Track Energy Through the System
Energy conservation starts with the chosen system. If the system is isolated, the total energy inside it stays constant even though energy can move between kinetic, gravitational potential, elastic, thermal, chemical, or internal stores. If the system is not isolated, energy may enter or leave by work done, heating, radiation, or electrical transfer. IB answers should avoid saying energy is lost. A better phrase is that energy is transferred or dissipated to the surroundings, often becoming less useful for the intended process.
Choose the conserved quantity after checking the system boundary.
DecisionFor a described process, define the system and explain how energy is conserved while changing stores or crossing the boundary.
IB questions often ask why energy is not “lost” when mechanical energy decreases; the expected answer names the transfer to other stores or surroundings.
Energy is conserved overall. Within an isolated system, total energy remains constant while energy transfers between stores. If the chosen system is not isolated, energy may cross the boundary by work, heating, radiation, or electrical transfer, so include those transfers in the accounting.
Claiming that energy is lost, or saying a single store such as kinetic energy is conserved without checking the process.
For a described process, define the system and explain how energy is conserved while changing stores or crossing the boundary.
ChooseMake Work an Energy Transfer
Work is not a new energy store; it is a way energy is transferred. A force does work only when the object has a displacement and the force has a component along that displacement. For a constant force, W = Fs cosθ. Positive work transfers energy into the object or chosen system; negative work transfers energy out of it or reduces a mechanical energy store. A perpendicular force, such as ideal centripetal force in uniform circular motion, does no work because cos90° = 0.
Build the work-done relation and decide the sign from the angle.
FormulaExplain or calculate the work done by a force, including the direction of energy transfer.
IB questions often test the angle between force and displacement, sign of work, and the phrase “energy transfer”.
Work done by a constant force is W = Fs cosθ, where θ is the angle between force and displacement. It represents energy transferred by the force. Work is positive if the force component is along the displacement, negative if opposite, and zero if perpendicular.
Using F s without resolving the force, or saying work is done when there is no displacement in the force direction.
Explain or calculate the work done by a force, including the direction of energy transfer.
ChooseRead the Sankey Diagram
Sankey diagrams are visual energy accounts. The width of each arrow represents the amount of energy transferred, or sometimes the power flow if the diagram is per unit time. The total input must equal the total output when all pathways are included. Useful output is the energy transferred into the intended store or pathway; dissipated output is energy transferred to less useful stores, often thermal energy of the surroundings. Read the diagram by comparing widths or labelled values, not by the physical length of an arrow.
Label the Sankey arrows and use their widths as the energy account.
LabelUse a Sankey diagram to identify input, useful output, dissipated output, and the energy or power represented by arrow widths.
IB questions may ask for useful output, wasted/dissipated transfer, efficiency, or whether the diagram satisfies conservation of energy.
Read the Sankey diagram by arrow width. The input equals the sum of all output arrows. Useful output is the intended pathway; dissipated energy is transferred to less useful stores such as thermal energy of the surroundings.
Reading arrow length instead of width, or ignoring a dissipated branch when calculating output totals.
Use a Sankey diagram to identify input, useful output, dissipated output, and the energy or power represented by arrow widths.
ChooseWork by constant force
This calculation card is about choosing the correct component and area. If force is constant and parallel to displacement, work is simply force times displacement. If the force is angled, first resolve it along the displacement, F_parallel = F cosθ, then multiply by s. A constant-force graph against displacement gives a rectangular area, so W is the area under the F_parallel-s graph. When the force opposes displacement, the work done by that force is negative.
Build the constant-force work calculation from component and displacement.
FormulaA constant force moves an object through a displacement. Calculate the work done and interpret it from a force-displacement graph.
IB questions may include angled forces, friction, or force-displacement graphs where the area represents work done.
Resolve the constant force along the displacement, then multiply by displacement: W = F_parallel s = Fs cosθ. On a force-displacement graph, this is the signed area under the graph.
Using the full force instead of the parallel component, or missing negative work for a force opposite displacement.
A constant force moves an object through a displacement. Calculate the work done and interpret it from a force-displacement graph.
ChooseWork-energy change
The work-energy idea turns a force-and-displacement problem into an energy-change problem. For one object, the net or resultant work is equal to the change in kinetic energy, W_net = ΔE_k = E_k,final - E_k,initial. For a broader system, work done across the boundary transfers energy into or out of the system and may change gravitational, elastic, thermal, or kinetic stores. This is why the setup matters: identify the system, decide whether you are using resultant work or work by a named force, then name the energy store being changed.
Spot and repair the setup errors before using the work-energy relation.
Spot ErrorsUse the work-energy theorem to relate work done by the resultant force to the change in kinetic energy, or explain energy changes for a chosen system.
IB questions often ask students to find speed from work done, or to explain why a named force’s work is not the same as net work.
For a single object, the net work done by all forces equals the change in kinetic energy: W_net = ΔE_k. If several forces do work, add their signed work terms. For a wider system, work crossing the boundary changes the system’s energy stores.
Equating one force’s work with ΔE_k when other forces also do work, or reversing final and initial energy.
