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IB Physics HL/Notes/A.5 Galilean and special relativity

IB Physics HLA.5 Galilean and special relativityNotes

Anchor Reference frames

A frame is not just an observer; it is the coordinate axes and synchronized clocks that observer uses to label events. Galilean and special relativity compare descriptions made in different inertial frames. The restriction to inertial frames matters because the standard transformation equations assume constant relative velocity, not acceleration or rotation.

A reference frame is a coordinate system plus clocks used by an observer to describe where and when events occur.
An inertial reference frame is not accelerating; Newton’s laws hold without adding fictitious forces.
A frame moving at constant velocity relative to another inertial frame is also inertial.
A non-inertial frame accelerates or rotates; observers in it may need extra apparent forces to explain motion.
In relativity questions, always state which frame measures each position, time interval, length, or velocity.

Compare inertial and non-inertial reference frames before choosing a relativity model.

Compare
A
inertial reference frame
B
non-inertial reference frame
whether the frame accelerates or rotates
whether Newton’s laws hold without fictitious forces
whether standard Galilean/Lorentz transformations apply directly

Define a reference frame and explain why an inertial reference frame is required when using Galilean or Lorentz transformations.

Common mark losses are describing only an observer, forgetting clocks/coordinates, or using transformation equations in an accelerating frame.

Define a reference frame and explain why an inertial reference frame is required when using Galilean or Lorentz transformations.

Choose

Read Galilean relativity

Imagine a smooth train moving at constant velocity. A ball thrown inside the train follows Newton’s laws just as it would on the platform, even though platform and train observers assign different velocities to the ball. This is the idea of Galilean relativity: uniform motion is relative, while the laws of mechanics are the same in every inertial frame. The model assumes absolute time, which special relativity later replaces.

Galilean relativity states that Newton’s laws of motion have the same form in all inertial reference frames.
No mechanical experiment performed inside an inertial frame can identify that frame as absolutely at rest.
Different inertial observers can measure different positions and velocities for the same event or object.
In Galilean relativity, time is absolute: all inertial observers agree on the time interval between events.
The Galilean model works for ordinary speeds but fails for light and for speeds that are a significant fraction of c.

Compare the Galilean relativity view with the absolute-rest misconception.

Compare
A
Galilean relativity
B
absolute-rest misconception
whether Newton’s laws hold in every inertial frame
whether one inertial frame is physically privileged by mechanics
whether time is treated as common to all inertial frames

Explain Galilean relativity using two inertial observers moving at constant relative velocity. Include what is frame-dependent and what is the same.

Common mark losses are saying all measured quantities are identical, forgetting the inertial-frame condition, or treating one frame as absolutely at rest.

Explain Galilean relativity using two inertial observers moving at constant relative velocity. Include what is frame-dependent and what is the same.

Choose

Galilean transformations

Define the frames before substituting: S is the reference frame in which x and t are measured, and S′ is moving relative to S. The term vt is the displacement of the S′ origin as measured in S, so subtract it to locate the event relative to S′. Because Galilean relativity assumes the same time in all inertial frames, t′ = t. If the relative direction is defined differently, the sign changes.

A Galilean transformation relates the coordinates of the same event in two inertial frames.
If S′ moves at speed v in the +x direction relative to S and origins coincide at t = 0, then x′ = x - vt and t′ = t.
The inverse transformation is x = x′ + vt and t = t′.
Coordinates perpendicular to the relative motion are unchanged in this simple one-dimensional setup.
The transformation assumes absolute time and is valid for low speeds compared with c.

Build the Galilean coordinate transformation.

Formula
Target formula x′ = x - vt; t′ = t; inverse: x = x′ + vt
x
event position measured in frame S
m
x′
event position measured in frame S′
m
v
velocity of S′ relative to S along +x
m s^-1
t
event time measured in S
s
t′
event time measured in S′
s
1Define which frame is moving and the positive x direction.S′ moves +v relative to S
2Find the displacement of the S′ origin in S after time t.vt
3Subtract that origin shift from x to get x′.x′ = x - vt
4Use absolute time in Galilean relativity.t′ = t
5Reverse the transformation if converting from S′ to S.x = x′ + vt

Frame S′ moves at speed v in the +x direction relative to S. State the Galilean transformations for x and t, and identify one assumption behind them.

