm{~m} \end{aligned} \] A1