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A-Level CAIE Physics 22 3 Wave Particle Duality Question Bank

Practice A-Level CAIE Physics 22 3 Wave Particle Duality questions by syllabus topic with past-paper context, marks, difficulty and question previews on Eduninja.

10 matching questions · Open interactive library

Question 6

6

1 marks

Question 6(b)

6(b)

An X-ray photon of energy \(3.06 \times 10^{-14} \mathrm{~J}\) is incident on an isolated stationary electron, as illustrated in Fig. 6.1. The photon is deflected elastically by the electron through angle \(\theta\). The deflected photon has a wavelength of \(6.80 \times 10^{-12} \mathrm{~m}\).

structured1 marks

Question 6(b)(i)

6(b)(i)

On Fig. 6.1, draw an arrow to indicate a possible initial direction of motion of the electron after the photon has been deflected.

Mediumstructured1 marks

Answer

arrow below axis and pointing to right

Question 7

7

9 marks

Question 7(a)

7(a)

State what is meant by the de Broglie wavelength.

Easystructured2 marks

Answer

wavelength of wave associated with a particle that is moving

Question 7(b)

7(b)

An electron is accelerated in a vacuum from rest through a potential difference of 850 V .

structured2 marks

Question 7(b)(ii)

7(b)(ii)

Calculate the de Broglie wavelength of this electron. wavelength = m

Mediumstructured2 marks

Answer

\(\lambda=h / p\) wavelength \(=\left(6.63 \times 10^{-34}\right) /\left(1.6 \times 10^{-23}\right)\)

Question 7(c)

7(c)

Describe an experiment to demonstrate the wave nature of electrons. You may draw a diagram if you wish.

Mediumstructured5 marks

Answer

diagram or description showing: electron beam in a vacuum incident on thin metal target / carbon film fluorescent screen B1 pattern of concentric rings observed pattern similar to diffraction pattern observed with visible light

Question 7

7

7 marks

Question 7(a)

7(a)

State what is meant by the de Broglie wavelength.

Easystructured0 marks

Answer

wavelength associated with a particle that is moving

Question 7(b)

7(b)

An electron is accelerated from rest in a vacuum through a potential difference of 4.7 kV .

structured7 marks

Question 7(b)(i)

7(b)(i)

Calculate the de Broglie wavelength of the accelerated electron. wavelength = m

Mediumstructured5 marks

Answer

kinetic energy \(=1.6 \times 10^{-19} \times 4700\) either energy \(=p^{2} / 2 m\) or \(E_{\mathrm{K}}=1 / 2 m v^{2}\) and p=m v \(p=\sqrt{ }\left(7.52 \times 10^{-16} \times 2 \times 9.1 \times 10^{-31}\right)\) C1 \(=3.7 \times 10^{-23} \mathrm{~N} \mathrm{~s}\) \(\lambda=h / p\) \(=\left(6.63 \times 10^{-34}\right) /\left(3.7 \times 10^{-23}\right)\) \(=1.8 \times 10^{-11} \mathrm{~m}\)

Question 7(b)(ii)

7(b)(ii)

By reference to your answer in (i), suggest why such electrons may assist with an understanding of crystal structure.

Mediumstructured2 marks

Answer

wavelength is about separation of atoms can be used in (electron) diffraction

Question 7

7

Electrons, travelling at speed v in a vacuum, are incident on a very thin carbon film, as illustrated in Fig. 7.1. The emergent electrons are incident on a fluorescent screen. A series of concentric rings is observed on the screen.

structured9 marks

Question 7(a)

7(a)

Suggest why the observed rings provide evidence for the wave nature of particles.

Mediumstructured2 marks

Answer

either if light passes through suitable film / cork dust etc. diffraction occurs and similar pattern observed or concentric circles are evidence of diffraction diffraction is a wave property

Question 7(b)

7(b)

The initial speed of the electrons is increased. State and explain the effect, if any, on the radii of the rings observed on the screen.