Common mark losses are using the wrong sign for vt, forgetting to define the frame motion, or applying Galilean transformations at speeds close to c.

Frame S′ moves at speed v in the +x direction relative to S. State the Galilean transformations for x and t, and identify one assumption behind them.

Choose

Galilean velocity addition

Velocity addition compares the same object as measured in two inertial frames. If the moving frame S′ is travelling in the positive direction relative to S, an object’s velocity measured in S′ is its S-frame velocity minus the frame velocity. Use signs carefully: an object moving opposite the positive direction has a negative velocity. At relativistic speeds this formula can wrongly predict speeds greater than c, so it must be replaced by the relativistic velocity addition formula.

For S′ moving at speed v in the +x direction relative to S, the object velocity in S′ is u′ = u - v.
The inverse relation is u = u′ + v.
Velocities are signed; choose the positive direction before substituting.
This relation follows from x′ = x - vt and t′ = t, so it assumes constant relative velocity and absolute time.
Galilean velocity addition is valid at low speeds but fails near the speed of light.

Build the Galilean velocity addition relation.

Formula
Target formula u′ = u - v; inverse: u = u′ + v
u
object velocity measured in S
m s^-1
u′
object velocity measured in S′
m s^-1
v
velocity of S′ relative to S
m s^-1
1Choose the positive x direction and assign signs to all velocities.signed u, u′, v
2State that S′ moves at +v relative to S.S′ relative to S = +v
3Subtract the frame velocity to get the velocity in S′.u′ = u - v
4Use the inverse relation when converting from S′ to S.u = u′ + v
5Check whether a relativistic formula is needed.only for speeds much less than c

State the Galilean velocity addition equation for S′ moving at +v relative to S, and explain why the equation is not used for light.

Common mark losses are using unsigned speeds, reversing the sign of v, or applying Galilean velocity addition to light or speeds close to c.

State the Galilean velocity addition equation for S′ moving at +v relative to S, and explain why the equation is not used for light.

Choose

Read Two postulates of special relativity

The first postulate extends the Galilean idea beyond mechanics: all laws of physics keep the same form in inertial frames. The second postulate is the new ingredient: light in vacuum is measured to travel at c by every inertial observer. To keep both postulates true, space and time measurements must transform with Lorentz transformations rather than Galilean transformations.

Postulate 1: The laws of physics have the same form in all inertial reference frames.
Postulate 2: The speed of light in vacuum is c for all inertial observers, regardless of the motion of the source or observer.
Special relativity applies to inertial frames; it does not describe accelerating frames without extra work.
The constant speed of light conflicts with Galilean velocity addition for light.
Time intervals, lengths, and simultaneity can be frame-dependent consequences of these postulates.

Match each special relativity cue to its postulate or consequence.

Match
Reasons
0/5

State the two postulates of special relativity and explain why they require a replacement for Galilean velocity addition at high speeds.

Common mark losses are omitting “inertial”, forgetting “vacuum” for c, or saying the speed of light depends on source speed.

State the two postulates of special relativity and explain why they require a replacement for Galilean velocity addition at high speeds.

Choose

Read Lorentz transformations

Use Lorentz transformations when relative speeds are a significant fraction of c and the frames are inertial. Define which frame is moving before choosing signs. Unlike Galilean transformations, time is mixed with position, so two events that have the same time in one frame may not have the same time in another. The transformations preserve the speed of light and the spacetime interval.

Lorentz transformations relate the coordinates of the same event measured in two inertial frames.
For S′ moving at speed v in the +x direction relative to S: x′ = γ(x - vt) and t′ = γ(t - vx/c^2).
The Lorentz factor is γ = 1/sqrt(1 - v^2/c^2), so γ is always at least 1.
The inverse transformation changes the sign of v: x = γ(x′ + vt′) and t = γ(t′ + vx′/c^2).
When v is much smaller than c, γ ≈ 1 and the Lorentz transformations reduce to the Galilean form.