Use the work-energy theorem to relate work done by the resultant force to the change in kinetic energy, or explain energy changes for a chosen system.
ChooseMechanical energy
Mechanical energy is a useful subset of total energy. It includes kinetic energy plus potential energy stores that can be converted mechanically, mainly gravitational potential and elastic potential in A.3. Use E_k = 1/2mv^2 for motion, E_p = mgh for height changes near Earth with constant g, and E_el = 1/2kx^2 for Hooke’s-law springs. If friction, drag, heating, or deformation is important, some mechanical energy is transferred into non-mechanical stores, so total mechanical energy may not be conserved.
Match each mechanical energy store to its expression and situation.
MatchIdentify the mechanical energy stores in a situation and write the expression for total mechanical energy.
IB questions may ask students to write an energy equation, so the first mark is often choosing the correct stores.
The total mechanical energy for this A.3 system is the sum of kinetic, gravitational potential, and elastic potential stores: E_mech = E_k + E_p + E_el, using 1/2mv^2, mgh, and 1/2kx^2 where the conditions apply.
Treating mechanical energy as total energy and ignoring thermal/internal energy produced by friction.
Identify the mechanical energy stores in a situation and write the expression for total mechanical energy.
ChooseMechanical energy conservation
PracticeUse mechanical energy conservation only after checking the model conditions. If gravity and ideal springs are the only forces doing work, energy can transfer between kinetic, gravitational potential, and elastic potential stores without changing their total. If friction, air resistance, an external motor, or deformation is significant, mechanical energy changes because energy transfers into or out of non-mechanical stores. Then write an energy account with an added dissipated or external work term instead of forcing mechanical energy to be constant.
Decide whether mechanical energy is conserved in each situation.
DecisionState whether mechanical energy is conserved in a described system and write the appropriate energy equation.
IB questions often hide the condition in words like “frictionless”, “negligible air resistance”, “rough”, or “constant speed motor”.
If friction and other dissipative transfers are negligible, E_k + E_p + E_el is conserved between initial and final states. If friction, drag, or external work is significant, include a dissipated-energy or work term rather than setting mechanical energies equal.
Using mechanical energy conservation despite friction or drag, or saying energy is lost instead of dissipated.
State whether mechanical energy is conserved in a described system and write the appropriate energy equation.
ChooseMechanical energy transformations
Mechanical energy transformations describe which stores increase and decrease during a process. A falling object loses gravitational potential energy and gains kinetic energy. A rising object does the reverse. An ideal spring can store energy elastically and release it as kinetic energy. With friction or drag, the transformation is not purely mechanical: some mechanical energy is transferred to thermal/internal stores. When writing an energy equation, name the stores before choosing formulas.
Sort each situation by the main energy transformation.
SortDescribe the energy transformations in a mechanical process and state whether mechanical energy remains in mechanical stores.
IB questions often ask for energy-store descriptions before or after a calculation, especially with springs, falling objects, or friction.
A correct transformation sentence names both stores. For example, a falling object transfers gravitational potential energy to kinetic energy; a compressed spring transfers elastic potential energy to kinetic energy; friction transfers mechanical energy to thermal/internal energy.
Listing formulas without naming stores, or omitting the dissipated store when friction is present.
Describe the energy transformations in a mechanical process and state whether mechanical energy remains in mechanical stores.
ChooseKinetic energy
Kinetic energy depends on mass and speed, not velocity direction. Use speed in E_k = 1/2mv^2, so a negative velocity does not make negative kinetic energy. Because speed is squared, changes in speed have a large effect: twice the speed gives four times the kinetic energy. The alternative form E_k = p^2/(2m) is useful when momentum and mass are known.
Build the kinetic energy formula and check the speed-squared dependence.
FormulaCalculate kinetic energy from mass and speed, or compare kinetic energies when speed or momentum changes.
IB questions often test proportional reasoning: speed doubled means kinetic energy quadrupled, and direction signs do not make kinetic energy negative.
Kinetic energy is E_k = 1/2mv^2. Since v is speed, the value is non-negative and measured in joules. If momentum is known instead, E_k = p^2/(2m).
Using velocity sign to make kinetic energy negative, or treating E_k as proportional to v rather than v^2.
Calculate kinetic energy from mass and speed, or compare kinetic energies when speed or momentum changes.
ChooseMap Gravitational potential energy
Gravitational potential energy near Earth is a height-based energy store. Because the zero level is chosen by the solver, absolute E_p values are less important than changes. Use ΔE_p = mgΔh when g is approximately constant over the height change. Lifting an object increases E_p; lowering or falling decreases E_p and can transfer energy to kinetic or other stores. Be careful to use vertical height change, not distance travelled along a slope.
Build the gravitational potential energy change formula using vertical height change.
FormulaCalculate the change in gravitational potential energy for an object moving between two heights near Earth.
IB questions often hide the height change inside a ramp, vertical circle, or graph, so using vertical Δh is the key mark.
Near Earth, ΔE_p = mgΔh, where Δh is the vertical height change relative to a chosen reference level. Rising gives positive ΔE_p; falling gives negative ΔE_p.