Mediumstructured3 marks

Answer

(speed increases so) momentum increases \(\lambda=h / p\) so \(\lambda\) decreases hence radii decrease (special case: wavelength decreases so radii decreases - scores 1/3) or (speed increases so) energy increases \(\lambda=h / \sqrt{ }(2 E m)\) so \(\lambda\) decreases hence radii decrease

Question 7(c)

7(c)

A proton and an electron are each accelerated from rest through the same potential difference. Determine the ratio \(\frac{\text { de Broglie wavelength of the proton }}{\text { de Broglie wavelength of the electron }}\). ratio =

Hardstructured4 marks

Answer

electron and proton have same (kinetic) energy either \(E=p^{2} / 2 m\) or \(p=\sqrt{ }(2 E m)\) C1 ratio \(=p_{\mathrm{e}} / p_{\mathrm{p}}=\sqrt{ }\left(m_{\mathrm{e}} / m_{\mathrm{p}}\right)\) \(=\sqrt{ }\left\{\left(9.1 \times 10^{-31}\right) /\left(1.67 \times 10^{-27}\right)\right\}\) \(=2.3 \times 10^{-2}\)

Question 7

7

Electrons, travelling at speed v in a vacuum, are incident on a very thin carbon film, as illustrated in Fig. 7.1. The emergent electrons are incident on a fluorescent screen. A series of concentric rings is observed on the screen.

structured9 marks

Question 7(a)

7(a)

Suggest why the observed rings provide evidence for the wave nature of particles.

Mediumstructured2 marks

Answer

either if light passes through suitable film / cork dust etc. diffraction occurs and similar pattern observed or concentric circles are evidence of diffraction diffraction is a wave property M1 A1 (M1) (A1) [2]

Question 7(b)

7(b)

The initial speed of the electrons is increased. State and explain the effect, if any, on the radii of the rings observed on the screen.

Mediumstructured3 marks

Answer

(speed increases so) momentum increases M1 \(\lambda=h / p\) so \(\lambda\) decreases A1 [3] (special case: wavelength decreases so radii decreases - scores 1/3) or (B1) (M1) (A1)

Question 7(c)

7(c)

A proton and an electron are each accelerated from rest through the same potential difference. Determine the ratio \(\frac{\text { de Broglie wavelength of the proton }}{\text { de Broglie wavelength of the electron }}\). ratio =

Hardstructured4 marks

Answer

electron and proton have same (kinetic) energy either \(E=p^{2 / 2 m\) or \(p=\sqrt{ }(2 E m)\) ratio \(=p_{\mathrm{e}} / p_{\mathrm{p}}=\sqrt{ }\left(m_{\mathrm{e}} / m_{\mathrm{p}}\right)\) \(=\sqrt{ }\left\{\left(9.1 \times 10^{-31}\right) /\left(1.67 \times 10^{-27}\right)\right\}\) \(=2.3 \times 10^{-2}\)} C1 C1 C1 A1 [4]

Question 8

8

\(8 \mathrm{~A} \pi^{0}\) meson is a sub-atomic particle. A stationary \(\pi^{0}\) meson, which has mass \(2.4 \times 10^{-28} \mathrm{~kg}\), decays to form two \(\gamma\)-ray photons. The nuclear equation for this decay is

structured2 marks

Question 8(b)

8(b)

Determine, for each \(\gamma\)-ray photon,

structured2 marks

Question 8(b)(ii)

8(b)(ii)

the wavelength, wavelength = m

Mediumstructured2 marks

Answer

\(E=h c / \lambda\) \(\lambda=\left(6.63 \times 10^{-34} \times 3.0 \times 10^{8}\right) /\left(1.08 \times 10^{-11}\right) \quad \mathrm{C} 1\)

Question 7

7

1 marks

Question 7(a)

7(a)

State an effect, one in each case, that provides evidence for

structured1 marks

Question 7(a)(i)

7(a)(i)

the wave nature of a particle,

Mediumstructured1 marks

Answer

e.g. electron / particle diffraction B1 [1]

Question 8

8

7 marks

Question 8(a)

8(a)

State the formula for the de Broglie wavelength \(\lambda\) of a moving particle. State the meaning of any other symbol used.

Easystructured2 marks

Answer

\(\lambda=\frac{\mathrm{h}}{\mathrm{p}}\) or \(\lambda=\frac{\mathrm{h}}{\mathrm{mv}}\) M1 where h is the Planck constant and p is the momentum (of particle) / m v is the momentum (of particle) / m is the mass (of particle) and v is the velocity (of particle) A1

Question 8(b)

8(b)

Electrons accelerate through a potential difference, pass through a thin crystal and are then incident on a fluorescent screen. The pattern in Fig. 8.1 is observed on the fluorescent screen.

structured5 marks

Question 8(b)(i)

8(b)(i)

State the name of the phenomenon shown by the electrons at the crystal.