Build the Lorentz coordinate transformation.

Formula
Target formula γ = 1/sqrt(1 - v^2/c^2); x′ = γ(x - vt); t′ = γ(t - vx/c^2)
γ
Lorentz factor
x
event position in S
m
t
event time in S
s
x′
event position in S′
m
t′
event time in S′
s
v
velocity of S′ relative to S
m s^-1
c
speed of light in vacuum
m s^-1
1State which frame moves and the positive direction.S′ moves +v relative to S
2Identify that x,t and x′,t′ refer to the same event.one event, two frames
3Calculate or identify the Lorentz factor.γ = 1/sqrt(1 - v^2/c^2)
4Transform position.x′ = γ(x - vt)
5Transform time.t′ = γ(t - vx/c^2)

For S′ moving at speed v in the +x direction relative to S, state the Lorentz transformations for x′ and t′ and define γ.

Common mark losses are using Galilean time t′ = t, omitting γ, or not defining which event and frame are being transformed.

For S′ moving at speed v in the +x direction relative to S, state the Lorentz transformations for x′ and t′ and define γ.

Choose

Read Relativistic velocity addition

Relativistic velocity addition replaces u′ = u - v when speeds are high. The denominator prevents inertial observers from measuring an object or light signal above c. Define which frame is moving and use signs consistently before substituting. The one-dimensional formula here is for velocities along the relative motion direction.

For S′ moving at speed v in the +x direction relative to S, the velocity measured in S′ is u′ = (u - v)/(1 - uv/c^2).
The inverse relation is u = (u′ + v)/(1 + u′v/c^2).
Use signed velocities along the same line; opposite directions must be negative.
If u = c, the transformed speed is still c, matching the second postulate of special relativity.
When speeds are much less than c, the denominator is approximately 1 and the formula reduces to Galilean velocity addition.

Build the relativistic velocity addition relation.

Formula
Target formula u′ = (u - v)/(1 - uv/c^2); inverse: u = (u′ + v)/(1 + u′v/c^2)
u
object velocity measured in S
m s^-1
u′
object velocity measured in S′
m s^-1
v
velocity of S′ relative to S
m s^-1
c
speed of light in vacuum
m s^-1
1Define S, S′, positive direction, and relative velocity v.S′ moves +v relative to S
2Assign signs to u and v along the same line.signed velocities
3Use the Galilean-looking numerator.u - v
4Add the relativistic correction denominator.1 - uv/c^2
5Check that c stays c and low speeds reduce to Galilean addition.u = c gives u′ = c; uv/c^2 ≈ 0 gives u′ ≈ u - v

State the relativistic velocity addition formula for S′ moving at +v relative to S, and explain one way it differs from Galilean velocity addition.

Common mark losses are using u′ = u - v at relativistic speeds, losing velocity signs, or putting the wrong sign in the denominator.

State the relativistic velocity addition formula for S′ moving at +v relative to S, and explain one way it differs from Galilean velocity addition.

Choose

Read Space-time interval

Special relativity allows different observers to disagree about the time separation and space separation of two events, but they agree on the spacetime interval. Calculate the interval from coordinate differences, not from a single coordinate. A light signal has (Δs)^2 = 0 because it travels Δx = cΔt. Timelike events can be causally connected; spacelike-separated events cannot influence each other without exceeding c.

The spacetime interval is calculated between two events, using differences Δt and Δx.
With the convention used here, (Δs)^2 = (cΔt)^2 - (Δx)^2 for one-dimensional motion.
The spacetime interval is invariant: all inertial observers calculate the same (Δs)^2 for the same pair of events.
If (Δs)^2 > 0 the interval is timelike; if (Δs)^2 = 0 it is lightlike; if (Δs)^2 < 0 it is spacelike.
Use units consistently: cΔt and Δx must both be in metres, so (Δs)^2 has units m^2.

Build the spacetime interval calculation.