Using path length instead of vertical height change, or treating the zero reference as physically fixed when only changes matter.
Calculate the change in gravitational potential energy for an object moving between two heights near Earth.
ChooseElastic potential energy
A spring stores elastic potential energy when it is stretched or compressed from its natural length. In the Hooke’s-law region, force increases linearly with extension, F = kx, so the energy stored is the triangular area under the force-extension graph: E_el = 1/2kx^2. Use x as the displacement from natural length, not the full length of the spring. Because x is squared, stretching and compressing by the same amount store the same energy, as long as the spring remains elastic.
Build the elastic potential energy expression from Hooke’s law and graph area.
FormulaCalculate the elastic potential energy stored in a spring and state the condition for using the formula.
IB questions often combine Hooke’s law with energy by using the area under a force-extension graph.
For a Hooke’s-law spring, force increases linearly with extension, so the stored elastic potential energy is the area under the force-extension graph: E_el = 1/2kx^2. The extension x is measured from natural length.
Using full spring length for x, omitting the 1/2, or using the formula beyond the proportional limit.
Calculate the elastic potential energy stored in a spring and state the condition for using the formula.
ChooseUse Energy per Time
Power tells how quickly energy is transferred. If 500 J is transferred in 10 s, the average power is 50 W. The same energy transferred in a shorter time has greater power. In mechanical problems, P = Fv is valid when F is the component of force along the motion; more generally use P = F_parallel v. Distinguish average power over a time interval from instantaneous power at a moment.
Build the power relation from energy transfer and time.
FormulaCalculate average power from energy transferred or work done over time, and apply P = Fv when a force moves at constant speed.
IB questions often compare devices doing the same work in different times, or use P = Fv for vehicles/lifts at steady speed.
Power is the rate of energy transfer: P_avg = ΔE/Δt = W/Δt. The unit is W = J s^-1. For mechanical motion, P = F_parallel v, where only the force component along the velocity counts.
Comparing power by energy alone without time, or using P = Fv when the force is not parallel to motion.
Calculate average power from energy transferred or work done over time, and apply P = Fv when a force moves at constant speed.
ChooseCompare Useful and Input Energy
Efficiency measures how much of the supplied energy or power becomes the useful output. The denominator is total input, not wasted output. The numerator is the useful output for the intended purpose. If powers are used, they must refer to the same process/time interval, so the time cancels. A realistic device has efficiency less than 1 or less than 100% because some energy is dissipated to less useful stores.
Build the efficiency ratio from useful output and total input.
FormulaCalculate the efficiency of a device from useful output and total input energy or power.
IB questions commonly give Sankey diagrams or input/output powers and require a fraction or percentage efficiency.
Efficiency is useful output divided by total input. It may be calculated from energies or powers: η = E_useful/E_input = P_useful/P_input. As a percentage, multiply the fraction by 100%.
Using wasted output as the numerator, using total output rather than useful output, or mixing energy and power in one ratio.
Calculate the efficiency of a device from useful output and total input energy or power.
ChooseCompare Energy per Fuel Mass
This card compares how much energy different fuels release for the same mass. If a fuel has a value in J kg^-1, multiply by the fuel mass in kg to find total energy released. Convert MJ kg^-1 to J kg^-1 when needed. A high energy-per-mass fuel is useful when mass matters, but it does not automatically mean the device using it is efficient or powerful; efficiency depends on useful output divided by input, and power depends on time.
Build the energy-per-mass comparison for a fuel.
FormulaCompare two fuels using energy released per unit mass, or calculate energy released from a given fuel mass.
IB questions may give a table of fuel values in MJ kg^-1 and ask for comparison, total energy, or useful output after efficiency.
Energy per unit mass is E/m with units J kg^-1. For a fuel mass m, E = (energy per mass)m. This compares fuels by mass; efficiency and power are separate quantities unless the question includes them.
Using grams with J kg^-1 without conversion, or assuming the fuel with higher energy per mass has higher efficiency.
Compare two fuels using energy released per unit mass, or calculate energy released from a given fuel mass.
ChooseRetrieve the A.3 Work, energy and power Model
ReviewA.3 is an energy-accounting topic. Start by choosing the system and the energy stores. If the question gives a force and displacement, use work. If it gives before/after speeds, heights, or springs, choose the relevant energy stores. If it gives time, use power. If it gives useful and input pathways, use efficiency. If it compares fuels, use energy per unit mass. The strongest IB answers state the model condition before the arithmetic.
Match each A.3 trigger to the model move it should trigger before calculation.
MatchA mixed A.3 problem includes a device, motion, or fuel data. State the model choice and condition before calculating.
A.3 marks usually reward choosing the right energy account before substituting: store changes, work terms, time rates, useful ratios, or fuel mass basis.
Begin with the system boundary and the requested quantity. Use work for force through displacement, mechanical energy when stores change, power for rate of energy transfer, efficiency for useful over input, and fuel energy per mass for fuel comparisons.
Using a memorized formula without checking whether the question asks for energy, rate, useful fraction, or energy per mass.
A mixed A.3 problem includes a device, motion, or fuel data. State the model choice and condition before calculating.
Choose