Easystructured1 marks

Answer

(electron) diffraction B1

Question 8(b)(ii)

8(b)(ii)

State what this phenomenon shows about the nature of electrons.

Easystructured1 marks

Answer

moving electrons behave like waves B1

Question 8(b)(iii)

8(b)(iii)

Suggest why the thin crystal causes the phenomenon in (b)(i).

Mediumstructured1 marks

Answer

spacing between atoms \(\approx\) wavelength of electron or diameter of atom ⟹ wavelength of electron B1

Question 8(b)(iv)

8(b)(iv)

The electron is accelerated through a different potential difference. The new pattern observed on the screen is shown in Fig. 8.2. State and explain the change that has been made to the potential difference to create the pattern shown in Fig. 8.2.

Hardstructured2 marks

Answer

Any one of: - wavelength has decreased - electron had greater momentum M1 so (accelerating) p.d. was increased A1

Question 7

7

9 marks

Question 7(a)

7(a)

State what is meant by the de Broglie wavelength.

Easystructured1 marks

Answer

wavelength associated with a moving particle B1

Question 7(b)

7(b)

Fig. 7.1 shows a glass tube in which electrons are accelerated through a high p.d. to form a beam that is incident on a thin graphite crystal. After passing through the graphite crystal, the electrons reach the fluorescent screen. The screen glows where the electrons strike it. Fig. 7.2 shows the fluorescent screen viewed end-on, from the right-hand side of Fig. 7.1.

structured3 marks

Question 7(b)(i)

7(b)(i)

State the name of the phenomenon demonstrated by the pattern shown in Fig. 7.2.

Easystructured1 marks

Answer

(electron) diffraction B1

Question 7(b)(ii)

7(b)(ii)

Explain what can be concluded from the pattern in Fig. 7.2 about the nature of electrons.

Mediumstructured2 marks

Answer

beam spreads out indicating diffraction or light and dark regions indicate an interference pattern B1 electron beam is behaving as a wave B1

Question 7(c)

7(c)

The electrons in (b) are now accelerated through a greater potential difference between the cathode and the anode.

structured5 marks

Question 7(c)(i)

7(c)(i)

On Fig. 7.3, sketch the pattern that is now seen on the fluorescent screen in Fig. 7.1.

Mediumstructured2 marks

Answer

central blob and concentric rings B1 rings closer together (than previously) B1

Question 7(c)(ii)

7(c)(ii)

Explain, with reference to de Broglie wavelength, the change in the pattern on the fluorescent screen.

Mediumstructured3 marks

Answer

(greater p.d. so) electrons to have greater momentum B1 greater momentum so decrease in (de Broglie) wavelength B1 lower (de Broglie) wavelength (for same grating spacing in crystal) causes: smaller diffraction angle or smaller angle of intensity maxima (for each order) or decrease in fringe spacing in diffraction pattern B1

Question 8

8

6 marks

Question 8(a)

8(a)

State one piece of experimental evidence for:

structured2 marks

Question 8(a)(i)

8(a)(i)

the particulate nature of electromagnetic radiation

Easystructured1 marks

Answer

photoelectric effect B1

Question 8(a)(ii)

8(a)(ii)

the wave nature of matter.

Easystructured1 marks

Answer

electron diffraction B1

Question 8(b)

8(b)

4 marks

Question 8(b)(i)

8(b)(i)

Calculate the de Broglie wavelength \(\lambda\) of an alpha-particle moving at a speed of \(6.2 \times 10^{7} \mathrm{~m} \mathrm{~s}^{-1}\).

Mediumstructured2 marks

Answer

\(\lambda=h / p\) C1 \[ \begin{aligned} p =4 \times 1.66 \times 10^{-27} \times 6.2 \times 10^{7} \left.=4.1 \times 10^{-19} \mathrm{~N} \mathrm{~s}\right) \end{aligned} \] C1 \[ \begin{aligned} \lambda =6.63 \times 10^{-34} / 4.1 \times 10^{-19} =1.6 \times 10^{-15} \mathrm{~m} \end{aligned} \] A1

Question 8(b)(ii)

8(b)(ii)

The speed v of the alpha-particle in (b)(i) is gradually reduced to zero. On Fig. 8.1, sketch the variation with v of \(\lambda\).

Mediumstructured2 marks

Answer

line with negative gradient throughout B1 curve asymptotic to both axes with non-zero \(\lambda\) at \(v=6.2 \times 10^{7} \mathrm{~m} \mathrm{~s}^{-1}\) B1