Formula
Target formula (Δs)^2 = (cΔt)^2 - (Δx)^2
(Δs)^2
spacetime interval squared
m^2
c
speed of light in vacuum
m s^-1
Δt
time separation between the two events
s
Δx
space separation between the two events along x
m
1Identify the same two events in the frame.event 1 and event 2
2Calculate coordinate differences, not absolute coordinates.Δt and Δx
3Convert cΔt and Δx to the same distance units.cΔt in m
4Calculate the interval squared.(Δs)^2 = (cΔt)^2 - (Δx)^2
5Classify the interval by sign.>0 timelike, =0 lightlike, <0 spacelike

For two events separated by Δx and Δt in an inertial frame, state the spacetime interval formula used here and explain what it means for the interval to be invariant.

Common mark losses are using coordinates instead of coordinate differences, missing the factor c, or forgetting that the sign convention must be consistent.

For two events separated by Δx and Δt in an inertial frame, state the spacetime interval formula used here and explain what it means for the interval to be invariant.

Choose

Proper time interval and proper length

Proper quantities are not automatically the values measured by the observer in the question. Proper time belongs to the frame where the start and end events happen at one place, so one clock can time both events. Proper length belongs to the frame where the object is at rest. Once the proper quantity is identified, time dilation and length contraction formulae can be applied in the following cards.

Proper time interval Δt0 is measured by a clock at rest relative to both events; the two events occur at the same position in that clock’s frame.
Proper length L0 is the length measured in the rest frame of the object.
A moving clock is observed to have a longer time interval: Δt = γΔt0.
A moving object is observed to have a shorter length along the direction of motion: L = L0/γ.
Before using a formula, decide which frame measures the proper quantity.

Compare proper time and proper length before choosing a relativity formula.

Compare
A
proper time interval Δt0
B
proper length L0
whether two events occur at the same position in the measuring frame
whether the object is at rest in the measuring frame
which later formula uses the quantity as the proper value

Define proper time interval and proper length, and state how each proper quantity is identified from the measuring frame.

Common mark losses are calling any measured value “proper” without checking whether the events occur at the same place or the object is at rest.

Define proper time interval and proper length, and state how each proper quantity is identified from the measuring frame.

Choose

Time dilation

First identify the two events being timed, such as creation and decay of a particle or two ticks of a moving clock. The proper time is measured by a clock at rest with those events, so the events happen at one position in that clock’s frame. Other inertial observers who see the clock moving measure a longer interval by the factor γ.

Time dilation relates a proper time interval to a longer time interval measured in another inertial frame: Δt = γΔt0.
Δt0 is the proper time measured in the frame where the two events occur at the same position.
γ = 1/sqrt(1 - v^2/c^2), so γ ≥ 1 and Δt ≥ Δt0.
A moving clock is observed to run slow: more time passes in the observer frame between ticks of the moving clock.
Use relative speed v between the clock’s rest frame and the observer frame.

Build the time dilation relation.

Formula
Target formula Δt = γΔt0; γ = 1/sqrt(1 - v^2/c^2)
Δt
dilated time interval measured in the observer frame
s
Δt0
proper time interval
s
γ
Lorentz factor
v
relative speed between frames
m s^-1
c
speed of light in vacuum
m s^-1
1Identify the two events being timed.event 1 and event 2
2Find the frame where both events occur at the same position.this frame measures Δt0
3Calculate γ from the relative speed.γ = 1/sqrt(1 - v^2/c^2)
4Multiply the proper time by γ.Δt = γΔt0
5Check that the dilated time is not smaller than the proper time.Δt ≥ Δt0

A particle has a lifetime Δt0 in its own rest frame and moves at speed v relative to the laboratory. State the lifetime measured in the laboratory and explain which interval is proper.

Common mark losses are swapping Δt and Δt0, forgetting γ, or identifying the proper time without checking where the two events occur at the same position.

A particle has a lifetime Δt0 in its own rest frame and moves at speed v relative to the laboratory. State the lifetime measured in the laboratory and explain which interval is proper.

Choose

Length contraction

First identify the object’s rest frame; the length measured there is L0. An observer who sees the object moving measures a shorter length along the motion direction by L = L0/γ. The simultaneity condition matters: to measure a moving object’s length, the observer must record both endpoints at the same time in their own frame.

Length contraction relates the proper length to the shorter length measured in a frame where the object is moving: L = L0/γ.
L0 is the proper length measured in the rest frame of the object.
γ = 1/sqrt(1 - v^2/c^2), so γ ≥ 1 and L ≤ L0.
Contraction occurs only along the direction of relative motion; perpendicular dimensions are unchanged.
A length measurement in any frame requires the positions of both ends to be recorded at the same time in that frame.

Build the length contraction relation.

Formula
Target formula L = L0/γ; γ = 1/sqrt(1 - v^2/c^2)
L
contracted length measured in the moving-object frame
m
L0
proper length or rest length
m
γ
Lorentz factor
v
relative speed between object and observer
m s^-1
c
speed of light in vacuum
m s^-1
1Identify the frame in which the object is at rest.this frame measures L0
2Check the length component is along the direction of motion.contract only parallel length
3Ensure the moving length is measured by simultaneous endpoint positions in the observer frame.same time in observer frame
4Calculate γ from relative speed.γ = 1/sqrt(1 - v^2/c^2)
5Divide proper length by γ.L = L0/γ

A spacecraft of rest length L0 moves at speed v past an observer. State the length measured by the observer and explain what must be simultaneous in that observer’s frame.

Common mark losses are swapping L and L0, contracting dimensions perpendicular to motion, or forgetting that endpoints must be measured simultaneously in the observer frame.

A spacecraft of rest length L0 moves at speed v past an observer. State the length measured by the observer and explain what must be simultaneous in that observer’s frame.

Choose

Read Relativity of simultaneity

Lorentz transformations mix time and position, so two events with the same time coordinate in one frame can have different time coordinates in another frame. The key condition is spatial separation along the direction of relative motion. This is why length contraction measurements require simultaneous endpoint positions in the measuring frame: simultaneity itself is frame-dependent.

Events that are simultaneous in one inertial frame need not be simultaneous in another inertial frame moving relative to it.
The effect matters for spatially separated events; if Δt = 0 but Δx ≠ 0 in S, then Δt′ = -γvΔx/c^2 for S′ moving at +v.
Relativity of simultaneity is not a light-travel-time illusion; it remains after each frame corrects for signal travel time using its own synchronized clocks.
For spacelike-separated events, different inertial frames can disagree about the time order.
Causally connected timelike or lightlike events cannot have their causal order reversed.

Repair the simultaneity misconceptions.

Spot Errors

Two events occur simultaneously in frame S but at different positions along the x-axis. Explain why they need not be simultaneous in frame S′ moving relative to S.

Common mark losses are describing only light travel time, forgetting that the events must be spatially separated, or claiming causal order can be reversed for timelike events.

Two events occur simultaneously in frame S but at different positions along the x-axis. Explain why they need not be simultaneous in frame S′ moving relative to S.

Choose

Read Space-time diagrams

Read a spacetime diagram as a map of events, not as a normal position-time graph. The vertical coordinate is often ct, not just t, so the slope/angle interpretation differs from a standard x-t graph. Timelike world lines for massive objects stay inside the light lines, while light itself follows the 45° boundary.

A spacetime diagram plots position x on the horizontal axis and time as ct on the vertical axis, so both axes can use metres.
A point on the diagram represents an event: something happening at a particular position and time.
A world line shows the history of an object through spacetime.
A stationary object has a vertical world line at constant x.
Light travels on 45° lines when the axes are x and ct because |x| = ct.

Label the core features of a spacetime diagram.

Label
Labels
5

Describe the meaning of an event, a world line, and a 45° line on an x-ct spacetime diagram.

Common mark losses are treating ct as ordinary t without units, or reading a spacetime diagram exactly like a displacement-time graph.

Describe the meaning of an event, a world line, and a 45° line on an x-ct spacetime diagram.

Choose

Read World lines and speed

Be precise about the angle or gradient being used. The IB-style relation tanθ = v/c uses θ measured from the ct-axis, not from the x-axis. For a plotted line, the gradient is Δ(ct)/Δx = c/v, so a steeper line actually means a smaller speed. Massive particles must have world lines inside the light lines, so their angle from the ct-axis is less than 45°.

On an x-ct diagram, a straight world line represents constant velocity.
If θ is the angle between the world line and the ct-axis, then tanθ = v/c.
A vertical world line has v = 0; a 45° light line has v = c.
The greater the tilt away from the ct-axis, the greater the speed.
If using graph gradient with ct on the vertical axis and x on the horizontal axis, gradient = c/v.

Build the speed relation from a spacetime world-line angle.

Formula
Target formula tanθ = v/c; gradient = c/v
θ
angle between world line and ct-axis
v
particle speed
m s^-1
c
speed of light in vacuum
m s^-1
gradient
Δ(ct)/Δx on the x-ct graph
1Check that the graph uses x horizontally and ct vertically.x-ct diagram
2Measure θ from the ct-axis to the world line.θ
3Use the angle relation to find speed.v = c tanθ
4If using gradient instead, invert it correctly.gradient = c/v
5Check that massive particles stay below c.0 ≤ θ < 45° for v < c

On an x-ct spacetime diagram, a particle world line makes an angle θ with the ct-axis. State how to determine the particle speed and explain what a 45° line represents.

Common mark losses are measuring θ from the wrong axis, using ordinary displacement-time gradient rules, or giving a massive particle a speed greater than c.

On an x-ct spacetime diagram, a particle world line makes an angle θ with the ct-axis. State how to determine the particle speed and explain what a 45° line represents.

Choose

Track Muon decay evidence

The muon experiment is powerful because the same observation can be explained consistently in two frames. Earth observers say fast muon clocks run slow, increasing the observed lifetime. Muons say their own lifetime is normal, but the atmosphere is moving toward them and is contracted along the direction of motion. The agreement between these explanations supports the Lorentz transformation model.

Muons are produced high in the atmosphere and travel toward Earth at speeds close to c.
Classically, their short proper lifetime would allow too few muons to reach the surface.
In Earth’s frame, the moving muon lifetime is dilated: Δt = γΔt0, so muons travel farther before decaying.
In the muon’s frame, the muon lifetime is proper, but the distance through the atmosphere is length-contracted: L = L0/γ.
Both frames agree on the physical outcome: more muons reach the surface than a non-relativistic prediction allows.

Compare the Earth-frame and muon-frame explanations.

Compare
A
Earth frame explanation
B
muon frame explanation
which time interval or length is proper
which relativistic effect is used
what both frames predict about muons reaching the surface

Explain how the observation of atmospheric muons at Earth’s surface supports special relativity, giving both the Earth-frame and muon-frame descriptions.

Common mark losses are giving only one frame, saying the muon lifetime is longer in its own rest frame, or forgetting that both frames must agree on the detection outcome.

Explain how the observation of atmospheric muons at Earth’s surface supports special relativity, giving both the Earth-frame and muon-frame descriptions.

Choose

Retrieve the A.5 Galilean and special relativity Model

Review

A.5 is mostly a frame-selection topic. Decide whether the situation is low-speed Galilean or high-speed relativistic, then identify the proper quantity or invariant. Formula use is safest after you state the frame convention, sign convention, and condition: inertial frames, same event pair, same axis of relative motion, proper time, proper length, or invariant interval.

Start every relativity question by naming the inertial frames and the event pair, object, or signal being measured.
Galilean relativity uses absolute time: x′ = x - vt, t′ = t, and u′ = u - v at low speeds.
Special relativity uses the same laws of physics in all inertial frames and invariant vacuum light speed c.
Lorentz transformations use γ and mix space with time; they reduce to Galilean transformations at low speed.
Proper time belongs to same-position events; proper length belongs to the object’s rest frame.
Time dilation gives Δt = γΔt0; length contraction gives L = L0/γ along the direction of motion.
Spacetime interval is invariant, simultaneity is frame-dependent for spatially separated events, and spacetime diagrams show events, world lines, and light lines.
Muon decay evidence can be explained by Earth-frame time dilation or muon-frame length contraction.

Match each A.5 retrieval cue to the physics move it should trigger.

Match
Reasons
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